iso

Can I convert iso date to milliseconds? for example I want to convert this iso 2012-02-10T13:19:11+0000 to milliseconds. Because I want to compare current date from the created date. And created date is an iso date. Try this var date = new Date("11/21/1987 16:00:00"); // some mock date var milliseconds = date.getTime(); // This will return you the number of milliseconds // elapsed from January 1, 1970 // if your date is less than that date, the value will be negative EDIT You've provided an ISO date. It is also accepted by the constructor of the Date object var myDate = new Date("2012-02-10T13

I think the question says it all. An example covering most standards from C89 to C11 would be helpful. I though of this one, but I guess it is just undefined behaviour: #include <stdio.h> int main( int argc, char* argv[] ) { const char *s = NULL; printf( "%c\n", s[0] ); return 0; } EDIT: As some votes requested clarification: I wanted to have a program with an usual programming error (the simplest I could think of was an segfault), that is guaranteed (by standard) to abort. This is a bit different to the minimal segfault question, which don't care about this insurance. Shafik Yaghmour A

This question already has an answer here: Superiority of unnamed namespace over static? 3 answers The section $7.3.1.1/2 from the C++ Standard reads: The use of the static keyword is deprecated when declaring objects in a namespace scope; the unnamed-namespace provides a superior alternative. I don't understand why an unnamed namespace is considered a superior alternative? What is the rationale? I've known for a long time as to what the standard says, but I've never seriously thought about it, even when I was replying to this question: Superiority of unnamed namespace over static? Is it