intersection

Regex java. Why using intersection?

徘徊边缘 提交于 2019-12-29 07:49:10
问题 I have taken from this oracle tutorial on java regex, the following bit: Intersections To create a single character class matching only the characters common to all of its nested classes, use &&, as in [0-9&&[345]]. This particular intersection creates a single character class matching only the numbers common to both character classes: 3, 4, and 5. Enter your regex: [0-9&&[345]] Enter input string to search: 3 I found the text "3" starting at index 0 and ending at index 1. Why would it be

Regex java. Why using intersection?

霸气de小男生 提交于 2019-12-29 07:48:08
问题 I have taken from this oracle tutorial on java regex, the following bit: Intersections To create a single character class matching only the characters common to all of its nested classes, use &&, as in [0-9&&[345]]. This particular intersection creates a single character class matching only the numbers common to both character classes: 3, 4, and 5. Enter your regex: [0-9&&[345]] Enter input string to search: 3 I found the text "3" starting at index 0 and ending at index 1. Why would it be

NetLogo two agentsets operations

≡放荡痞女 提交于 2019-12-29 07:34:26
问题 I have two agentsets. Are there functions for finding: An agentset of agents that are present in both (intersection) An agentset of agents that are present in one and not the other I'm finding it very difficult to implement this by hand, especially when it's needed inside of a triple ask Ideal use would be similar to with syntax: let cross set1 and-in set2 let uniq set1 with [color = red] not-in set2 Simple things like "Is agent A in the agentset X?" are problematic 回答1: For the first one you

Determining if two rays intersect

。_饼干妹妹 提交于 2019-12-29 03:27:06
问题 I have two rays on a 2D plane that extend to infinity, but both have a starting point. They are both described by a starting point and a vector in the direction of the ray extending to infinity. I want to find out if the two rays intersect, but I don't need to know where they intersect (it's part of a collision detection algorithm). Everything I have looked at so far describes finding the intersection point of two lines or line segments. Is there a fast algorithm to solve this? 回答1: Given:

Intersection of two strings in Java

廉价感情. 提交于 2019-12-28 02:52:51
问题 Need a Java function to find intersection of two strings. i.e. characters common to the strings. Example: String s1 = new String("Sychelless"); String s2 = new String("Sydney"); 回答1: Using HashSet<Character> : HashSet<Character> h1 = new HashSet<Character>(), h2 = new HashSet<Character>(); for(int i = 0; i < s1.length(); i++) { h1.add(s1.charAt(i)); } for(int i = 0; i < s2.length(); i++) { h2.add(s2.charAt(i)); } h1.retainAll(h2); Character[] res = h1.toArray(new Character[0]); This is O(m +

Find the intersection between sublists

拜拜、爱过 提交于 2019-12-25 18:54:44
问题 Recently i encounter with a question about Find the intersection between sublists . that tells the sublist which have any (1 or more ) intersection together become one. for example the following list : l=[[1,2,3],[0,13,6],[9,10],[3,4,5],[10,11],[6,7,50]] must be converted to : [[1, 2, 3, 4, 5],[0, 50, 6, 7, 13],[9, 10, 11]] So i wrote the following function to do it that works well with a good performance, i use set for its fast complexity for checking membership and also in inner loop i use

SceneKit with SpriteKit intersection of nodes

自作多情 提交于 2019-12-25 08:18:30
问题 Hi I want to have a selection box on my game. I assume that making with 'SpriteKit' overlay is the easiest way to do But is there any API to detect intersection of 'SKShapeNode' and 'SCNNode' (Ignoring the Z axis ofcourse) ? What have I tried to do: _unitsArray is an array of SCNNodes that I wish to have they're bounding boxes in a SKScene for (SCNNode * node in _unitsArray) { SCNVector3 min = SCNVector3Zero; SCNVector3 max = SCNVector3Zero; [node getBoundingBoxMin:&min max:&max]; NSLog(@"Min

3d line-intersection code not working properly

痴心易碎 提交于 2019-12-25 04:27:41
问题 I created this piece of code to get the intersection of two 3d line-segments. Unfortunately the result of this code is inaccurate, the intersection-point is not always on both lines. I am confused and unsure what I'm doing wrong. Here is my code: --dir = direction --p1,p2 = represents the line function GetIntersection(dirStart, dirEnd, p1, p2) local s1_x, s1_y, s2_x, s2_y = dirEnd.x - dirStart.x, dirEnd.z - dirStart.z, p2.x - p1.x, p2.z - p1.z local div = (-s2_x * s1_y) + (s1_x * s2_y) if div

How to find Intersections in two singly linked lists

|▌冷眼眸甩不掉的悲伤 提交于 2019-12-25 01:46:39
问题 I am writing an program in which i have to set up data structure dictionary(singly linked list) with words alphabetically ordered(words that appear in sentence in a text document with document ids). and find which words appear in more than one document so the professor wants us to do an intersection. I am really confused on how to do the intersection. I have everything else(Which I believe is correct). Here is my code(I have added my intersect algorithm, but it is clearly not working and I

Line intersections for diagonals on a 2d plane in C#

…衆ロ難τιáo~ 提交于 2019-12-24 19:23:48
问题 Assume a 2D grid with the top left cell as (0, 0). Pick any two points/coordinates and draw a diagonal and anti-diagonal on each. They may intersect inside or outside the grid. In the picture attached, the red lines are diagonals to the two points (300, 200) and (700, 800). How can I find out the coordinates for the diagonal intersections? Also, how would the formula differ if the slope of the line were negative? I will use this in an algorithm that needs to be highly optimized so the right