launching-application

The following .bat file below simply opens two text files overlaying them, but I'm wondering if it's possible to define a specific display source, or if anyone can assist in providing the correct parameters. @echo off START /max /wait NOTEPAD.EXE C:\test\screen1.txt START /max /wait NOTEPAD.EXE C:\test\screen2.txt What I'm trying to get: @echo off START /max /wait NOTEPAD.EXE C:\test\screen1.txt "monitor1" START /max /wait NOTEPAD.EXE C:\test\screen2.txt "monitor2" So the results I am trying to receive is that screen1.txt opens on monitor1, and screen2.txt on monitor2. Unless the application

I wish to know if i can catch the unhandled exceptions thrown by another process which I started using the Process.Start(...) I know i can catch the standered error using this link , but what I want is to catch the error that are usually caught by the Just In Time debugger of the.net environment, the window with the following words: "An unhandled exception has occurred in your application . If you Continue, the application will ignore this error and attempt to continue . If you click Quit, the application will be shut down immediately ...." Which is then followed by the exception message and a

When launching Path Finder app with command line, I use open -a Path Finder.app /Users/ . Based on this idea, I use the following code to launch Path Finder. Can I have launch app without using open command line? NSTask *task; task = [[NSTask alloc] init]; [task setLaunchPath: @"/usr/bin/open"]; NSArray *arguments; arguments = [NSArray arrayWithObjects: @"-a", @"Path Finder.app", @"/Users/", nil]; [task setArguments: arguments]; NSPipe *pipe; pipe = [NSPipe pipe]; [task setStandardOutput: pipe]; NSFileHandle *file; file = [pipe fileHandleForReading]; [task launch]; ughoavgfhw if(![[NSWorkspace

I would like to launch my app when my tablet starts, so that the main activity of my app is the first thing that the user see when they start the tablet. I've read about LauncherActivity but I don't understand how to use it. Can anyone help me with suggestions, links or tutorials for this? Is LauncherActivity the best way or are there alternatives? vishesh chandra These lines of code may be helpful for you... Step 1: Set the permission in AndroidManifest.xml <uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" /> Step 2: Add this intent filter in receiver <receiver android

Using Xcode beta 9 (v4), I'm trying to launch the app by clicking on the "play" button. I get a "build succeeded" but right before launching, a popup message appears in Xcode: "iPhone has denied the launch request." It used to work yesterday. It does work on the simulator. I've rebooted my computer, the iPhone, uninstall the app, cleaned the build. Running out of ideas. It may be code sign issue. Make sure you're signing with developer, not distribution. Brian M It happens using Xcode 9.x or newer. I tracked this problem down to the " debug executable " checkbox in the product scheme (product-

How do I detect when an iOS app is launched for the first time? Pretty much what Marc and Chris said, though I prefer to change the value when the app quits in case there're multiple areas of the application that need to know about it. In code: // -applicationDidFinishLaunching: [[NSUserDefaults standardUserDefaults] registerDefaults:[NSDictionary dictionaryWithObjectsAndKeys:[NSNumber numberWithBool:YES],@"firstLaunch",nil]]; // to check it: [[NSUserDefaults standardUserDefaults] boolForKey:@"firstLaunch"]; // -applicationWillTerminate: [[NSUserDefaults standardUserDefaults] setBool:NO forKey