instance

I Have this class: class Bowler: def __init__(self, name, score): self.name = name self.score = score def nameScore(self): return '{} {}'.format(self.name, self.score) I need to get user input until a blank line is entered. Then use the data I got to create instances of a class. I was thinking something like: def getData(): name, score = input("Please enter your credentails (Name score): ").split() B1 = Bowler(name, score) print(B1.nameScore()) But then I would somehow have to loop it until I get a blank user input. Also I would somehow have to create B2 B3 B4 etc in the loop. Sorry I am still

I have a static inner class, in which I want to use the outer class's instance variable. Currently, I have to use it in this format "Outerclass.this.instanceVariable", this looks so odd, is there any easier way to access the instance field of the outer class? Public class Outer { private int x; private int y; private static class Inner implements Comparator<Point> { int xCoordinate = Outer.this.x; // any easier way to access outer x ? } } A static nested class cannot reference the outer class instance because it's static , there is no related outer class instance. If you want a static nested

In using Vaadin Flow, version 14, I know we can store state as key-value pairs kept as "attributes" via getAttribute / setAttribute / removeAttribute methods found on: VaadinSession (per-user scope) VaadinContext (web-app scope) How does one access the current object for those classes? VaadinSession.getCurrent() For that per-user scope , the VaadinSesion class provides a static class method getCurrent to access the current instance. VaadinSession session = VaadinSession.getCurrent() ; // Fetch current instance of `VaadinSession` to use its key-value collection of attributes. session

I have this code on Visual C++ 2010 #include <iostream> #include <string> using namespace std; class Human { private: int magic; int health; string name; public: int GetMagic() const; int GetHealth() const; Human(int, string); ~Human(); }; //helper int Human::GetHealth() const { cout <<"This returns Human::health" << endl; return Human::health; } int Human::GetMagic() const { cout <<"This returns this->magic"<< endl; return this->magic; } //con/destructor Human::Human(int a, int b, string c): health(a), magic(b), name(c) { cout<<c<<" is born!"<<endl; } Human::~Human() { cout <<this->name << "

Hi could someone please explain to me why you have to create an instance before calling a non static method to the main function in java? What is the reasoning behind this? Because, they are instance members,to access them you need instance. When a number of objects are created from the same class blueprint, they each have their own distinct copies of instance variables. In the case of the Bicycle class, the instance variables are cadence, gear, and speed. Each Bicycle object has its own values for these variables, stored in different memory locations. So now your second question about static

I'm collecting instances using the following code: class Hand(): instances = [] def __init__(self): Hand.instances.append(self) self.value = 5 def do_something(self, a): self.value = self.value * a class Foo(): def __init__(self): pass def insty(self): self.hand1 = Hand() self.hand2 = Hand() foo = Foo() foo.insty() print Hand.instances for hand in Hand.instances: print "how do I print the instance name?" The last line is just a way to learn how to to access the instance name so i can call the 'do_something' method on each instance in order. How do I access the instance name for each instance

This is a snippet of Java code: static { ture = 9; } static int ture; { // instance block System.out.println(":"+ture+":"); } How is that it compiles at all? Declaration of variable 'ture' has been performed after initialization. As far as I know static blocks and fields have been executed in the order they appear. And now why is that value 9 within instance block has been printed 3 times? By the way, the instance of the class has been created 3 times. That is not a homework, I am learning Java for certification. T.J. Crowder Regarding your first question, static blocks are indeed processed in