intersection

问题 I'm doing some set operations in Python, and I noticed something odd.. >> set([1,2,3]) | set([2,3,4]) set([1, 2, 3, 4]) >> set().union(*[[1,2,3], [2,3,4]]) set([1, 2, 3, 4]) That's good, expected behaviour - but with intersection: >> set([1,2,3]) & set([2,3,4]) set([2, 3]) >> set().intersection(*[[1,2,3], [2,3,4]]) set([]) Am I losing my mind here? Why isn't set.intersection() operating as I'd expect it to? How can I do the intersection of many sets as I did with union (assuming the [[1,2,3],

问题 I'm drawing n rectangles on a canvas. The rectangles are draggable and scalable. I want to prevent them from overlapping or intersecting. The best case is, if they just snap to each other. I figured out to check the intersection. In my example I set the opacity of touching objects to 0.1. Coincidentally in my attempt to solve this problem, my objects cant be released when they touch another object. See http://jsfiddle.net/gcollect/jZw7P/ It's because of line 91, where the alert is not

问题 !1I have the Canny edge output of a ear... i have connected the farthest two boundaries with a line(green). Now I want to draw a normal from the midpoint of this line to the outer boundary(left side). The code i have written helps me to plot a normal but i want the red line to exactly meet the white boundary. Also I want the point of intersection at the point where it meets. I have also thought about another method for the same.By changing 50 to 60 pixels (in the code) the red line crosses

问题 I would like to know if there is a way to find the intersection of a key value pair in an array of objects. Let's say you have an array of three objects which all have the same keys like this : arrayOfObj = [ { "a": 1, "b": "stringB" "c": {"c1":1, "c2": "stringC2" } }, { "a": 1, "b": "stringBdiff" "c": {"c1":1, "c2": "stringC2" } }, { "a": 1, "b": "stringB" "c": {"c1":1, "c2": "stringC2" } } ] I would like to find the common key value pairs of the three objects: output= [ {"a":1}, {"c": {"c1"

问题 I currently have two arrays each of which contain ranges. How would you go about getting the intersection of these two arrays. In other words, I would like to get an array of ranges that only contains the ranges that are contained in both of the two original arrays. I tried .Intersect but that does not work on arrays as I learned. array1: (Range("A1"),Range("B1"),Range("C1")) array2: (Range("A1"),Range("A2"), Range("A3")) Result: (Range("A1")) 回答1: you can use this code. The idea is to merge

问题 Trying to write a for function that takes two strings and returns the characters that intersect in the order that they appear in the first string. Here's what I tried: def strIntersection(str1, str2): for i in str1: str3 = '' str3 = str3.join(i for i in str1 if i in str2 not in str3) return str3 str1 = 'asdfasdfasfd' str2 = 'qazwsxedc' strIntersection(str1,str2) => 'asdasdasd' however I only want the the intersection characters to appear once and in order of the first string ie. 'asd' Can

问题 Trying to write a for function that takes two strings and returns the characters that intersect in the order that they appear in the first string. Here's what I tried: def strIntersection(str1, str2): for i in str1: str3 = '' str3 = str3.join(i for i in str1 if i in str2 not in str3) return str3 str1 = 'asdfasdfasfd' str2 = 'qazwsxedc' strIntersection(str1,str2) => 'asdasdasd' however I only want the the intersection characters to appear once and in order of the first string ie. 'asd' Can

问题 I have this function vector<string> instersection(const vector<string> &v1, const vector<string> &v2); I have two vectors of strings and I want to find the strings that are present in both, which then fills a third vector with the common elemnts. If my vectors are... v1 = <"a","b","c"> v2 = <"b","c"> 回答1: Try std::set_intersection, for example: #include <algorithm> //std::sort #include <iostream> //std::cout #include <string> //std::string #include <vector> //std::vector std::vector<std:

问题 This could be terribly trivial, but I'm having trouble finding an answer that executes in less than n^2 time. Let's say I have two string arrays and I want to know which strings exist in both arrays. How would I do that, efficiently, in VB.NET or is there a way to do this other than a double loop? 回答1: The simple way (assuming no .NET 3.5) is to dump the strings from one array in a hashtable, and then loop through the other array checking against the hashtable. That should be much faster than

问题 i think this question has been asked before but i havent been able to deduce a clear answer. I am trying to find the best way (or a way) to intersect two completely different ienumerable collections. class A: int z1 int z2 int z3 string z4 class B: int j5 int j6 T j7 T j8 string j9 ..I want to intersect List<A> with List<B> on z2 == j6 . can this be done? 回答1: The question doesn't really make sense - what would the result type be? Intersections have to be performed on two sequences of the