itertools

How to summarize on different groupby combinations?

自作多情 提交于 2019-11-27 04:07:42
问题 I am compiling a table of top-3 crops by county. Some counties have the same crop varieties in the same order. Other counties have the same crop varieties in a different order. df1 = pd.DataFrame( { "County" : ["Harney", "Baker", "Wheeler", "Hood River", "Wasco" , "Morrow","Union","Lake"] , "Crop1" : ["grain", "melons", "melons", "apples", "pears", "raddish","pears","pears"], "Crop2" : ["melons","grain","grain","melons","carrots","pears","carrots","carrots"], "Crop3": ["apples","apples",

list around groupby results in empty groups

二次信任 提交于 2019-11-27 03:50:27
问题 I was playing around to get a better feeling for itertools groupby , so I grouped a list of tuples by the number and tried to get a list of the resulting groups. When I convert the result of groupby to a list however, I get a strange result: all but the last group are empty. Why is that? I assumed turning an iterator into a list would be less efficient but never change behavior. I guess the lists are empty because the inner iterators are traversed but when/where does that happen? import

itertools.cycle().next()?

家住魔仙堡 提交于 2019-11-27 02:02:27
问题 Well, I was using itertools.cycle().next() method with Python 2.6.6, but now that I updated to 3.2 I noticed that itertools.cycle() object has no method next() . I used it to cycle a string in the spin() method of a Spinner class. So if we cycle the tuple ('|', '/', '-', '\\', '|', '/', '-') , it'll print: | , / , - , \ , | , / , - , | , / and so on... I've searched the release notes of Python 3.0, 3.1 and 3.2 and didn't noticed any change on this. When this have changed? Is there any simple

When is it better to use zip instead of izip?

◇◆丶佛笑我妖孽 提交于 2019-11-27 00:07:59
When is it better to use zip instead of itertools.izip ? When you know you'll want the full list of items constructed (for instance, for passing to a function that would modify that list in-place). Or when you want to force the arguments you're passing to zip() to be completely evaluated at that specific point. zip computes all the list at once, izip computes the elements only when requested. One important difference is that 'zip' returns an actual list, 'izip' returns an 'izip object', which is not a list and does not support list-specific features (such as indexing): >>> l1 = [1, 2, 3, 4, 5,

importing izip from itertools module gives NameError in Python 3.x

别等时光非礼了梦想. 提交于 2019-11-26 22:36:35
I am trying to import the izip module like so: from itertools import izip However after recently changing over from Python 2.7 to 3 - it doesn't seem to work. I am trying to write to a csv file: writer.writerows(izip(variable1,2)) But I have no luck. Still encounter an error. In Python 3 the built-in zip does the same job as itertools.izip in 2.X(returns an iterator instead of a list). The zip implementation is almost completely copy-pasted from the old izip , just with a few names changed and pickle support added. Here is a benchmark between zip in Python 2 and 3 and izip in Python 2: Python

Using itertools.product and want to seed a value

谁都会走 提交于 2019-11-26 22:25:01
问题 So I've wrote a small script to download pictures from a website. It goes through a 7 alpha charactor value, where the first char is always a number. The problem is if I want to stop the script and start it up again I have to start all over. Can I seed itertools.product somehow with the last value I got so I don't have to go through them all again. Thanks for any input. here is part of the code: numbers = '0123456789' alnum = numbers + 'abcdefghijklmnopqrstuvwxyz' len7 = itertools.product

zip_longest without fillvalue

偶尔善良 提交于 2019-11-26 22:01:41
问题 I am searching for a middle ground between Python's zip and zip_longest functions (from the itertools module), that exhausts all given iterators, but does not fill in anything. So, for example, it should transpose tuples like so: (11, 12, 13 ), (11, 21, 31, 41), (21, 22, 23, 24), --> (12, 22, 32, 42), (31, 32 ), (13, 23, 43), (41, 42, 43, 44), ( 24, 44) (Spaces added for nicer graphical alignment.) I managed to compose a crude a solution by cleaning out the fillvalue s after zip_longest . def

Group consecutive integers and tolerate gaps of 1

泄露秘密 提交于 2019-11-26 21:49:01
问题 In Python, given a list of sorted integers, I would to group them by consecutive values and tolerate gaps of 1. For instance, given a list my_list : In [66]: my_list Out[66]: [0, 1, 2, 3, 5, 6, 10, 11, 15, 16, 18, 19, 20] I would like the following output: [[0, 1, 2, 3, 5, 6], [10, 11], [15, 16, 18, 19, 20]] Now, if I didn't have to tolerate gaps of 1, I could apply the neat solution explained here: import itertools import operator results = [] for k, g in itertools.groupby(enumerate(my_list)

Numpy equivalent of itertools.product [duplicate]

房东的猫 提交于 2019-11-26 21:23:56
问题 This question already has answers here : itertools product speed up (6 answers) Closed 4 years ago . I know about itertools.product for iterating on a list of several dimensions of keywords. For instance if I have this: categories = [ [ 'A', 'B', 'C', 'D'], [ 'E', 'F', 'G', 'H'], [ 'I', 'J', 'K', 'L'] ] and I use itertools.product() over it, I have something like: >>> [ x for x in itertools.product(*categories) ] ('A', 'E', 'I'), ('A', 'E', 'J'), ('A', 'E', 'K'), ('A', 'E', 'L'), ('A', 'F',

How do I “multi-process” the itertools product module?

依然范特西╮ 提交于 2019-11-26 21:22:58
问题 So I tried I tried calculating millions and millions of different combinations of the below string but I was only calculating roughly 1,750 combinations a second which isn't even near the speed I need. So how would I reshape this so multiple processes of the same thing are calculating different parts, while not calculating parts that have already been calculated and also maintaining fast speeds? The code below is partially what I've been using. Any examples would be appreciated! from