jax-rs

JBoss Fuse CXF-RS REST Issue - 'No services have been found'

笑着哭i 提交于 2020-08-05 14:14:12
问题 I'm creating a REST Service with Apache Camel and CXF-RS, using the following tutorial: https://www.javainuse.com/camel/apache_camel_rest_cxfrs I've set up the code as shown in the tutorial and followed the steps correctly. After building the Maven project, I have successfully been able to install the bundle on Apache Karaf, using the SNAPSHOT file created. (A new Bundle ID was created). When I run the command to 'start' the newly created bundle, it seemingly works with no errors being shown.

JBoss Fuse CXF-RS REST Issue - 'No services have been found'

旧城冷巷雨未停 提交于 2020-08-05 14:08:33
问题 I'm creating a REST Service with Apache Camel and CXF-RS, using the following tutorial: https://www.javainuse.com/camel/apache_camel_rest_cxfrs I've set up the code as shown in the tutorial and followed the steps correctly. After building the Maven project, I have successfully been able to install the bundle on Apache Karaf, using the SNAPSHOT file created. (A new Bundle ID was created). When I run the command to 'start' the newly created bundle, it seemingly works with no errors being shown.

How to convert Java Gradle project to Dynamic Web Project?

独自空忆成欢 提交于 2020-08-02 04:13:48
问题 I am following this article https://www.linkedin.com/pulse/building-jax-rs-project-eclipse-gradle-neeraj-malhotra On how to build a JAX-RS project in Eclipse with Gradle I am using Eclipse Java EE IDE for Web Developers. Version: Oxygen.2 Release (4.7.2) Build id: 20171218-0600 My target runtime is WildFly Full 11.0.0.Final (WildFly Core 3.0.8.Final) my gradle build file apply plugin: 'war' apply plugin: 'eclipse-wtp' sourceCompatibility = 1.8 repositories { mavenCentral() } dependencies {

How to convert Java Gradle project to Dynamic Web Project?

▼魔方 西西 提交于 2020-08-02 04:12:05
问题 I am following this article https://www.linkedin.com/pulse/building-jax-rs-project-eclipse-gradle-neeraj-malhotra On how to build a JAX-RS project in Eclipse with Gradle I am using Eclipse Java EE IDE for Web Developers. Version: Oxygen.2 Release (4.7.2) Build id: 20171218-0600 My target runtime is WildFly Full 11.0.0.Final (WildFly Core 3.0.8.Final) my gradle build file apply plugin: 'war' apply plugin: 'eclipse-wtp' sourceCompatibility = 1.8 repositories { mavenCentral() } dependencies {

How to indicate the file name for saving to the browser from a REST service in Jersey?

让人想犯罪 __ 提交于 2020-08-01 16:39:44
问题 i am trying to have a REST service return a zip file from the local harddrive . Following is what i am doing , @Path("/interface3/{Ent_id}/{esf_app_id}/{esf_app_ver}") public class Interface3Mock { // This method is called if TEXT_PLAIN is request @GET @Produces("application/zip") public Response callInterface3_text( @PathParam("Ent_id") Integer entitlement_id, @PathParam("eapp_id") String eapp_id, @PathParam("eapp_ver") String eapp_ver) { File f = new File("D:\\Documentation\\Documentation

How to indicate the file name for saving to the browser from a REST service in Jersey?

随声附和 提交于 2020-08-01 16:35:59
问题 i am trying to have a REST service return a zip file from the local harddrive . Following is what i am doing , @Path("/interface3/{Ent_id}/{esf_app_id}/{esf_app_ver}") public class Interface3Mock { // This method is called if TEXT_PLAIN is request @GET @Produces("application/zip") public Response callInterface3_text( @PathParam("Ent_id") Integer entitlement_id, @PathParam("eapp_id") String eapp_id, @PathParam("eapp_ver") String eapp_ver) { File f = new File("D:\\Documentation\\Documentation

微服务架构的前世今生(六):微服务架构带来的问题

你。 提交于 2020-07-29 05:32:02
上次讲了微服务的前世今生(五):CAP 原则与 BASE 理论,这次我们再说微服务架构的前世今生(六):微服务架构带来的问题。 一、客户端如何访问服务? 传统的开发方式,所有的服务都是本地的,客户端可以直接调用,现在按功能拆分成独立的服务,客户端如何访问? 后台有 N 个服务,前台就需要管理 N 个服务,一个服务下线/更新/升级,前台就要重新部署,这明显不符合我们拆分的理念,另外,N 个服务的调用也是一个不小的网络开销。还有一般微服务在系统内部,通常是无状态的,用户登录信息和权限管理最好有一个统一的地方维护管理(OAuth2)。 所以,一般在后台 N 个服务和客户端之间一般会一个代理(API Gateway),作用如下: - 提供统一服务入口,聚合接口使得服务对调用者透明,客户端与后端的耦合度降低 - 聚合后台服务,节省流量,提高性能,提升用户体验 - 提供安全、流控、过滤、缓存、计费、监控等 API 管理功能 二、服务之间如何通信? 因为服务都是独立部署的,所以通信也就成了问题,不过好在业界已经有很多成熟的解决方案,比如: **同步通信:** - REST(JAX-RS,Spring Boot) - RPC(Dubbo,Thrift) **异步通信:** - RabbitMQ,Kafka 三、这么多服务如何查找? 在微服务架构中,为了高可用,普遍采用集群方式构建服务

Cannot construct instance of `java.time.ZonedDateTime` (no Creators, like default construct, exist)

a 夏天 提交于 2020-07-15 07:11:51
问题 I'm learning Jackson under JAX-RS 1.0. The server returns a HTTP response as follows: { "url": "http://localhost:8080/api/123", "created": "2018-05-26T09:21:26.301+02:00" } and I need to deserialize the JSON response into a Java object called ProductCreated : public class ProductCreated { @JsonProperty("created") private final ZonedDateTime created; @JsonProperty("url") private final String url; public ProductCreated(String url) { this.url = url; this.created = ZonedDateTime.now(); }

Using Jedis pool in JAX-RS app running in Quarkus native results in ClassNotFoundException: org.apache.commons.pool2.impl.DefaultEvictionPolicy

落爺英雄遲暮 提交于 2020-06-28 03:54:28
问题 I'm trying to use JedisPool in application run in Quarkus native mode (works fine in JVM mode). I've already disabled JMX feature of the pool, which is not avaliable in native mode, like this: JedisPoolConfig jedisConfiguration = new JedisPoolConfig(); jedisConfiguration.setJmxEnabled(false); jedisPool = new JedisPool(jedisConfiguration, jedisURI); However I'm hitting following error: 2020-04-29 17:35:37,724 INFO [test.StockQuote] (main) java.lang.IllegalArgumentException: Unable to create

how to see actual body sent from restassured

有些话、适合烂在心里 提交于 2020-06-27 08:17:30
问题 I have created a jax-rs rest api and tested it with rest-assured. All tests are green. Now I am trying to create an html/js front end for it. My problem is I do not know how my json objects should look like to be accepted by my rest api. Thanks to restassured/jax-rs I never handled request strings. I fill in objects and I get objects, (un)marshaling (json) is invisible. Is there any way I can see (debug) what strings are created by rest-assured/java and sent over the "wire"? 回答1: If you want