jsonarray

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I am new to Android Development. I purely like to work with JSON Objects and Arrays for my simple application considering the lightness of the JSON Carrier compared to XMLs. I had challenges with ArrayAdapter to populate the ListView. This is how I overcome and need your suggestions on it. Extend the Adaptor class. Then pass the JSONArray to the constructor. Here the constructor calls super with dummy String array setting the length of the JSONArray. Store the constructor arguments in class for further use. public myAdaptor(Context context,

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: When I try in my localhost it work find. this is the JSON that provide by my localhost. Y it error in this url http://api.androidhive.info/contacts/ [{ "id": "1", "first_name": "man", "last_name": "woman", "username": "man", "password": "4f70432e6369 70de9929bcc6f1b72412", "email": "man@gmail.com", "url": "http:\/\/localhost\/adchara1\/" }, { "id": "6", "first_name": "first", "last_name": "Last Name", "username": "user", "password": "1a1dc91c907325c69271ddf0c944bc72", "email": "0", "url": "ht tp:\/\/api.androidhive.info\/contacts\/" }, { "id

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I try to read a JSON file like this: { "presentationName" : "Here some text", "presentationAutor" : "Here some text", "presentationSlides" : [ { "title" : "Here some text.", "paragraphs" : [ { "value" : "Here some text." }, { "value" : "Here some text." } ] }, { "title" : "Here some text.", "paragraphs" : [ { "value" : "Here some text.", "image" : "Here some text." }, { "value" : "Here some text." }, { "value" : "Here some text." } ] } ] } It's for a school exercice, I choose to try to use JSON.simple (from GoogleCode) but I am open to

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have a json stream which can be something like : {"intervention": { "id":"3", "subject":"dddd", "details":"dddd", "beginDate":"2012-03-08T00:00:00+01:00", "endDate":"2012-03-18T00:00:00+01:00", "campus": { "id":"2", "name":"paris" } } } or something like {"intervention": [{ "id":"1", "subject":"android", "details":"test", "beginDate":"2012-03-26T00:00:00+02:00", "endDate":"2012-04-09T00:00:00+02:00", "campus":{ "id":"1", "name":"lille" } }, { "id":"2", "subject":"lozlzozlo", "details":"xxx", "beginDate":"2012-03-14T00:00:00+01:00",

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: How might I obtain the city name in Google Maps if I have latitude and longitude coordinates of a town or area? I tried using the latitude, longitude and I got country but I don't know how to get city name. 回答1: From a Geocoder object, you can call the getFromLocation(double, double, int) method. It will return a list of Address objects that have a method getLocality() . Geocoder gcd = new Geocoder(context, Locale.getDefault()); List<Address> addresses = gcd.getFromLocation(lat, lng, 1); if (addresses.size() > 0) { System.out.println

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have one string String arr= "[1,2]"; ie "[1,2]" is like a single string How do convert this arr to int array in java 回答1: String arr = "[1,2]"; String[] items = arr.replaceAll("\\[", "").replaceAll("\\]", "").replaceAll("\\s", "").split(","); int[] results = new int[items.length]; for (int i = 0; i 回答2: Using Java 8's stream library, we can make this a one-liner (albeit a long line): String str = "[1, 2, 3, 4, 5, 6, 7, 8, 9, 0]"; int[] arr = Arrays.stream(str.substring(1, str.length()-1).split(",")) .map(String::trim).mapToInt(Integer:

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: having JSON from web service, Json Array as a response [ 3 ] 0 : { id : 2 name : "a561137" password : "test" firstName : "abhishek" lastName : "ringsia" organization : "bbb" }- 1 : { id : 3 name : "a561023" password : "hello" firstName : "hello" lastName : "hello" organization : "hello" }- 2 : { id : 4 name : "a541234" password : "hello" firstName : "hello" lastName : "hello" organization : "hello" } After Getting Response in JsonArray Getting error while reading Json Object of Json Array : List list = new ArrayList (); JSONArray

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: The link is http://iipacademy.in/askpoll/ten_feed.php exception is in onPostExecute() method (4th line) : Log.i("result", result); try { if (result != null) { JSONArray jsonArray = new JSONArray(result); // erreor for (int i = 0; i LOGCAT: 12-18 03:20:45.447: W/System.err(2790): org.json.JSONException: Value response of type java.lang.String cannot be converted to JSONArray 12-18 03:20:45.447: W/System.err(2790): at org.json.JSON.typeMismatch(JSON.java:111) 12-18 03:20:45.447: W/System.err(2790): at org.json.JSONArray. (JSONArray.java:91) 12

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: The link is http://iipacademy.in/askpoll/ten_feed.php exception is in onPostExecute() method (4th line) : Log.i("result", result); try { if (result != null) { JSONArray jsonArray = new JSONArray(result); // erreor for (int i = 0; i LOGCAT: 12-18 03:20:45.447: W/System.err(2790): org.json.JSONException: Value response of type java.lang.String cannot be converted to JSONArray 12-18 03:20:45.447: W/System.err(2790): at org.json.JSON.typeMismatch(JSON.java:111) 12-18 03:20:45.447: W/System.err(2790): at org.json.JSONArray. (JSONArray.java:91) 12

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I've a JSONArray and I need to get the hashmap with the values, because I need to populate a stream, like twitter done. What you suggest to do? 回答1: HashMap pairs = new HashMap (); for (int i = 0; i Something like that. 回答2: You can use Iterator for getting JsonArrays . or use this way eg. json { ........ ........ "FARE":[ //JSON Array { "REG_ID":3, "PACKAGE_ID":1, "MODEL_ID":9, "MIN_HOUR":0 ....... ....... ....... } ] } HashMap mMap= new HashMap(); for (int i = 0; i note : For better coding use Iterator 文章来源: JSONArray to HashMap