jsonobject | 易学教程

fastJSON 的jsonobject和bean互转

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//bean转换成JSONObejct JSONObject json = JSONObject.parseObject(JSONObject.toJSON(bean).toString()); //jsonObject 转换成bean OrderNodeRecordsBean orderNodeRecordsBean = JSONObject.toJavaObject(json, Object.class); 来源： CSDN 作者：架构师制造机链接： https://blog.csdn.net/gbh666666/article/details/103473928

一篇文章教你轻松使用fastjson

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前言只有光头才能变强。文本已收录至我的GitHub精选文章，欢迎Star ： https://github.com/ZhongFuCheng3y/3y JSON 相信大家对他也不陌生了，前后端交互中常常就以 JSON 来进行数据交换。而有的时候，我们也会将 JSON 直接保存在数据库中。可能就有人不太理解，为什么要将JSON保存在关系型数据库中？我在最开始的时候也有类似的疑惑，问了几个同事，得出的结论都差不多：方便扩展，如果那些字段不需要用到索引，改动比较频繁，你又不想改动表的结构，那就可以在数据库中存入 JSON 虽说存 JSON 会方便扩展，但如果你的 MySQL 版本还是相对较低的话，想要用SQL查 JSON 里某个属性，还是比较麻烦的。并且从数据库里边取出来也仅仅是一个 String ，而想要操作 JSON 里边的属性，自己写不太方便，所以就有 fastjson 给我们去用。这篇文章简单讲讲 fastjson 的使用，希望对大家有帮助。如果有帮助，给我点个赞呀！一、fastjson入门以下内容来源： https://github.com/alibaba/fastjson/wiki/Quick-Start-CN 它可以解析 JSON 格式的字符串，支持将 Java Bean 序列化为 JSON 字符串，也可以从 JSON 字符串反序列化到

Converting String to Android JSONObject loses utf-8

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问题 I am trying to get a (JSON formatted) String from a URL and consume it as a Json object. I lose UTF-8 encoding when I convert the String to JSONObject. This is The function I use to connect to the url and get the string: private static String getUrlContents(String theUrl) { StringBuilder content = new StringBuilder(); try { URL url = new URL(theUrl); URLConnection urlConnection = url.openConnection(); BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(urlConnection

inserting data into MySQL from android app

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问题 I am going to develop a web application for android but I am trying first time ever this experiment so i am not able to complete my task because I am new in it. Its giving me an error like string cannot convert to JSONObject. please please help me I've tried everything upto me but could not get any solution yet. Here is my code. public class signup extends Activity implements OnClickListener { Button signup,cancel; EditText e1,e2,e3,e4; String name; String email; String mobile; String passwd;

Convert xml file to json object using dom parser in java

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问题 Trying to convert any type of XML file to JSON object structure . Different xml files are having varied depths of elements and sub-elements. creation of arrays when elements with same name are at same height I need a recursive function which create exact JSON Object for any structured XML file 回答1: /* * To change this template, choose Tools | Templates * and open the template in the editor. */ /** * * @author nikunj.m */ import java.io.File; import javax.xml.parsers.DocumentBuilder; import

how to get JSON representation of Java Objects in JAX-RS layer in java EE 7?

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问题 We are currently using Java EE 5 and we do something like the following for turning POJO into JSON before sending the response. @GET @Path("/books") @Produces(MediaType.APPLICATION_JSON) public Response getBooks() { List<Book> listOfBooks = getMiscService().getbooks(); String response = "{\"books\":" + gson.toJson(listOfBooks) + "}"; return Response.status(Response.Status.OK).entity(response).build(); } we are using gson API of google. Now that we are restructuring the code to Java EE 7 API

Parse jsonObject when field names are unknowm

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问题 I'm trying to extract some data from a JsonObject. The problem is that the fields that come inside that json have unpredictable names. How can I extract that information having this weird field names? Here is an example: "myObject":{ "216cfa89a2de57554b36b177f0bfbb05":{ }, "0cf9182b5ceba2cb64174141a13e647d":{ }, "eb1d1b19e117ba1387a798d9194b4660":{ }, "157b52871e8e560c7ec0be111ef02363":{ }, "4db69dd3a8ae8e0089bd2959ab0c5f86":{ }, } I'm using gson, where we have the method getAsJsonObject, but

Jackson Parser can't read backslash quotation marks in String

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问题 I've got JSON like this from the server: { "id":"1", "value":13, "text":"{\"Pid\":\"2\",\"value\":42}" } I am using jackson library to deserialize this JSON string into java object with this code: (example below) ObjectMapper mapper = new ObjectMapper(); MapObj obj = mapper.readValue(JSONfromServerInString, MapObj.class); where Map Object looks like that: public class MapObj { @JsonProperty("id") private Integer id; @JsonProperty("value") private Integer value; @JsonProperty("text") private

19.JAVA-从文件中解析json、并写入Json文件(详解)

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1.json介绍 json与xml相比, 对数据的描述性比XML较差,但是数据体积小,传递速度更快. json数据的书写格式是 "名称:值对" ,比如: "Name" : "John" //name为名称,值对为"john"字符串值对类型共分为: 数字（整数或浮点数）字符串（在双引号中）逻辑值（true 或 false）数组（在方括号[]中）对象（在花括号{}中） null 当然数组也可以包含多对象: { "employees": [ { "Name":"John" , "Age":19 }, { "Name":"Anna" , "Age":22 }, { "Name":"Peter", "Age":23 } ] } 表示 "employees" 对象中有 3个对象数组 (每个对象数组表示一条员工信息), 其中并列的数据都必须用逗号 "," 隔开. 2.json包使用在 www.json.org 上公布了很多JAVA下的json解析工具(还有C/C++等等相关的)，其中org.json和json-lib比较简单，两者使用上差不多,这里我们使用 org.json ,org.json下载地址为: https://search.maven.org/search?q=g:org.json%20AND%20a:json&core=gav 3.json解析 3.1解析步骤首先通过

JSONObject转换为JavaBean时，时间默认转换成当前日期

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在写接口时候遇到的问题记录一下、如果遇到此问题的同学避免入坑。 JSONObject businessInfoMap = ps.getBusinessInfo(); PersonalInfoDTO personinfo = new PersonalInfoDTO(); personinfo = (PersonalInfoDTO) JSONObject.toBean(businessInfoMap, PersonalInfoDTO.class); // 通过json 转换成bean。其中businessInfoMap中有aac006、aae006日期格式为“1993-02-09”。 JSONObject.Bean时转换后内容都直接为当期系统日期了。这是因为JSONObject不能识别“1993-02-09”格式；解决办法：在toBean方法使用前先执行以下方法； JSONUtils.getMorpherRegistry().registerMorpher(new DateMorpher(new String[] {“yyyy-MM-dd”, “yyyy-MM-dd HH:mm:ss”})); 来源： CSDN 作者：大憧憬链接： https://blog.csdn.net/ch_csdn_ch/article/details/103512284