latitude-longitude

问题 I have a gps module that gives me latitude in longitude in a weird format. DDDMM.MMMM As written on user manual, Degrees*100 + Minutes. As far as I know, It is degrees minutes seconds, and seconds is between 0-59, above than this will increment the minute. But this is giving minutes in decimal places. Does this means 1/1000th of a minute? eg. 07717.3644 E 077 --> degrees 17 --> minutes 3644 --> ? E --> Direction Also how will I convert it to decimal, I am using the formula decimal = degrees +

问题 I have a legacy innodb table Listing containing a business with latitude/longitude. Given an input latitude/longitude (below 51.2167/4.41667), the query is to return the first active, enabled, not-deleted 30 businesses in order of proximity (kilometers). A join with the accounts table is made to check the validity of the listing. select listing.* from listing listing , account account where listing.account_id = account.id and listing.active = 1 and listing.approved = 1 and listing.deleted = 0

问题 I am using the following code to get the current location,I have added the corelocation framework - (void)viewDidLoad { [super viewDidLoad]; locationManager = [[CLLocationManager alloc] init]; locationManager.delegate = self; locationManager.distanceFilter = kCLDistanceFilterNone; // whenever we move locationManager.desiredAccuracy = kCLLocationAccuracyHundredMeters; // 100 m [locationManager startUpdatingLocation]; } - (void)locationManager:(CLLocationManager *)manager didUpdateToLocation:

问题 When storing latitudes/longitudes which are typically of the format: 44.087585 (i.e. max 2 numbers before the dot and 6dp) do I need to bother with bigdecimals? 回答1: Using double has enough precision for accurate lat/lon down to inches for 6-7 decimal places. In aviation, if decimal degrees are used, they typically go to at least 7 decimal places. In our NASA simulations, lat/lon data are doubles while all other attitude and altitude are floats. In other words, the 6th decimal place for

问题 I'm trying to do a nearest neighbor search that yields a single point as the single "nearest neighbor" to another point in matlab. I've got the following data: A longitude grid that is size 336x264 "lon" some random point within the bounds of the longitude grid "dxf" I've tried using MATLAB's "knnsearch" function https://www.mathworks.com/help/stats/knnsearch.html But sadly when I use the command: idx = knnsearch(lon, dxf) I am met with the error: "Y must be a matrix with 264 columns." Is

问题 I want to now how to convert longitude, latitude to its equivalent xy coordinate components in iPhone programming. (I am using only CoreLocation programming, and want to show a point on iPhone screen without any map). thanks 回答1: Well the exact conversion depends on exactly which part of the Earth you want to show, and the stretching along longitude varies according to latitude, at least in Mercator. That being said, even if you don't want to display an actual MapKit map, it would probably be

问题 Does anyone know the best way to go about getting the mid-point of a pair of latitude and longitude points? I mm using d3.js to draw points on a map and need to draw a curved line between two points, so I need to create a mid point to draw a curve in the lines. Please see image below for a better understanding of what I am trying to do: 回答1: Apologies for the long script - it just seemed fun to draw stuff :-). I've marked off sections that are not required // your latitude / longitude var co2

问题 After a while, Google Maps seems to change the property name (Qa or Pa) to Na or another name. var map; function initialize() { var myLatlng = new google.maps.LatLng(-25.363882,131.044922); var myOptions = { zoom: 4, center: myLatlng, mapTypeId: google.maps.MapTypeId.ROADMAP } map = new google.maps.Map(document.getElementById("map_canvas"), myOptions); google.maps.event.addListener(map, 'click', function(event) { AlertPos(event.latLng); }); } function AlertPos (location) { // try to show the

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 4 years ago . I’ve got a database full of UK Postcodes, now I’d like to be able to store the latitude and longitude of these specific postcodes along with the record with the database. Is there any way that I can obtain this data free without violating any T&C's? I know I could do this using Google maps API for each postcode,

问题 I am receiving data from a gps unit via a udp packet. Lat/Lng values are in hex. Example Data 13BF71A8 = Latitude (33.1313576) BA18A506 = Longitude (-117.2790010) The documentation explains that longitude/latitude readings are measured in degrees with a 1x10^-7 degree lsb, signed 2’s complement. For the Latitude I can convert using this formula: 13BF71A8 = 331313576 * 0.0000001 = 33.1313576 This code works for Lat but not for Lng: function convertLat(h){ var latdec = parseInt(h,16); var lat =