jsonobject

How can I access each key and value in JSONArray

风流意气都作罢 提交于 2019-11-28 09:26:36
问题 I have a JSONArray as below. How can I access each key and value in it in order. JSONArray = [{"a":1},{"b":2,"c":3},{"d":4},{"e":5,"f":7}] 回答1: You can try following code: JSONArray jsonArray = new JSONArray("[{\"a\":1},{\"b\":2,\"c\":3},{\"d\":4},{\"e\":5,\"f\":7}]"); for (int i = 0; i < jsonArray.length(); i++) { JSONObject json = jsonArray.getJSONObject(i); Iterator<String> keys = json.keys(); while (keys.hasNext()) { String key = keys.next(); System.out.println("Key :" + key + " Value :"

【Java】各个JSON技术的比较

♀尐吖头ヾ 提交于 2019-11-28 09:17:15
一 、各个JSON技术的简介和优劣 1. json-lib json-lib最开始的也是应用最广泛的json解析工具,json-lib 不好的地方确实是依赖于很多第三方包,包括commons-beanutils.jar,commons-collections-3.2.jar,commons-lang-2.6.jar,commons-logging-1.1.1.jar,ezmorph-1.0.6.jar,对于复杂类型的转换,json-lib对于json转换成bean还有缺陷,比如一个类里面会出现另一个类的list或者map集合,json-lib从json到bean的转换就会出现问题。 json-lib在功能和性能上面都不能满足现在互联网化的需求。 2. 开源的Jackson 相比json-lib框架,Jackson所依赖的jar包较少,简单易用并且性能也要相对高些。 而且Jackson社区相对比较活跃,更新速度也比较快。 Jackson对于复杂类型的json转换bean会出现问题,一些集合Map,List的转换出现问题。 Jackson对于复杂类型的bean转换Json,转换的json格式不是标准的Json格式 3. Google的Gson Gson是目前功能最全的Json解析神器,Gson当初是为因应Google公司内部需求而由Google自行研发而来,

How to Get JSON Array Within JSON Object?

寵の児 提交于 2019-11-28 08:35:36
This is my JSON { "data": [ { "id": 1, "Name": "Choc Cake", "Image": "1.jpg", "Category": "Meal", "Method": "", "Ingredients": [ { "name": "1 Cup Ice" }, { "name": "1 Bag Beans" } ] }, { "id": 2, "Name": "Ice Cake", "Image": "dfdsfdsfsdfdfdsf.jpg", "Category": "Meal", "Method": "", "Ingredients": [ { "name": "1 Cup Ice" } ] } ] } And this is how i am getting the id, name this part works fine in getting the first part of JSON //getting whole json string JSONObject jsonObj = new JSONObject(jsonStr); //extracting data array from json string JSONArray ja_data = jsonObj.getJSONArray("data"); int

Volley Post method for json object

前提是你 提交于 2019-11-28 07:04:58
data={ "request": { "type": "event_and_offer", "devicetype": "A" }, "requestinfo": { "value": "offer" } } how to post this request from volley plz help JsonObjectRequest jsonObjReq = new JsonObjectRequest( Request.Method.POST,url, null , new Response.Listener<JSONObject>() { @Override public void onResponse(JSONObject response) { Log.d(TAG, response.toString()); msgResponse.setText(response.toString()); hideProgressDialog(); } }, new Response.ErrorListener() { @Override public void onErrorResponse(VolleyError error) { VolleyLog.d(TAG, "Error: " + error.getMessage()); hideProgressDialog(); } })

fastjson

旧街凉风 提交于 2019-11-28 06:22:09
/** * 常用json和javabean相互转换 * json字符串转化为JSONObject */ JSONObject parseObject = JSONObject.parseObject(reqStr); /** * Json字符串转换成对应javaBean */ CalculateRequest calculateRequest = JSON.parse(parseObject.toJSONString(), CalculateRequest.class); /** * JavaBean 转换为json字符串 */ String jsonString = JSONObject.toJSONString(calculateRequest); 来源: https://www.cnblogs.com/CoderRdf/p/11397098.html

Creating nested JSON object for the following structure in Java using JSONObject? [closed]

