intersection

This question already has an answer here: Removing duplicates from a list of lists 10 answers These are my two lists; k = [[1, 2], [4], [5, 6, 2], [1, 2], [3], [4], [5,9]] kDash = [[1, 2], [4], [5, 6, 2], [1, 2], [3], [4], [5,6], [1,2]] My output should be the following; [[1, 2], [4], [5, 6, 2], [1, 2], [3], [4]] how can I get to this output? thank you in advance You will have to convert the lists to list of tuples, and then use the intersection. Note that below solution may have elements in a different order, and duplicates will obviously not be there, since I'm using set. In [1]: l1 = [[1, 2

I have a canvas for diagramming, and want to join nodes in the diagram by directed lines (arrow ends). I tried the anchor approach, where lines only attach at specific points on the nodes but that did not work for me, it looked like crap. I simply want a line from the centre of each object to the other, and stop the line at the nodes' edge in order for the arrow end to show properly. But finding the edge of a canvas element to test intersections against has proven difficult. Any ideas? I got a method working using the bounding box of the element. It is not perfect, since my elements are not

I am working on an algorithm and trying to figure out how to solve it given the following information: I would like to find the intersection between n number of lists assume that I have a (properly working) intersection(a, b) function assume that the intersection() only takes two lists as input So the problem would look something like this: var a = {1, 2, 'b'}; var b = {2, 'b', 'b'}; var c = {2, 'b', 'c'}; var d = {'a', 'b', 'c'}; //this is the part that does not work, of course: function intersect_all(d) { //what goes in here??? } Note: I don't want to use python for this, since python has

I need to calculate volume intersection and penetration depth between 3D triangular meshes (e.g. in .obj format), but I am quite new to computational geometry. In a previous post ( Mesh to mesh intersections ) and from my google search, I found a few C++ libraries which might be appropriate to do the job: CGAL PQP libigl SWIFT Though, I am not sure which one could be the most appropriate for a beginner. Any suggestion? libigl as of version 1.1 has robust mesh boolean operations in igl/boolean/mesh_boolean.h . This uses either an implementation using CGAL's exact arithmetic kernel or a wrapper

Is it possible in SVG, using any method, to call an even if two specific elements touch? Or would I have to code the long way, and figure out if their borders touch with complicated maths? There are actually four methods available on the outermost SVG element for intersection handling in the SVG 1.1 DOM: getIntersectionList getEnclosureList checkIntersection checkEnclosure Unfortunately I think the cross-browser support for these methods is still not great. I don't think there are any built-in methods, but this guy wrote a Javascript library that detects collisions: http://www.kevlindev.com

How can I find the intersecttion between 2 arrays in C#, in a fast way? There's the Intersect extension method on Enumerable. It works on any IEnumerable<T> including arrays. Here is an example use of Linq Intersect. // Assign two arrays. int[] array1 = { 1, 2, 4 }; int[] array2 = { 2, 3, 4 }; // Call Intersect extension method. var intersect = array1.Intersect(array2); foreach (int value in intersect) { label1.Text += value + "\n"; } 来源： https://stackoverflow.com/questions/4248433/intersect-two-arrays

I have trajectory data, where each trajectory consists of a sequence of coordinates(x, y points) and each trajectory is identified by a unique ID. These trajectories are in x - y plane, and I want to divide the whole plane into equal sized grid (square grid). This grid is obviously invisible but is used to divide trajectories into sub-segments. Whenever a trajectory intersects with a grid line, it is segmented there and becomes a new sub-trajectory with new_id . I have included a simple handmade graph to make clear what I am expecting. It can be seen how the trajectory is divided at the