laravel

问题 this is my first question here, I'm really desperate and I hope you can help me. I'm trying to build a post/comment/reply system like Facebook by using vuejs, I'm using v-for to loop all posts/comments/replies after I use Axios to fetch data in my database (using laravel API), the problem here that I have input with v-model attached to a form inside my v-for loops when I type in my of my input it appears in all other inputs that has been looped here is an image for better understanding ->

问题 this is my first question here, I'm really desperate and I hope you can help me. I'm trying to build a post/comment/reply system like Facebook by using vuejs, I'm using v-for to loop all posts/comments/replies after I use Axios to fetch data in my database (using laravel API), the problem here that I have input with v-model attached to a form inside my v-for loops when I type in my of my input it appears in all other inputs that has been looped here is an image for better understanding ->

问题 Does laravel provide a way to prevent multiple logins of a user from different devices / browsers at a given time? If yes then how can i force a user to logged in from a single device at a single time. I am developing a online quiz app using laravel 5.6 where users can logged in from a single place and take test. 回答1: laravel provide this method to invalidating and "logging out" a user's sessions that are active on other devices logoutOtherDevices() to work with this method you need also to

问题 Does laravel provide a way to prevent multiple logins of a user from different devices / browsers at a given time? If yes then how can i force a user to logged in from a single device at a single time. I am developing a online quiz app using laravel 5.6 where users can logged in from a single place and take test. 回答1: laravel provide this method to invalidating and "logging out" a user's sessions that are active on other devices logoutOtherDevices() to work with this method you need also to

问题 The product data always return null when i get the incoming_goods data (belongsTo). Here is my Product Model: <?php namespace App; use Illuminate\Database\Eloquent\Model; use Illuminate\Database\Eloquent\SoftDeletes; class Product extends Model { use SoftDeletes; protected $guarded = [ 'id', 'created_at', 'updated_at', 'deleted_at', ]; public function transaction_details() { return $this->hasMany('App\Transaction_detail'); } public function incoming_goods() { return $this->hasMany('App

问题 I need two submit button for my update form, current setting Currently when I hit submit it saves my data and redirect me another page where i can edit my multiple images (so my form is like two step function) What I want to add I want to add another button in order to just save my data and return me to index page (skip second step) last result Last result will be my edit form with two button button 1 saves data and return me to next form to edit my images button 2 saves data and return me to

问题 I have two tables(models), one with a json column that may contain the id on other table. I want to join these two together, how do i chain a laravel join to my query. 回答1: Apply the JSON logic inside the join query like: Post::select('posts.id', 'posts.field1','posts.field2','samples.id as sample_id', ..) ->join('samples', 'posts.json_col_name.id', '=', 'samples.id') ->get(); Make sure that you make no conflict for the query builder while picking columns (use field_name as another_name )

问题 I have two tables(models), one with a json column that may contain the id on other table. I want to join these two together, how do i chain a laravel join to my query. 回答1: Apply the JSON logic inside the join query like: Post::select('posts.id', 'posts.field1','posts.field2','samples.id as sample_id', ..) ->join('samples', 'posts.json_col_name.id', '=', 'samples.id') ->get(); Make sure that you make no conflict for the query builder while picking columns (use field_name as another_name )

问题 I have two tables(models), one with a json column that may contain the id on other table. I want to join these two together, how do i chain a laravel join to my query. 回答1: Apply the JSON logic inside the join query like: Post::select('posts.id', 'posts.field1','posts.field2','samples.id as sample_id', ..) ->join('samples', 'posts.json_col_name.id', '=', 'samples.id') ->get(); Make sure that you make no conflict for the query builder while picking columns (use field_name as another_name )

问题 After validation fails. The values are flashed to the fields. Now, I am trying to use old input to display all the dynamic fields where the user-added data. Therefore, I am using an array called "name" and loop through them to determine how many names are stored in the array. This determines the number of fields I need to display. But my field is a select field. This already checks within an array which field is select. So, for example, the user selects "Jan" from the field called "name".