廉价感情. 提交于 2019-11-28 04:23:42
I want to build a JSON Object similar to following the structure in java using JSONObject and JSONArray. I have gone through various posts in stack overflow, which suggests using methods like push, put etc which I am unable to identify for JSONArray. Please help. { "name": "sample", "def": [ { "setId": 1, "setDef": [ { "name": "ABC", "type": "STRING" }, { "name": "XYZ", "type": "STRING" } ] }, { "setId": 2, "setDef": [ { "name": "abc", "type": "STRING" }, { "name": "xyz", "type": "STRING" } ] } ] } goten With the imports org.json.JSONArray and org.json.JSONObject JSONObject object = new

微服务下的登录实现及相关问题解决

拟墨画扇 提交于 2019-11-28 02:29:04
  最近由于工作需要,需要开发一个登录的微服务;由于前期在网上找session共享的实现方案遇到各种问题,所以现在回过头来记录下整个功能的实现和其中遇到的问题;总结一下主要有以下几点:   1、登录实现(整合redis以及用户信息的共享问题)   2、登录拦截器的实现及拦截后成功跳转(这里踩了一个大坑)   3、登录过期时间随用户的操作而跟新(即当用户操作时间大于设置的登录时间时不要让用户推出登录)   4、Springboot的自定义异常捕获(初衷是为了解决2的跳转问题,最后兜了一大圈)   下面对上面提到的几点进行详细记录; 一、登录实现(整合redis以及用户信息的共享问题)   这是整个功能的核心所在,由于我们有多个服务所以首要解决的就是session共享的问题,解决这个问题主要是通过redis来实现的,我把登录成功后对session的操作全部换为对redis的操作,以userId为key,然后将userId返回给前台,在前台需要写一个common.js来重写ajax请求,使得每次访问后台的请求都自动带上userId,这样再写一个拦截器登录整个登录功能差不多就实现了; 二、登录拦截器的实现及拦截后成功跳转   首先需要写一个拦截器的配置类,主要就是将我们自定义的拦截器注册到项目中以及白名单的添加;下面是注册拦截器的代码: @Configurationpublic class

spring boot java多线程实战

ぃ、小莉子 提交于 2019-11-28 01:25:44
基于ThreadPoolExecutor线程池实现多线程应用 /** * @Description: 线程池常量 * @date: 2019-10-19 */ public class ThreadPoolConstants { public final static Integer CORE_POOL_SIZE = 20; public final static Integer MAX_POOL_SIZE =40; public final static Integer KEEP_ALIVE_TIME = 120; public final static Integer WORK_QUEUE_SIZE =600; } /** * @Description: * @date: 2019-10-19 */ public interface MyThreadPoolService { Future submitTask(Callable callable); void submitRunalbeTask(Runnable callable); } ** * @Description: 线程池实现 * @date: 2019-10-19 */ @Service public class MyThreadPoolServiceImpl implements

Delete Request With header and Parametes Volley

☆樱花仙子☆ 提交于 2019-11-28 01:21:49
Hi i want to Send Delete Request to server using Volley along Headers and body parameters. but i am not able to send request successfully What i have tried JSONObject jsonbObjj = new JSONObject(); try { jsonbObjj.put("nombre", Integer.parseInt(no_of_addition .getText().toString())); jsonbObjj.put("cru", crue); jsonbObjj.put("annee", 2010); } catch (JSONException e) { // TODO Auto-generated catch block e.printStackTrace(); } VolleyRequest mVolleyRequest = new VolleyRequest( Method.DELETE, url, jsonbObjj, new Listener<JSONObject>() { @Override public void onResponse(JSONObject jsonObject) { //

fastjson对象,JSON,字符串,map之间的互转

假如想象 提交于 2019-11-28 01:19:58
1.对象与字符串之间的互转 将对象转换成为字符串 String str = JSON.toJSONString(infoDo); 字符串转换成为对象 InfoDo infoDo = JSON.parseObject(strInfoDo, InfoDo.class); 2.对象集合与字符串之间的互转 将对象集合转换成为字符串 String users = JSON.toJSONString(users); 将字符串转换成为对象集合 List<User> userList = JSON.parseArray(userStr, User.class); 3.字符串互转JSONObject String 转 Json对象 JSONObject jsonObject = JSONObject.parseObject(jsonString); json对象转string JSONObject jsonObject = JSONObject.parseObject(str);//json对象转字符串 String jsonString = jsonObject.toJSONString(); 4.map与字符串之间互转 //字符串转map JSONObject jsonObject = JSONObject.parseObject(str); Map<String,Object> map =