java-time

问题 Trying to parse a ZonedDateTime from a date string e.g '2020-08-24'. Upon using TemporalAccesor, and DateTimeFormatter.ISO_OFFSET_DATE to parse, I am getting a java.time.format.DateTimeParseException. Am I using the wrong formatter? Even tried adding 'Z' at the end of date string for it to be understood as UTC private ZonedDateTime getZonedDateTime(String dateString) { TemporalAccessor parsed = null; dateString = dateString + 'Z'; try { parsed = DateTimeFormatter.ISO_OFFSET_DATE.parse

问题 For a REST web service, I need to return dates (no time) with a time zone . Apparently there is no such thing as a ZonedDate in Java (only LocalDate and ZonedDateTime ), so I'm using ZonedDateTime as a fallback. When converting those dates to JSON, I use DateTimeFormatter.ISO_OFFSET_DATE to format the date, which works really well: DateTimeFormatter formatter = DateTimeFormatter.ISO_OFFSET_DATE; ZonedDateTime dateTime = ZonedDateTime.now(); String formatted = dateTime.format(formatter); 2018

问题 Using clj-time it is possible to parse an #inst Date literal like so: (require '[clj-time.coerce :as c]) (c/from-date #inst "2012-12-12") ;; => #object[org.joda.time.DateTime 0x4a251269 "2012-12-12T00:00:00.000Z"] How would this be done using the new java.time wrapper clojure.java-time? 回答1: PLEASE NOTE: Joda Time and the clj-time library which wraps it are both deprecated. You should use java.time via Java interop for most tasks. There are also some helper functions here you may find useful.

问题 Backstory I recently came across a problem with saving a LocalTime to a TIME column in a MySQL database. Saving a value of 9:00 was causing 8:00 to be saved in the database. This problem did not occur on my dev environment (Windows), but did occur on two Linux machines we tried. My code was the following: preparedStatement.setObject(parameterIndex, localTime, JDBCType.TIME); After investigating, I eventually found that the MySQL JDBC driver was using java.sql.Time.valueOf(localTime) , then

问题 Before Java-8 I got accustomed to always keep anything date/time related as milliseconds since Epoch and only ever deal with human readable dates/times on the way out, i.e. in a UI or a log file, or when parsing user generated input. I think this is still safe with Java-8, and now I am looking for the most concise way to get a formatted date out of a milliseconds time stamp. I tried df = Dateformatter.ofPattern("...pattern..."); df.format(Instant.ofEpochMilli(timestamp)) but it bombs out with

问题 Before Java-8 I got accustomed to always keep anything date/time related as milliseconds since Epoch and only ever deal with human readable dates/times on the way out, i.e. in a UI or a log file, or when parsing user generated input. I think this is still safe with Java-8, and now I am looking for the most concise way to get a formatted date out of a milliseconds time stamp. I tried df = Dateformatter.ofPattern("...pattern..."); df.format(Instant.ofEpochMilli(timestamp)) but it bombs out with

问题 Please tell me how to set the date (current date minus one day) and time equal to 19:00:00 using such a construction? new java.sql.Timestamp(java.util.Calendar.getInstance.getTime().getTime()) LocalDateTime don't use. 回答1: I recommend you do it using the java.time (the modern date-time API). Solution, purely using the modern API: import java.time.LocalTime; import java.time.OffsetDateTime; import java.time.ZoneId; import java.time.ZonedDateTime; public class Main { public static void main

问题 Please tell me how to set the date (current date minus one day) and time equal to 19:00:00 using such a construction? new java.sql.Timestamp(java.util.Calendar.getInstance.getTime().getTime()) LocalDateTime don't use. 回答1: I recommend you do it using the java.time (the modern date-time API). Solution, purely using the modern API: import java.time.LocalTime; import java.time.OffsetDateTime; import java.time.ZoneId; import java.time.ZonedDateTime; public class Main { public static void main

问题 This question already has answers here : Java Time period in decimal number of years (3 answers) Closed 3 years ago . I am new in using Java 8 date time API and was wondering how can i able to calculate the age in decimals which returns the double value like 30.5 which means 30 years and 6 months? For example the below sample code gets me the output as 30.0 but not 30.5 which probably am trying for. LocalDate startDate = LocalDate.of(1984, Month.AUGUST, 10); LocalDate endDate = LocalDate.of

问题 Weirdly, I found several times there's difference when running with spark-submit vs running with spark-shell (or zeppelin), though I don't believe it. With some codes, spark-shell (or zeppelin) can throw this exception, while spark-submit just works fine: org.apache.spark.SparkException: Task not serializable at org.apache.spark.util.ClosureCleaner$.ensureSerializable(ClosureCleaner.scala:345) at org.apache.spark.util.ClosureCleaner$.org$apache$spark$util$ClosureCleaner$$clean(ClosureCleaner