instantiation

Android SDK error: Trying instantiate a class that is not a fragment

独自空忆成欢 提交于 2019-12-03 06:09:37
I am hardly trying to create a simple application with a top menu and a changeable view below (by pressing the buttons in the menu fragment we change the view of the fragment below). So, I have 2 fragments inside the main view but when trying to run the application in the emulator I get an error like: Cause by android.app (bla bla bla, piece of crap Eclipse doesn't even allow copying the errors): Trying to instantiate a class com.example.android.topmenu that is not a fragment So, these are my XML layouts: main.xml <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http:/

java override during object creation

三世轮回 提交于 2019-12-03 05:57:13
问题 in the following java code a JButton is created but at the same time one of its methods gets overridden. Qestion: is there a name for overriding in this way while creating the object? the code: JButton myButton; myButton = new JButton ("ok"){ @Override public void setText(String text) { super.setText(text +", delete"); } the jbutton's label is now "ok, delete" 回答1: That's an anonymous class. From Java in a Nutshell An anonymous class is a local class without a name. An anonymous class is

Scala 2.10, its impact on JSON libraries and case class validation/creation

走远了吗. 提交于 2019-12-03 05:40:31
问题 In Scala 2.10 apparently we're getting improved reflection. How will this impact lift-json, jerkson, sjson and friends? Furthermore, can we expect in the not too distant future a built-in JSON language feature a la Groovy's excellent GSON in Scala? The reason I ask is that I would dearly love to do: case class Foo(a: String, b: Int, bar: Bar) case class Bar(c: Int) val foo = Foo("hey", 10, Bar(23)) val json = foo.toJson without hoop jumping (i.e. boilerplate-ish prep work), even with

How is a template instantiated?

梦想与她 提交于 2019-12-03 02:50:16
It's an exercise from C++ Primer 5th Edition : Exercise 16.27: For each labeled statement explain what, if any, instantiations happen. If a template is instantiated, explain why; if not, explain why not. P.677 template <typename T> class Stack { }; void f1(Stack<char>); // (a) class Exercise { Stack<double> &rsd; // (b) Stack<int> si; // (c) }; int main() { Stack<char> *sc; // (d) f1(*sc); // (e) int iObj = sizeof(Stack< string >); // (f) } Below is what I tried: (a) Stack<char> is instantiated , but no member of it is instantiated. (b) Stack<double> is instantiated , but no member of it is

How to instantiate class from name string in Rails?

依然范特西╮ 提交于 2019-12-03 02:34:38
问题 How we can instantiate class from it's name string in Ruby-on-Rails? For example we have it's name in database in format like "ClassName" or "my_super_class_name". How we can create object from it? Solution: Was looking for it myself, but not found, so here it is. Ruby-on-Rails API Method name = "ClassName" instance = name.constantize.new It can be even not formatted, we can user string method .classify name = "my_super_class" instance = name.classify.constantize.new Of course maybe this is

The impact of virtual on the use of member of class template

送分小仙女□ 提交于 2019-12-03 02:34:02
I (vaguely) know that a template is not instantiated if it is not used . For example, the following code will compile fine even though T::type doesn't make sense when T = int . template<typename T> struct A { void f() { using type = typename T::type; } }; A<int> a; //ok It compiles because f() is not used , so it is not instantiated — thus the validity of T::type remains unchecked. It doesn't matter if some other member function g() calls f() . template<typename T> struct A { void f() { using type = typename T::type; } void g() { f(); } //Is f() still unused? }; A<int> a; //ok This also

Can I use methods of a class without instantiating this class?

假装没事ソ 提交于 2019-12-03 01:22:24
I have a class with several methods and there is no constructor among these methods. So, I am wondering if it is possible to call a method of a class without a creation of an instance of the class. For example, I can do something like that: NameOfClass.doMethod(x1,x2,...,xn) In general I do not see why it should be impossible. I just call a function which does something (or return some values). If it is possible, what will happen if the method sets a value for a private variable of the class. How can I reach this value? In the same way? NameOfClass.nameOfVariable It's called static variables

Unity 5 An object reference is required for the non-static field, method, or property error

邮差的信 提交于 2019-12-03 00:11:09
问题 In Unity 5 using c# on line 35 of my PlayerMovement class I have this error: Error CS0120 An object reference is required for the non-static field, method, or property 'GameManager.completeLevel()' PlayerMovement Class: using System.Collections; using System.Collections.Generic; using UnityEngine; public class PlayerMovement : MonoBehaviour { public GameObject deathParticals; public float moveSpeed; private Vector3 spawn; // Use this for initialization void Start () { spawn = transform

Instantiate an Interface [duplicate]

爷,独闯天下 提交于 2019-12-02 23:41:30
问题 This question already has answers here : What does it mean to “program to an interface”? (31 answers) Initializing an Interface? (2 answers) Closed 5 years ago . Extending the question asked in Initializing an Interface? , we do instantiate an Interface while initialize it with implemented class. My question is why in the first place, we are instantiate it with the Interface? Why can't I directly instantiate it with implemented class? For eg. : Doc mydoc = new SimpleDoc(); Where Doc is

Different ways of constructing an object in C++

自作多情 提交于 2019-12-02 23:20:22
I want to construct an object in the stack, using C++. Do you know what is the difference between these to ways of calling the constructor (with and without parenthesis): a) MyClass object ; b) MyClass object() ; I am using MFC and when constructing the global variable for the main app, if I use the latter way, I get an exception, I thought these two ways were equivalent. Thank you guys for any information. LeopardSkinPillBoxHat This is one of those gotchas of C++. MyClass object(); is the way that a function prototype is defined in C++, so the compiler thinks you are trying to declare another