intersection

! 1 I have the Canny edge output of a ear... i have connected the farthest two boundaries with a line(green). Now I want to draw a normal from the midpoint of this line to the outer boundary(left side). The code i have written helps me to plot a normal but i want the red line to exactly meet the white boundary. Also I want the point of intersection at the point where it meets. I have also thought about another method for the same.By changing 50 to 60 pixels (in the code) the red line crosses the white boundary. If I get the point of intersection of the same then I can easily plot the line of

I would like to know if there is a way to find the intersection of a key value pair in an array of objects. Let's say you have an array of three objects which all have the same keys like this : arrayOfObj = [ { "a": 1, "b": "stringB" "c": {"c1":1, "c2": "stringC2" } }, { "a": 1, "b": "stringBdiff" "c": {"c1":1, "c2": "stringC2" } }, { "a": 1, "b": "stringB" "c": {"c1":1, "c2": "stringC2" } } ] I would like to find the common key value pairs of the three objects: output= [ {"a":1}, {"c": {"c1":1, "c2":"stringC2" } } ] This is what I have done so far, it works but not on nested objects. I would

I tried to solve this problem, but I could not implement. Could you help me anything for this? Problem Mat1 | Mat2 | Mat3 1 2 | 1 3 | 2 6 1 3 | 2 6 | 2 5 2 4 | 3 1 | 3 1 3 1 | 3 5 | 5 2 4 5 | When there are 3 matrices(for example above), I want to get this result for the intersection rows in [column1 column2 matrixnumber] form. The result for above example would be 1 3 1 1 3 2 2 6 2 2 6 3 3 1 1 3 1 2 3 1 3 It would be OK if the result is in the form [column1 column2 firstmatrix secondmatrix, ...] 1 3 1 2 2 6 2 3 3 1 1 2 3 For this problem, I want to use at most one for-loop. Do you have any

I am calculating intersection, union and differences of sets. I have a typedef of my set type: typedef set<node_type> node_set; When it is replaced with typedef hash_set<node_type> node_set; The results are different. It's a complicated program, and before I start debugging - am I doing it right? When I use functions like this: set_intersection(v_higher.begin(), v_higher.end(), neighbors[w].begin(), neighbors[w].end(), insert_iterator<node_set>(tmp1, tmp1.begin())); should they work seamlessly with both set and hash_set? kennytm I don't think so. One of the pre-condition of set_intersection is

Starting Point I have a multiple array, like the follow example. $array = array ( 'role_1' => array ( 0 => 'value_2', 0 => 'value_3', ), 'role_2' => array ( 0 => 'value_1', 1 => 'value_2', ), 'role_3' => array ( 0 => 'value_2', 1 => 'value_3', ), ) Goal I like to loop about the sub-arrays to get only the intersection. The array was created dynamically, can have a lot of sub-arrays role_[x] and also a lot of key/value inside the sub-arrays. The key is not necessary, only the value. The key is also a count, not a string. As result I like to get in this example this small array. $array = array(

I currently have two arrays each of which contain ranges. How would you go about getting the intersection of these two arrays. In other words, I would like to get an array of ranges that only contains the ranges that are contained in both of the two original arrays. I tried .Intersect but that does not work on arrays as I learned. array1: (Range("A1"),Range("B1"),Range("C1")) array2: (Range("A1"),Range("A2"), Range("A3")) Result: (Range("A1")) you can use this code. The idea is to merge your array in a single range using an iterative Union . Then you can use the built-in Intersect . Function

I have a code that takes a condition C as an input, and computes the solution to my problem as an 'allowed area' A on the (x,y) space. This area is made of several 'tubes', which are defined by 2 lines that can never cross. The final result I'm looking for must satisfy k conditions {C1, .., Ck}, and is therefore an intersection S between k areas {A1, .. , Ak}. Here is an example with 2 conditions (A1: green, 3 tubes. A2: purple, 1 tube); the solution S is in red. How can I find S when I'm dealing with 4 areas of around 10 tubes each? (The final plot is awful!) I would need to be able to plot