launch

Launch JVM process from a Java application use Runtime.exec?

好久不见. 提交于 2019-11-26 22:39:37
I want to be able to launch a Java server process from an existing java application and monitor the stdoutput and stderror and redirect that output to a file. Is the best approach to use 'Runtime.exec' and treat the app like any other OS process or is there something more suited for new JVMs. This is on Java 1.5 Fabian Steeg Instead of Runtime , you should probably use ProcessBuilder , though I don't know if something else is even more appropriate in your case (running a Java process in particular). I know I am late in this thread, but in case someone needs it, in my experience, it is easier

Android: Launch activity from clickable text

女生的网名这么多〃 提交于 2019-11-26 21:57:09
Is there any way I can launch an activity from a portion of a string. eg I have this in my strings.xml file: <string name="clickable_string">This is a <u>clickable string</u></string> I would like the text between the u tags to be underlined and launch an activity when clicked when inserted in to a TextView Try this, final Context context = ... // whereever your context is CharSequence sequence = Html.fromSource(context.getString(R.string.clickable_string)); SpannableStringBuilder strBuilder = new SpannableStringBuilder(sequence); UnderlineSpan[] underlines = strBuilder.getSpans(UnderlineSpan

Launch JVM process from a Java application use Runtime.exec?

跟風遠走 提交于 2019-11-26 17:27:03
问题 I want to be able to launch a Java server process from an existing java application and monitor the stdoutput and stderror and redirect that output to a file. Is the best approach to use 'Runtime.exec' and treat the app like any other OS process or is there something more suited for new JVMs. This is on Java 1.5 回答1: Instead of Runtime , you should probably use ProcessBuilder, though I don't know if something else is even more appropriate in your case (running a Java process in particular).

How to launch app on click of url in android

Deadly 提交于 2019-11-26 16:46:42
问题 Launch app when click on url if app installed on device. if app not installed on device, open playstore. <intent-filter> <data android:scheme="app" /> <action android:name="android.intent.action.VIEW" /> <category android:name="android.intent.category.DEFAULT" /> <category android:name="android.intent.category.BROWSABLE" /> </intent-filter> </activity> 回答1: You have to deep link your app, add following lines in activity (Manifiest.xml) which you want to launch <intent-filter > <action android

iOS app first launch

喜欢而已 提交于 2019-11-26 15:53:43
问题 I would like to display a welcome screen when a user opens my app for the first time. What method is there to check the first launch of an app in Swift? 回答1: Swift 4 and higher func isAppAlreadyLaunchedOnce()->Bool{ let defaults = UserDefaults.standard if let _ = defaults.string(forKey: "isAppAlreadyLaunchedOnce"){ print("App already launched") return true }else{ defaults.set(true, forKey: "isAppAlreadyLaunchedOnce") print("App launched first time") return false } } Note: This method would

How can I launch Safari from an iPhone app?

假装没事ソ 提交于 2019-11-26 15:51:15
This might be a rather obvious question, but can you launch the Safari browser from an iPhone app? surtyaar should be the following : NSURL *url = [NSURL URLWithString:@"http://www.stackoverflow.com"]; if (![[UIApplication sharedApplication] openURL:url]) { NSLog(@"%@%@",@"Failed to open url:",[url description]); } Brad The App Guy UIApplication has a method called openURL: example: NSURL *url = [NSURL URLWithString:@"http://www.stackoverflow.com"]; if (![[UIApplication sharedApplication] openURL:url]) { NSLog(@"%@%@",@"Failed to open url:",[url description]); } Dhaval Parmar you can open the

Application not automatically launching in device and getting error on xcode

≡放荡痞女 提交于 2019-11-26 14:47:17
问题 I'm getting a weird bug on Xcode 4.5. When i tried to run my application on Ipad 2 from xcode with iOS 6, I'm getting this error. I done the following methods to run the application, but no luck. Cleaned the project and run Restarted the device Restarted xcode I have a valid certificate in my machine and the application is installing on the device but it's not launching automatically. What could be the issue ? Thanks in advance 回答1: That is really annoying. This error happens in a number of

How to check JRE version prior to launch?

梦想与她 提交于 2019-11-26 14:00:18
问题 What's the best way to determine if the version of the JRE installed on a machine is high enough for the application which the user wants to run? Is there a way of doing it using java-only stuff? I'd like the solution to work on Windows/Linux/MacOSX - if the JRE version is too low a message should be displayed. Currently I'm getting an exception if i try to run it on Java 1.5 (the app is built for Java 1.6). If there's no universal solution, what's the best way to do it on Windows? 回答1: An

Android - detecting application launch from home or history

旧街凉风 提交于 2019-11-26 09:56:44
问题 What is the best way to detect when an Android \"Application\" has been launched from the Home screen/History screen? Basically, what I\'m trying to achieve is force the user to login to certain screens each time they come back to the app (i.e. they have full access to all activities once logged in, but essentially I want them to re-authenticate when they come back to the app via launching on the home screen). I know similar questions have been asked before (i.e. how to log launches of an app

How to open the command prompt and insert commands using Java?

感情迁移 提交于 2019-11-26 08:05:22
Is it possible to open the command prompt (and I guess any other terminal for other systems), and execute commands in the newly opened window? Currently what I have is this: Runtime rt = Runtime.getRuntime(); rt.exec(new String[]{"cmd.exe","/c","start"}); I've tried adding the next command after the "start", I've tried running another rt.exec containing my command, but I can't find a way to make it work. If it matters, I'm trying to run a command similar to this: java -flag -flag -cp terminal-based-program.jar EDIT Unfortunately I have had some strange findings. I've been able to successfully