intersection

Somewhat simple PHP array intersection question

拜拜、爱过 提交于 2019-12-12 08:09:36
问题 Maybe I'm going insane, but I could have sworn that there was an PHP core function which took two arrays as arguments: $a = array('1', '3'); $b = array('1'=>'apples', '2'=>'oranges', '3'=>'kiwis'); And performs an intersection where the values from array $a are checked for collisions with the keys in array $b . Returning something like array('1'=>'apples', '3'=>'kiwis'); Does such a function exist (which I missed in the documentation), or is there a very optimized way to achieve the same

Ray and square/rectangle intersection in 3D

走远了吗. 提交于 2019-12-12 07:19:20
问题 Hei. Are making a game and are looking for a ray intersection onto a square or a rectangle only in 3D space. Have search the web and found many solutions but nothing i can understand have a line and line segment intersection script in 2D but i cant figure out have to make it 3D. It is not important from what side it intersect the square or rectangle but it must be able to retrive the point of intersection vector so that later can be tested for distance to se if it occurred before or after

groovy/java check list intersections and combine elements

血红的双手。 提交于 2019-12-12 06:09:25
问题 I have a list: def a = [[14, 17, 12, 5], [14, 17, 12, 8, 3], [5, 2], [9]] I need to check intersections and if two lists intersect, combine them. The result should be as follows: def b = [[14, 17, 12, 5, 8, 3, 2], [9]] (i.e 14 is in first sublist, which is also in second sublist, and recursively so on...) How this task can be solved? 回答1: You can do something like this in Groovy: def a = [[14, 17, 12, 5], [14, 17, 12, 8, 3], [5, 2], [9]] def rslt = a.inject( [ ] ) { c, n -> for( cc in c ) {

Intersection between two geographic lines

回眸只為那壹抹淺笑 提交于 2019-12-12 05:45:51
问题 I'm using the DotSpatial C# library and I'm trying to use the following code to try to find the intersection point between two lines (I know they do intersect) var geoproj = DotSpatial.Projections.KnownCoordinateSystems.Geographic.World.WGS1984; var d1 = new FeatureSet { Projection = geoproj }; //var c1 = new Coordinate(31.877484, 34.736723); //var c2 = new Coordinate(31.879607, 34.732362); var c1 = new Coordinate(0, -1); var c2 = new Coordinate(0, 1); var line1 = new LineString(new[] { c1,

Algorithm for Intersection (or Merge) of Numerical Ranges

╄→гoц情女王★ 提交于 2019-12-12 03:54:02
问题 Let's say I have a list of ranges like this: List A) 0 to 3, 9 to 14 List B) 1 to 4, 6 to 7, 14 to 16 List C) 15 (i.e., 15 to 15) I'd like to get a merged list of these ranges where the result would look like this: Merged Result List) 0 to 4, 6 to 7, 9 to 16 (notice that the result is a merging/intersection/union of Lists A, B, and C) I'm sure there's an algorithm for this, but have no idea. Has anyone come across this before? (pseudocode, or VB, would be great) Adding a visual representation

How can i get union of 2D list items when there occurs any intersection (in efficient way)?

我的未来我决定 提交于 2019-12-12 02:34:45
问题 I have 2D list in python list = [[9, 2, 7], [9, 7], [2, 7], [1, 0], [0, 5, 4]] I would like to get union of list items if there occurs any intersection. For example [9, 2, 7] , [9, 7] , [2, 7] has intersection of more than one digit. The union of this would be [9,2,7] . How can i get the final list as follows in efficient way ? finalList = [[9,2,7], [0, 1, 5, 4]] N.B. order of numbers is not important. 回答1: You have a graph problem. You want to build connected components in a graph whose

Why does the resulting shape from Shape.intersect appear at an incorrect position?

落花浮王杯 提交于 2019-12-12 02:29:41
问题 For one of my current javafx projects I'm working with Venn Diagrams. I'd like to take advantage of Shape.intersect to ease the amount of math calculations I'd have to personally work through (and avoid working with Path objects). Shape.intersect produces a perfect shape, but it is translated / moved a bit and I can't figure out how much to put it back. Ideally, I'd like to have the intersection area occur exactly where the two original shapes intersect - i.e. the new intersection would fit

How to find the intersection of two lines given a point on each line and a parallel vector

做~自己de王妃 提交于 2019-12-12 02:25:06
问题 I need an algorithm that can find the intersection of two 2D lines. Each line will come in the form of a point on the line and the dx/dy of a parallel vector . I've tried parameterizing each line and solving the system of equations to solve for the parameterized variable which I could plug back into the parametric equation of the lines and get my x/y, but my attempt failed. Any ideas? I'm programming in Python but the language doesn't much matter. 回答1: You basically have to solve the

How to repaint over images in Java game

好久不见. 提交于 2019-12-12 01:55:37
问题 Hello everyone I am having trouble with painting over coins that the user intersects with. What I want this code to do is when the user sprite intersects with any of the ten coin images it paints over the coin so that it no longer appears on the screen (also need to add in some kind of counter so that when the user collects all ten coins it will stop the thread, and say "You Win!"). My question is how would I go about doing this because I have tried using repaint() in the if statements, and

Distance for each intersected points of a line in increased order in 2D coordinate

核能气质少年 提交于 2019-12-12 00:43:22
问题 I am calculating the distance between A(x0,y0) and B(x1,y1) points in a 2D (x,y). I have the following code which represents intersected points of each cell in the given two boundary points, A(x0,y0) and B(x1,y1). def intersected_points(x0, x1, y0, y1): # slope m = (y1 - y0 )/( x1 - x0) # Boundary of the selected points x_ceil = ceil( min (x0, x1 )) x_floor = floor( max(x0, x1)) y_ceil = ceil( min(y0, y1)) y_floor = floor( max(y0, y1)) # calculate all intersected x coordinate ax = [] for x in