laravel

Laravel snappy - How to Load internal/external css

浪子不回头ぞ 提交于 2021-01-27 13:41:43
问题 I am trying to get the css styling working for my pdf documents. So far no such luck. Is it possible to use CDN style sheet documents? When I add say bootstrap stylesheet cdn to my view's head section, I get the error below; The exit status code '1' says something went wrong: stderr: "Loading pages (1/6) [> ] 0% [======> ] 10% [======> ] 11% Error: Failed to load https://stackpath.bootstrapcdn.com/bootstrap/4.3.1/css/bootstrap.min.css, with network status code 3 and http status code 0 - Host

public_path() returning results with backslash instead of forward slash

折月煮酒 提交于 2021-01-27 13:12:21
问题 I am writing, <?php echo public_path();?> It returns results with backlashes instead of forward slashes. I expected forward slashes. 回答1: public_path() uses DIRECTORY_SEPARATOR which depends on your OS. To change it to backslashes, you can use str_replace(): str_replace('\\', '/', public_path()) Update For loading assets, use the assets() helper. 来源: https://stackoverflow.com/questions/48289384/public-path-returning-results-with-backslash-instead-of-forward-slash

Laravel redirect back after login

女生的网名这么多〃 提交于 2021-01-27 12:44:42
问题 How can I redirect back page after login? in Laravel 5.2 AuthController protected $redirectTo = '/'; RedirectUsers <?php namespace Illuminate\Foundation\Auth; trait RedirectsUsers { /** * Get the post register / login redirect path. * * @return string */ public function redirectPath() { if (property_exists($this, 'redirectPath')) { return $this->redirectPath; } return property_exists($this, 'redirectTo') ? $this->redirectTo : '/'; } } 回答1: You can do it by using either of these two options.

Laravel redirect back after login

老子叫甜甜 提交于 2021-01-27 12:32:08
问题 How can I redirect back page after login? in Laravel 5.2 AuthController protected $redirectTo = '/'; RedirectUsers <?php namespace Illuminate\Foundation\Auth; trait RedirectsUsers { /** * Get the post register / login redirect path. * * @return string */ public function redirectPath() { if (property_exists($this, 'redirectPath')) { return $this->redirectPath; } return property_exists($this, 'redirectTo') ? $this->redirectTo : '/'; } } 回答1: You can do it by using either of these two options.

How do I change the namespace of my application in Laravel?

我与影子孤独终老i 提交于 2021-01-27 12:21:26
问题 I can't change the namespace of my application in Laravel 5.8. I'm using artisan to change it: php artisan app:name TestApp Result is: There are no commands defined in the " app " namespace. 回答1: laravel change this command to app:namespace you have to do this php artisan app:namespace TestApp 回答2: Are you trying to change the namespace of your application or just the name ? What do you want to change exactly in the namespace ? EDIT I think you must have touched something in your application

Filter table with a column in Laravel Backpack

懵懂的女人 提交于 2021-01-27 12:20:45
问题 I have a Employee table which display like this: +-------------------------------+ | id | name | code | --------------------------------- | 1 | Employee 1 | A1 | | 2 | Employee 2 | A2 | | ... | ... | ... | +-------------------------------+ And I want to create a filter by code column in this table. My query will be like this: SELECT name FROM employee WHERE code LIKE .% $filter %. I searched in backpack document and trying to do like this $this->crud->addFilter( [ 'type' => 'select2', 'name'

Laravel 5 Dynamically create Eloquent Models

烂漫一生 提交于 2021-01-27 11:50:55
问题 Suppose I have an of mysql table names and a row id: ['table_name' => 'things', 'row_id' => 11], ['table_name' => 'stuff', 'row_id' => 5] Each of these tables has an Eloquent model referencing the table. How can I iterate the list and dynamically use the Model to create a new instance from the table_name key and find the row based on the row_id key? I can get the data I need through a Builder instance but I really need to construct a Model instance. This is because I am implementing a

Laravel 5 Dynamically create Eloquent Models

那年仲夏 提交于 2021-01-27 11:42:02
问题 Suppose I have an of mysql table names and a row id: ['table_name' => 'things', 'row_id' => 11], ['table_name' => 'stuff', 'row_id' => 5] Each of these tables has an Eloquent model referencing the table. How can I iterate the list and dynamically use the Model to create a new instance from the table_name key and find the row based on the row_id key? I can get the data I need through a Builder instance but I really need to construct a Model instance. This is because I am implementing a

Laravel - Call to undefined method Illuminate\Foundation\Application::share()

空扰寡人 提交于 2021-01-27 10:18:19
问题 I am upgrading from Laravel 5.3 to Laravel 5.4. Problem is that when I run composer update and when it comes to php artisan optimize part, I get an error: [Symfony\Component\Debug\Exception\FatalErrorException] Call to undefined method Illuminate\Foundation\Application::share() I've read a couple of questions here on StackOverflow and the answer is to replace this share method with singleton. But where can I find this share() ? EDIT My composer.json file: "name": "laravel/laravel",

Laravel 5 js is blocking by app.js

≯℡__Kan透↙ 提交于 2021-01-27 08:11:29
问题 I am using a javascript inside home.blade.php it extends layout/app.blade.php @extend(layout.app) when I extend javascript inside home.blade.php stop working, So I commented out <script src="{{ asset('js/app.js') }}" defer></script> in app.blade.php then javascript starts working. I am not sure what is the issue can anyone help me to fix this. home.blade.php @extends('layouts.app') @section('content') <div class="container"> <div class="row justify-content-center"> <div class="col-md-8"> <div