inline

shadowbox - open inline element

霸气de小男生 提交于 2019-12-23 23:16:24
问题 I am using shadowbox and jQuery. I have it opening on page load fine. What I want to do is. Have the shadowbox open up and show a form where the user can enter their email address. I then want to submit said form via ajax. I am dumping the form on the page wrapped in a hidden div with the id of #dialog . My question is. How can I get the shadowbox to be opened automatically with an inline element? 回答1: Use the Shadowbox.open method. Shadowbox.open({ content: '<div id="welcome-msg">Welcome to

Identity of function template instantiation in multiple translation units

↘锁芯ラ 提交于 2019-12-23 22:25:34
问题 According to cppref, the identity characteristics of inline functions in multiple translation units are as follows: ... 2) It has the same address in every translation unit. 3) Function-local static objects in all function definitions are shared across all translation units (they all refer to the same object defined in one translation unit) ... Simply speaking, a singleton identity is implied. I'm wondering whether the same applies to function template instantiations without the inline

When lambda parameters must be noinline in Kotlin?

岁酱吖の 提交于 2019-12-23 19:42:16
问题 I often encounter errors in Kotlin inlined functions where lambda parameters must be marked noinline . Other times, lambda parameters seem to work OK. I've read the Kotlin documentation of inline functions, and it seems like this is the operative passage explaining the rule: Inlinable lambdas can only be called inside the inline functions or passed as inlinable arguments, but noinline ones can be manipulated in any way we like: stored in fields, passed around etc. I'm having trouble unpacking

ARM + gcc: don't use one big .rodata section

对着背影说爱祢 提交于 2019-12-23 19:40:50
问题 I want to compile a program with gcc with link time optimization for an ARM processor. When I compile without LTO, the system gets compiled. When I enable LTO (with -flto), I get the following assembler-error: Error: invalid literal constant: pool needs to be closer Looking around the web I found out that this has something to do with the constants in my system, which are placed in a special section called .rodata, which is called a constant pool and is placed right after the .text section in

Why is inline script forbidden (Content Security Policy)?

懵懂的女人 提交于 2019-12-23 14:19:55
问题 i'am wondering about the quote from the specification: (https://dvcs.w3.org/hg/content-security-policy/raw-file/tip/csp-specification.dev.html) To reap the greatest benefit, authors will need to move all inline script and style out-of-line, for example into external scripts, because the user agent cannot determine whether an inline script was injected by an attacker. Sourcing out all inline-script is a time heavy task. My question is from the security point of view. Do you really get any

g++ doesn't inline functions

人盡茶涼 提交于 2019-12-23 14:11:16
问题 There is such code: int fun1(){ return 2 + 3; } inline int fun2(){ return 4 + 5; } int main(){ int a = fun1(); int b = fun2(); return 0; } and corresponding assembly code: .file "prog47.cpp" .text .globl _Z4fun1v .type _Z4fun1v, @function _Z4fun1v: .LFB0: .cfi_startproc .cfi_personality 0x0,__gxx_personality_v0 pushl %ebp .cfi_def_cfa_offset 8 movl %esp, %ebp .cfi_offset 5, -8 .cfi_def_cfa_register 5 movl $5, %eax popl %ebp ret .cfi_endproc .LFE0: .size _Z4fun1v, .-_Z4fun1v .section .text.

final methods are inlined?

女生的网名这么多〃 提交于 2019-12-23 12:12:57
问题 Are Java final methods automatically inlined? Many books says yes many books says no!!! 回答1: Interesting question, prompted me to look into it further. 2 interesting remarks I found - 1 comment that automatic inlining is a bug: Contrary to the implication of many tips, methods declared as final cannot be safely inlined by the compiler, because the method could have a non-final declaration at runtime. To see why, suppose the compiler looks at class A and subclass B, and sub-subclass C and sees

Python: Inline if statement else do nothing

此生再无相见时 提交于 2019-12-23 11:41:23
问题 Assigning a Django Model's field to a value if it matches a condition. g = Car.objects.get(pk=1234) g.data_version = my_dict['dataVersion'] if my_dict else expression_false # Do nothing?? How do I do nothing in that case? We can't do if conditional else pass . I know I can do: if my_dict: g.data_version = my_dict['dataVersion'] but I was wondering if there was a way to do inline expression_true if conditional else do nothing . 回答1: No, you can't do exactly what you are describing, as it

What do “the mustinline value … was not inferred to have a known value” and “marked inline but not bound in the optimization environment” mean?

六月ゝ 毕业季﹏ 提交于 2019-12-23 11:36:17
问题 I have run into a compile-time error I do not understand while working with F# in Visual Studio 2012. I could find a minimal snippet here: http://ideone.com/hbhbF type Foo() = inherit System.Exception() member inline this.Bar() = () Foo().Bar() What do the following error messages mean? /home/iU0RLi/prog.fs(3,22): error FS0073: internal error: the mustinline value 'Bar' was not inferred to have a known value /home/iU0RLi/prog.fs(5,1): error FS1114: The value 'Prog.Foo.Bar' was marked inline

Generic zero for generic function

旧城冷巷雨未停 提交于 2019-12-23 09:59:53
问题 I have a function to calculate the cumulated sum of a sequence. let cumsum<'T> = Seq.scan (+) 0 >> Seq.skip 1 >> Seq.toArray Though it looks generic, the integer 0 makes it non-generic, and thus I cannot call the function with a sequence of floats. Is there a generic zero that can replace my hardcoded 0 , or maybe a different way of making the function generic. 回答1: You can use the GenericZero primitive but you need to make your function inline and make it explicitly a function (right now