java.util.scanner

问题 I'm trying to write a loop which runs until I type a specific text in console where the application is running. Something like: while (true) { try { System.out.println("Waiting for input..."); Thread.currentThread(); Thread.sleep(2000); if (input_is_equal_to_STOP){ // if user type STOP in terminal break; } } catch (InterruptedException ie) { // If this thread was intrrupted by nother thread }} And I want it to write a line each time it pass through so I do not want it to stop within the while

问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 4 years ago . I'm new to programming and I'm trying to write a very simple Rock, Paper, Scissors game in Java. It will compile and run fine, but I am looking to say something like "Invalid move. Try again." or something along those lines for when the user (personPlay) does not enter a correct

问题 there I'm making this app to change subtitle files. when I was testing it I faced a strange problem, when I was testing it on non-english (persian for instance) the program wouldn't read the file. this is how I read subtitles in my program: Scanner sub = null; try { sub = new Scanner(new File(address)); } catch (FileNotFoundException ex) { ex.printStackTrace(); } while(sub.hasNext()){ String sentence = sub.nextLine(); //some magical stuff here :) } where address is a String keeping place of

问题 import java.io.*; import java.util.*; class usingDelimiters { public static void main(String args[]) { Scanner dis=new Scanner(System.in); int a,b,c; a=dis.nextInt(); b=dis.nextInt(); c=dis.nextInt(); System.out.println("a="+a); System.out.println("b="+b); System.out.println("c="+c); } } This program is working fine when my input is 1 2 3 (separated by space) But, how to modify my program when my input is 1,2,3 (separated by commas) 回答1: you can use the nextLine method to read a String and

问题 New programmer here. This is probably a really basic question, but it's stumping me nevertheless. What I'm trying to do is write a method that supplies only one integer input so I can use that input in my main program without having to mess around with non-integer inputs. However, even writing the method to do that in its own method seems to be problematic. public static int goodInput () { Scanner input = new Scanner (System.in); //construct scanner boolean test = input.hasNextInt(); //set a

问题 I'm using scanner to read a text file line by line but then how to get line number since scanner iterates through each input?My program is something like this: s = new Scanner(new BufferedReader(new FileReader("input.txt"))); while (s.hasNext()) { System.out.print(s.next()); This works fine but for example: 1,2,3 3,4,5 I want to know line number of it which mean 1,2,3 is in line 1 and 3,4,5 is in line 2.How do I get that? 回答1: You could use a LineNumberReader in place of the BufferedReader to

问题 I am playing around with the Scanner class for learning purposes and i use it to read a very large file (60.000 lines aprox) without using the Reader class , and it stops reading after approximately 400 lines. Do i have to use a Bufferedreader inside the Scanner's constructor or the problem is something else? I want to know why this is happening. Thanks. My code is the usual code to output all the lines. File file1 = new File("file1"); Scanner in= new Scanner(file1); while (scan.hasNextLine()

问题 This question already has answers here : Scanner is skipping nextLine() after using next() or nextFoo()? (16 answers) Closed 2 years ago . I am using Java's Scanner to read user input. If I use nextLine only once, it works OK. With two nextLine first one doesnt wait for user to enter the string(second does). Output: X: Y: (wait for input) My code System.out.print("X: "); x = scanner.nextLine(); System.out.print("Y: "); y = scanner.nextLine(); Any ideas why could this happen? Thanks 回答1: It's

问题 I am using Scanner to scan a .txt document in Java. However, when I open the .txt document in Eclipse, I notice some characters are not being recognized, and they are replaced with something that looks like this: � These characters won't even let me scan the file as while(scan.hasNext) automatically returns false (if these characters are not present, then I can scan the document just fine). So, how do I get Eclipse to recognize these characters so I can scan? I can't manually remove them

问题 EDIT for further readers: the problem was that my input file was corrupted. I don't understand what I'm doing wrong : I was using this code : File f = new File("C:\\Temp\\dico.txt"); BufferedReader r = null; try { r = new BufferedReader(new FileReader(f)); String scan; while((scan=r.readLine())!=null) { if(scan.length()==0) {continue;} //treatment } } catch (FileNotFoundException ex) { Logger.getLogger(Lexique.class.getName()).log(Level.SEVERE, null, ex); } catch (IOException ex) { Logger