jquery-deferred

I have a chain of ajax requests that support a series of cascading drop down select lists. When you select a value in the 1st drop down, a request is fired to populate the 2nd, when that is complete (and the drop down filled), the next request fires to populate the 3rd drop down, and so on down the line. There are some variations to the way these request chains are formed, so I was hoping to assemble the requests using the jQuery Deferred objects. I see how I can chain the 2nd request to the first, but I don't see how I can chain the third request to the 2nd. function Step1() { return $.ajax(

I'm using the following code to have multiple ajax requests like this: request 1 start | request 1 finish | request 2 start | request 2 finish | ... This is the code: var startingpoint = fireRequest(1); $.each(types,function(ix,type) { startingpoint = startingpoint.pipe( function() { alert(startingpoint.status); // undefined return fireRequest(type); }); }); fireRequest is just a switchcase to the correct ajax function which returns $.ajax(...) I'd like the chain to stop when one request fails. I started implementing it and as a test I'd like to alert the status of the ajax object, but it

I could declare a jQuery AJAX call this way: var foo = $.ajax({ ... }); But that would actually perform the request right then and there, correct? How can I declare the AJAX call without executing it initially, then call it later? Something like: var foo = $.ajax({ ... }); // some stuff in between foo.execute(); Thanks. EDIT Little more info: What I really want to do is have a function that constructs an AJAX request based on parameters, returns it to the calling code, and have the calling code manage its state (i.e. be able to execute it, abort it, etc.). So rather than simply declare the

I am using jQuery and am aware that this issue is because the jQuery.Deferred implementation is not Promises/A+ compiant. I do not want to use any other libraries to solve this. With that out of the way, is there a way to recover from a $.Deferred().fail() callback such that I am returned back to the success chain? This is possible with the multi-callback form of then() but so far I have not found a solution using .fail() then: asyncThatWillFail().then(function () { // useless callback }, function () { console.log("error"); return $.Deferred().resolve(); }).then(function () { console.log(

How can I cancel a promise without removing the element from the DOM? fiddle I ran this code: $("#box") .delay(2000) .show("slow") .delay(2000) .promise() .then(function(){log("Done");}); After this, is there a way to cancel the promise? Both clearQueue() and stop(true) didn't work, because it's not an animation that I'm trying to cancel. I saw that remove() should do it ... but I only want to stop the promise, not remove the entire element. Good news. Since yesterday you can cancel your promise. I published the new version of my small plugin jquery-timing that provides two methods amongst

I'm using $.when to chain some Deferred objects, and if one of them fail, the always method will be called directly after the failure, even if I still have some deferrer in a "pending" state. var promises = [], defs = []; for(var i=0 ; i < 10 ; i++){ defs.push($.Deferred()); promises.push(defs[i].promise()); } var res = $.when.apply($, promises); res.fail(function(){console.log('failed')}); res.done(function(){console.log('done')}); res.always(function(){console.log('always')}); res.then(function(){console.log('then, done')}, function(){console.log('then, failed')}); var j = 0; var t =