interrupt-handling

Do interrupts interrupt other interrupts on Arduino?

别等时光非礼了梦想. 提交于 2019-12-04 15:35:28
问题 I have an Arduino Uno (awesome little device!). It has two interrupts; let's call them 0 and 1 . I attach a handler to interrupt 0 and a different one to interrupt 1, using attachInterrupt() : http://www.arduino.cc/en/Reference/AttachInterrupt. Interrupt 0 is triggered and it calls its handler, which does some number crunching. If interrupt 0 's handler is still executing when interrupt 1 is triggered, what will happen? Will interrupt 1 interrupt interrupt 0 , or will interrupt 1 wait until

Should my interrupt handler disable interrupts or does the ARM processor do it automatically?

孤街醉人 提交于 2019-12-04 12:25:24
Our group is using a custom driver to interface four MAX3107 UARTs on a shared I2C bus. The interrupts of the four MAX3107's are connected (i.e. shared interrupt via logic or'ing)) to a GPIO pin on the ARM9 processor (LPC3180 module). When one or more of these devices interrupt, they pull the GPIO line, which is configured as a level-sensitive interrupt, low. My question concerns the need, or not, to disable the specific interrupt line in the handler code. (I should add that we are running Linux 2.6.10). Based on my reading of several ARM-specific app notes on interrupts, it seems that when

What happens when you disable interrupts, and what do you do with interrupts you don't know how to handle?

…衆ロ難τιáo~ 提交于 2019-12-04 11:39:58
问题 When you disable interrupts (with the cli instruction in x86), what exactly happens? Does the PIC wait for you to turn on interrupts, and fire the interrupt when that happens? (If so, how long does it wait, and what happens if the time 'expires'?) Does the interrupt -- from the device's perspective -- get sent into a "black hole", with no response? Does the PIC somehow tell the device that "the CPU is busy" or something? Or does something else happen? Also, how do you deal with an interrupt

Trigger Kernel Interrupt Handler: How?

和自甴很熟 提交于 2019-12-04 11:10:17
问题 I am trying to understand Asynchronous Interrupt handling in kernel, ofcourse through the legendary Understanding the Linux Kernel. In this process how and who will trigger Kernel Interrupt Handler? I would like some one to help me correcting this and to clarify my question on 1)How and Who trigger Kernel Interrupt Handler? 2)How to define new or change existing hardware interrupt handlers? Thank you in Advance! 回答1: This picture from Robert Love's "Linux Kernel Development" pretty well

Java Hardware Interrupt Handling

守給你的承諾、 提交于 2019-12-04 10:51:24
I would like to know if it is possible to automatically invoke a Java method when a hardware interrupt is raised. There may be an alternative. I'm doing something similar: In an application I monitor 4 mice for clicks. Those clicks generate interrupts but I'm happy enough not to deal with them directly from Java. Under Linux, it turns out there are device files ( /dev/input/mouse# ) that spew a bunch of characters when something happens with the mouse. I have a Thread for each one with a FileReader blocking on a read. Once characters arrive, the appertaining thread unblocks and I can do

interrupt() not working as expected (how does interrupt work?)

微笑、不失礼 提交于 2019-12-04 07:22:42
I want to interrupt a thread, but invoking interrupt() doesn't seem to work. Below is the sample code: public class BasicThreadrRunner { public static void main(String[] args) { Thread t1 = new Thread(new Basic(), "thread1"); t1.start(); Thread t3 = new Thread(new Basic(), "thread3"); Thread t4 = new Thread(new Basic(), "thread4"); t3.start(); t1.interrupt(); t4.start(); } } class Basic implements Runnable{ public void run(){ while(true) { System.out.println(Thread.currentThread().getName()); try { Thread.sleep(1000); } catch (InterruptedException e) { System.err.println("thread: " + Thread

Real mode Interrupt handling routine not working as expected

余生长醉 提交于 2019-12-04 04:36:15
问题 I managed to load a small kernel into memory via a bootloader that performs a far jump to 0x0090:0x0000 . The kernel is loaded successfully as I print a character from there to test it and it works properly. I wanted to remap interrupts 0x08->0x0F and 0x70->0x77 to interrupts 0x20->0x2F , so the exception/reserved interrupts are not overlapped. So far, I am only handling a keyboard press and attempting to print it to the screen. I went over it a bunch of times and for some reason, I just don

difference between software interrupt and signal

删除回忆录丶 提交于 2019-12-03 20:32:44
"Software interrupts are delivered using signals" Is this always true, if not then a) what is the difference between two If yes, is there some other mechanism, by which software interrupts are raised, other than delivering signals. The author of that quote appears to be using "Software interrupt" in a very general sense (i.e. "anything that causes a program to diverge from it's usual flow of operation and does not originate in hardware" ) and "signals" in the sense of a particular mechanism used by a particular operating system (probably unix derived). Yes its always true that software

What happens to preempted interrupt handler?

最后都变了- 提交于 2019-12-03 15:05:45
I could not find a proper answer for the following questions even in some well written kernel books: They are saying that an ISR can't sleep because its not possible to reschedule an ISR as it is not connected with any process , so what happens when a higher priority interrupt preempt the executing one? the interrupted ISR will not rescheduled(execute) again ? if yes how & who will do that work? many time we will disable interrupt (eg: 1.In critical region 2. When a fast interrupt is executing it will disable all the interrupt in the current processor) , so what will happen for the interrupts

How can I add a user interrupt to an infinite loop?

妖精的绣舞 提交于 2019-12-03 13:42:58
I have a ruby script below which infinitely prints numbers from 1 onward. How can I make the script stop its infinite execution through an interrupt in the terminal like 'Ctrl+C' or key 'q'? a = 0 while( a ) puts a a += 1 # the code should quit if an interrupt of a character is given end Through every iteration, no user input should be asked. I think you will have to check the exit condition in a separate thread: # check for exit condition Thread.new do loop do exit if gets.chomp == 'q' end end a = 0 loop do a += 1 puts a sleep 1 end BTW, you will have to enter q<Enter> to exit, as that's how