intervals

Max coverage disjoint intervals

六眼飞鱼酱① 提交于 2019-12-14 02:33:20
问题 Assume you have k<=10^5 intervals [a_i, b_i] \in [1,10^18] (some of them may overlap), and you need to choose a set of intervals mutually disjoint such that their union is maximal. Not maximum number of disjoint intervals, but the union must cover the most. Can't try all possible subsets 2^k infeasible. Greedy approaches ordering by a_i ( interval covering algorithm) and ordering by b_i ( maximum number of disjoint intervals algorithm ) didn't work Can't figure out if there is a dynamic

Intersecting overlapping intervals in Java

ⅰ亾dé卋堺 提交于 2019-12-14 02:21:13
问题 I have an input set of date ranges that may overlap. Instead of combining these overlapping date ranges, I want to create new date ranges with adjusted dates, e.g.: |---------------------–| |-----| |--------------–| should end up in: |-------|---|-|--------|----| Is there an efficient way to solve this with Java? Thanks in advance! UPDATE: I didn't mention my own approach in my first question, so here it is: I'd simply take the start and the end date of an interval and add it to a sorted set.

Overlapping intervals and the amount of overlaps

怎甘沉沦 提交于 2019-12-13 19:24:52
问题 This question might be similar to others but is a bit different. Let's say we have a set of intervals that goes like this let's say A-9 are numbers but for the sake of formatting I used letters): <-a---> <------c---> <------------MAIN> ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789 <--d-> <--b-------> So we have the Main interval which goes from I to Z , the interval a that goes from M to S and so on. Now I want to have the intervals where I have the most overlaps WITHIN the main one (which is

R - output overlapping intervals

你。 提交于 2019-12-13 16:53:17
问题 fileA contains intervals (start, end), and a value assigned to that interval (value). start end value 0 123 1 #value 1 at positions 0 to 122 included. 123 78000 0 #value 0 at positions 123 to 77999 included. 78000 78004 56 #value 56 at positions 78000, 78001, 78002 and 78003. 78004 78005 12 #value 12 at position 78004. 78005 78006 1 #value 1 at position 78005. 78006 78008 21 #value 21 at positions 78006 and 78007. 78008 78056 8 #value 8 at positions 78008 to 78055 included. 78056 81000 0

group values in intervals

只愿长相守 提交于 2019-12-13 15:53:44
问题 I have a pandas series containing zeros and ones: df1 = pd.Series([ 0, 0, 0, 0, 0, 1, 1, 1, 0, 0, 0]) df1 Out[3]: 0 0 1 0 2 0 3 0 4 0 5 1 6 1 7 1 8 0 9 0 10 0 I would like to create a dataframe df2 that contains the start and the end of intervals with the same value, together with the value associated... df2 in this case should be... df2 Out[5]: Start End Value 0 0 4 0 1 5 7 1 2 8 10 0 My attempt was: from operator import itemgetter from itertools import groupby a=[next(group) for key, group

Backbone.js fire event on .remove()

一曲冷凌霜 提交于 2019-12-13 12:35:38
问题 I need to fire a function when a Backbone.js view is removed. I guess something like a de-constructor. The code below is a snippet I wrote; I know it won't work. However, I do remember seeing in the past a video tutorial on how to write a function that does this. The reason I need to run a de-constructing function is to clear the interval set inside a view when the view is removed. ViewWeather = Backbone.View.extend({ interval: setInterval(function() {console.log('interval fire');}, 1000), //

How does one break out of a Set Interval in Action Script 2

核能气质少年 提交于 2019-12-13 03:45:54
问题 p2 = setInterval(function () { clearInterval(p2); some code here; }, waitTime) I need to break out of this interval in a separate function. This plays an array of SWF movies - there is a purge function that needs to stop this interval. How can I stop this interval from a separate function in AS2? 回答1: the whole thing with setInterval is scope. the way your code looks, p2 is in the main timeline and it belongs to this/_level0/_root right ? clearInterval() is a global function as well, so you

optimize has weird behavior when I change the interval

久未见 提交于 2019-12-13 02:51:57
问题 I have a problem with optimize() in R. When I only change the interval in optimize() , surprisingly, the optimal parameter value will vary a lot. I found posts with similar problems before, but there is no answer for them. I got really different values from different intervals: c(-1,1): -0.819 c(-1,2): -0.729 c(0.3,0.99):0.818 c(0.2,0.99):0.803 c(0.1,0.99):0.23 c(0,0.99):0.243 I really need help on this problem, thank you guys if you could help or give me any information!! edit : here is a

Android - How can I make an animation of an image occur at a certain interval?

て烟熏妆下的殇ゞ 提交于 2019-12-13 02:37:21
问题 I'm taking a Coursera class on Android programming. Here's a illustration of what I'm trying to do... Here's the code I have so far... XML: <Button android:id="@+id/startbutton" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_above="@+id/leftfoot" android:layout_alignRight="@+id/leftfoot" android:onClick="startRhythmandAnimation" android:text="@string/start_button" /> Java: public class Assignment3MainActivity extends Activity { private View

BigQuery select data within a time interval

时光怂恿深爱的人放手 提交于 2019-12-13 02:15:03
问题 my data looks like name| From | To_City | Date of request Andy| Paris | London| 08/21/2014 12:00 Lena | Koln | Berlin | 08/22/2014 18:00 Andy| Paris | London | 08/22/2014 06:00 Lisa | Rome | Neapel | 08/25/2014 18:00 Lena | Rome | London | 08/21/2014 20:00 Lisa | Rome | Neapel | 08/24/2014 18:00 Andy| Paris | London| 08/25/2014 12:00 I want to find how many identical drive requests a person had within +/- one day. I'd love to receive a table saying: name| From | To_City | avg Date of request