last

traverse pointer from last node to first

匿名 (未验证) 提交于 2019-12-03 01:46:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: bn_ptr drive_temp(bn_ptr head,bn_ptr temp,bn_ptr current) { while(temp->next!=current) { temp=temp->next; current=temp; } temp=head; return current; } I have linked list and 'head' pointer hold first node , 'current' pointer hold last node,I want to bring 'current' to head one by one ,so I write this function but it gives segmentation fault when I debug the program 回答1: temp->next!=current will never be true unless temp==temp->next . Try this: bn_ptr drive_temp(bn_ptr head,bn_ptr temp,bn_ptr current) { while(temp->next!=current) { temp=temp-

Pandas - TypeError: Cannot compare type 'Timestamp' with type 'date'

匿名 (未验证) 提交于 2019-12-03 01:46:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: The function below compares dates to filter a dataframe, but on line 8 it throws this error: TypeError: Cannot compare type 'Timestamp' with type 'date' It used to throw that same error on lines 5-7 , but when I addded the .date() that fixed it, but the .date() does not fix it were I have it commented. Any clue why? if day_of_week == 0: last_monday -= pd.to_timedelta(7, unit='d') last_sunday = last_monday + pd.to_timedelta(6, unit='d') last_sat = last_sunday - pd.to_timedelta(1, unit='d') finaldf['Completed_Date'] = pd.to_datetime(finaldf[

Postgresql get first and last day of all iso week in a given year

匿名 (未验证) 提交于 2019-12-03 01:45:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: select week_num , week_start , week_end , to_char ( week_start , 'dd Dy Mon yyyy' ), to_char ( week_end , 'dd Dy Mon yyyy' ) from ( WITH RECURSIVE t ( n ) AS ( select ( date_trunc ( 'week' ,( date_trunc ( 'week' ,( 2016 || '-01-04' ):: date ):: date - interval '1 day' ):: date )):: date UNION ALL SELECT ( n - interval '1 week' ):: date FROM t WHERE extract ( WEEK from n ) > 1 ) SELECT n as week_start , ( n + interval '6 days' ):: date as week_end , extract ( WEEK from n ) as week_num FROM t ) as weeks order by week_num i wrote this

Parent last for Hibernate Arquillian test on JBOSS

匿名 (未验证) 提交于 2019-12-03 01:41:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I'm having an Arquillian test. The subject is an EJB that uses Hibernate 3, which I add to the shrinkwrapped archives along with all other Maven dependencies. It deploys the EJB as a JAR wrapped in an EAR, to an embedded JBOSS 7 which has Hibernate 4 on board. It clashes with the following exception: java . lang . AbstractMethodError : org / hibernate / usertype / UserType . nullSafeSet ( Ljava / sql / PreparedStatement ; Ljava / lang / Object ; ILorg / hibernate / engine / spi / SessionImplementor ;) V I strongly believe that my

Rails 3 - retrieving last accessed action/controller from current controller

匿名 (未验证) 提交于 2019-12-03 01:40:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I need to be able to set my nav on the current page depending on which page the user was perviously on. e.g pageX => pageA(tab1selected) pageY => pageA(tab2selected) I know from reading you can use request.env["HTTP_REFERER"] but I read this doesnt always get return if the user has a firewall etc I am using devise in my app if that helps. Is there another method ? Thanks Alex 回答1: Though not a quick solution, it works: At the end each controller with view , call a method to set your store your current action in the session. If you

Want the last day of each month for a data frame in pandas

匿名 (未验证) 提交于 2019-12-03 01:36:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I have a data frame in pandas where the index are business days. I want to create a new data frame using only the last day of each month, along with the corresponding data in the various columns. I have tried a few different ways with little success and the error message I keep getting is: AttributeError: 'DataFrame' object has no attribute 'date'. The index in my data frame is labeled 'Date'. Other than verifying that, I don't know where to go. Also, the dates in this column include hours, minutes, and seconds...not sure if that

Set initial vuetify v-select value

匿名 (未验证) 提交于 2019-12-03 01:36:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Can someone help me set the default value for a v-select ? The caveat is that my v-select is populated with objects, which I think might be the reason why assigning my item-value to my desired initial value isn't working: <v-select item-text="name" v-model="defaultSelected" :items="people" > Vue.use(Vuetify); const vm = new Vue({ el: "#app", data: { defaultSelected: { name: "John", last: "Doe" }, people: [ { name: "Harry", last: "Potter" }, { name: "George", last: "Bush" } ] } }); Expected: The initial v-select should be John Actual: The

Making pyplot.hist() first and last bins include outliers

匿名 (未验证) 提交于 2019-12-03 01:33:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: pyplot.hist() documentation specifies that when setting a range for a histogram "lower and upper outliers are ignored" . Is it possible to make the first and last bins of a histogram include all outliers without changing the width of the bin ? For example, let's say I want to look at the range 0-3 with 3 bins: 0-1, 1-2, 2-3 (let's ignore cases of exact equality for simplicity). I would like the first bin to include all values from minus infinity to 1, and the last bin to include all values from 2 to infinity. However, if I explicitly set

洛谷 3111 [USACO14DEC]牛慢跑Cow Jog_Sliver 题解

℡╲_俬逩灬. 提交于 2019-12-03 01:32:33
本蒟蒻又来发题解了, 一道较水的模拟题。 题意不过多解释, 思路如下: 在最开始的时候求出每头牛在t秒的位置(最终位置 然后,如果后一头牛追上了前一头牛,那就无视它, 把它们看成一个整体。 else 就++ ans; 上代码: ```cpp #include<bits/stdc++.h> using namespace std; //要开long long long long n, t, ans = 1, last[100010]; struct node { long long s, p; }a[100010]; int main() { scanf("%lld%lld", &n, &t);//输入 for(int i = 1; i <= n; ++ i) { scanf("%lld%lld", &a[i].p, &a[i].s);//输入 last[i] = a[i].p + a[i].s * t;//记录下它的最终位置。 } for(int i = n - 1; i >= 1; -- i) { if(last[i] >= last[i + 1])//如果,追上来,就看成一样的 last[i] = last[i + 1]; else ++ ans;//++ ans } printf("%lld", ans);//输出 return 0; } ``` 来源: https:/

recursively traverse multidimensional dictionary, dimension unknown

匿名 (未验证) 提交于 2019-12-03 01:31:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I want to create a function to recursively traverse a multidimensional dictionary, where the dimensions are unknown. Here is what I have come up with so far, but it doesn't seem to be working correctly. This will print out some key / values twice and they are not in order. def walk_dict(d): for k,v in d.items(): if isinstance(v, dict): walk_dict(v) else: print "%s %s" % (k, v) Here's a sample array: d = { 'plan_code': 'b', 'quantity': '1', 'account': { 'account_code': 'b', 'username': 'jdoe', 'email': 'jdoe@domain.com', 'first_name': 'b',