increment

问题 In JavaScript you can use ++ operator before ( pre-increment ) or after the variable name ( post-increment ). What, if any, are the differences between these ways of incrementing a variable? 回答1: Same as in other languages: ++x (pre-increment) means "increment the variable; the value of the expression is the final value" x++ (post-increment) means "remember the original value, then increment the variable; the value of the expression is the original value" Now when used as a standalone

问题 From Ira Baxter answer on, Why do the INC and DEC instructions not affect the Carry Flag (CF)? Mostly, I stay away from INC and DEC now, because they do partial condition code updates, and this can cause funny stalls in the pipeline, and ADD / SUB don\'t. So where it doesn\'t matter (most places), I use ADD / SUB to avoid the stalls. I use INC / DEC only when keeping the code small matters, e.g., fitting in a cache line where the size of one or two instructions makes enough difference to

问题 Is there a difference between ++x and x++ in java? 回答1: ++x is called preincrement while x++ is called postincrement. int x = 5, y = 5; System.out.println(++x); // outputs 6 System.out.println(x); // outputs 6 System.out.println(y++); // outputs 5 System.out.println(y); // outputs 6 回答2: yes ++x increments the value of x and then returns x x++ returns the value of x and then increments example: x=0; a=++x; b=x++; after the code is run both a and b will be 1 but x will be 2. 回答3: These are

问题 #include <stdio.h> int main(void) { int i = 0; i = i++ + ++i; printf(\"%d\\n\", i); // 3 i = 1; i = (i++); printf(\"%d\\n\", i); // 2 Should be 1, no ? volatile int u = 0; u = u++ + ++u; printf(\"%d\\n\", u); // 1 u = 1; u = (u++); printf(\"%d\\n\", u); // 2 Should also be one, no ? register int v = 0; v = v++ + ++v; printf(\"%d\\n\", v); // 3 (Should be the same as u ?) int w = 0; printf(\"%d %d\\n\", ++w, w); // shouldn\'t this print 1 1 int x[2] = { 5, 8 }, y = 0; x[y] = y ++; printf(\"%d