laravel-5.2

问题 I am making a POST request, but unable to get anything besides a 422 response. Vue.js client code: new Vue({ el: '#app', data: { form: { companyName: '', street: '', city: '', state: '', zip: '', contactName: '', phone: '', email: '', numberOfOffices: 0, numberOfEmployees: 0, } }, methods: { register: function() { this.$http.post('/office-depot-register', this.form).then(function (response) { // success callback console.log(response); }, function (response) { // error callback console.log

问题 I'd like to know is it possible to extend the built-in authentication to use an external API to authenticate a user? I'm a Laravel newbie, so I'd appreciate your help. I'm making a custom app in Laravel 5.2 for my client, but I don't a direct access to their database server and I can only call their API to get users' details. Thanks. 回答1: If I understood correctly you want to log users from APIs like facebook, twitter or github for example ? If that's so you need to use a laravel package

问题 Even ios can get notification from fcm console. Controller function : public function push(Request $request) { $validator = Validator::make($request->all(), [ 'title' = > 'required', 'body' = > 'required', 'token' = > 'required', 'type' = > 'required', 'id' = > 'required', ]); if ($validator->fails()) { $this->throwValidationException( $request, $validator ); } $title = $request['title']; $body = $request['body']; $type = $request['type']; $id = $request['id']; $dataarray = array( "id" = >$id

问题 Hello all I am a new laravel, I have problem with my project. I have 2 table: posts: id title category_id category: id name(PHP, Laravel, Ruby) Ex:I want result like, if I am insert a post into posts database title=Jonh and chosse two category name(PHP,Laravel), and the result will two column like posts(id=1 title(jonh) category_id(1), id=2 title(jonh) category_id(2)) but it still not work I try to find in google and youtube follow and it not work, and here is my code: View(create.blade.php)

问题 I have the following test function, that I want to call directly from my URL or by clicking a link from my blade view. public function callMeDirectlyFromUrl() { return "I have been called from URL :)"; } My Question: Is it possible to call a function directly from button-click or URL link from blade view in Laravel? 回答1: Here is the solution: We assume you have a function callMeDirectlyFromUrl in YourController , here how you can call the function directly from URL, Hyperlink or Button.

问题 I know this question has already been asked. But none of them solve my issue. I am facing the issue : DecryptException in BaseEncrypter.php line 48: The MAC is invalid. I checked my .env file there is no space in APP_DEBUG and APP_KEY Tried to generate new key but nothing worked out. Laravel Framework version 5.2.45 回答1: After surfing for around two hours , tried so many solution form different sources but none of them solved my problem. There may be reason then .env file have space in APP

问题 I am using Laravel 5.2. I have almost done the resizing of an image that runs fine. But i am facing one problem When i upload an image of 300 dpi it reduces the dpi to 96 dpi. I don't know what i am doing wrong.I am using Intervention Package of laravel5.2. Here i have done so far:- // Input::file('image') -> upload file having dpi of 300 $height = 6048; //upload image height $width = 4032; //upload image width xxlheight = ($height*60)/100; $xxlwidth = ($width*60)/100; $xxlFileName = str

问题 Using the post/redirect/get pattern, you can prevent duplicate form submission. For example, you can prevent a visitor of your online shopping website from ordering the same item twice. However, is it possible to block such a duplicate action but receive and maintain input values, which are send with POST, on DOM after the visitor refreshes the page without using AJAX call? To clarify the point, here is an example. You have only one page, which has a <form> , several <input> and submit button

问题 The reason why I'm doing that is Laravel has the document root in a subdirectory is so that you don't have to expose your code to the public. The folder structure in my localhost is Test Test/laravel/ Test/public_html/ where laravel contains all the folder of root without the public folder and public_html contains the public files. And I have changed in below lines in public_html/index.php : require __DIR__.'./../laravel/bootstrap/autoload.php'; $app = require_once __DIR__.'./../laravel

问题 My controller: $class = new joinclass(); $class -> user_id = Auth::user()->id; $class -> class_code = $request['class_code']; $class -> save(); Class_code is another table column name. It's not primary key or foreign key. 回答1: Your field "class_code" contain "nothing" (null) and Your MySQL server is running in "strict" mode. As of MySQL 5.7.5, the default SQL mode includes STRICT_TRANS_TABLES , which is exactly the cause of your headache. To change your server's mode, edit your my.cnf (or my