increment

Java increment and assignment operator

由 微笑、不失礼 提交于 2019-11-27 08:41:18
I am confused about the post ++ and pre ++ operator , for example in the following code int x = 10; x = x++; sysout(x); will print 10 ? It prints 10,but I expected it should print 11 but when I do x = ++x; instead of x = x++; it will print eleven as I expected , so why does x = x++; doesn't change the the value of x ? No, the printout of 10 is correct. The key to understanding the reason behind the result is the difference between pre-increment ++x and post-increment x++ compound assignments. When you use pre-increment, the value of the expression is taken after performing the increment. When

Changing the value of something in a function

由 北城余情 提交于 2019-11-27 08:30:52
问题 This is a test case for something larger, which is why it is written the way is. How could I make this bit of code so that a's value would keep incrementing? In my project I call a function that parses a line from a file. I need to set values of a struct to certain values that were set in the function call (the parameters of the function were initialized in the main function, like the code below). int increment(int a) { a++; return 0; } int main() { int a =0; int b =0; while( b<5){ increment

Increment behavior on strings - PHP easter egg?

由 耗尽温柔 提交于 2019-11-27 07:49:10
问题 $var = 'test_1'; var_dump(++$var); // string(6) "test_2" $var2 = '1_test'; var_dump(++$var2); // string(6) "1_tesu" $var3 = 'test_z'; var_dump(++$var3); // string(6) "test_a" $var4 = 'test_'; var_dump(++$var4); // string(5) "test_" So apparently, using an increment operator on a string has the effect of increasing the digit if the last character is a number, increasing the letter and then resetting to a once z if the last character is in the alphabet, and has no effect on non alpha numeric

Post Increment Infinite loop i += i++; [duplicate]

由 前提是你 提交于 2019-11-27 07:39:32
问题 This question already has answers here : Why does this expression i+=i++ differs from Java and C? (8 answers) Closed 2 years ago . I am not understanding why this post increment equation does not increase. I would have thought that after the += operation the value would increment by 1 and then the second time around i would have a 1 value. But the output is an infinite loop of 0 zero. Is anyone able to explain why 'i' doesn't increase. int i = 0; for(; ; ) { if ( i >= 10) break; i += i++; }

Increment the name of variable

由 ＊爱你＆永不变心＊ 提交于 2019-11-27 07:33:09
问题 Basically I want to increment the name of the variable. What is the correct syntax to do this? for (i=0; i<5; i++) { eval("var slider_" + i); var slider_+i = function(){ //some code } dojo.addOnLoad(slider_+i); 回答1: Why not just use an array? var slider = []; for (i=0; i<5; i++) { slider[i] = function(){ //some code } dojo.addOnLoad(slider[i]); } Alternatively, you could access them based on the object they are contained within. Assuming they are global variables (hopefully not): for (i=0; i

Vim - incremental numbering via regular expression search and replace

由 谁说胖子不能爱 提交于 2019-11-27 07:31:11
问题 I have this code: array ('id' => 1, 'name' => "Murka", 'date_of_birth' => "2014-10-31", "breed_id" => 1), array ('id' => 1, 'name' => "Jurka", 'date_of_birth' => "2014-11-31", "breed_id" => 2), array ('id' => 1, 'name' => "Nyash", 'date_of_birth' => "2014-12-31", "breed_id" => 3), array ('id' => 1, 'name' => "Meowy", 'date_of_birth' => "2014-01-31", "breed_id" => 4), array ('id' => 1, 'name' => "Yummi", 'date_of_birth' => "2014-10-31", "breed_id" => 2), array ('id' => 1, 'name' => "Barss",

Obj-C -> Incrementing a number (and showing steps on a Cocoa label)

由 纵饮孤独 提交于 2019-11-27 07:16:21
问题 I'm new with Objective-C, so there probably is a simple solution to this. I want a number to increment, but each iteration to be show on a label. (for example, it shows 1, 2, 3, 4, 5... displayed apart by an amount of time). I tried: #import "testNums.h" @implementation testNums - (IBAction)start:(id)sender { int i; for(i = 0; i < 10; ++i) { [outputNum setIntValue:i]; sleep(1); } } @end and all it did was wait for 9 seconds (apparently frozen) and then displayed 9 in the text box. 回答1: To

Is incrementing a field in MySQL atomic?

由 落爺英雄遲暮 提交于 2019-11-27 07:14:13
I'm making a web site where I would like to increment a counter in a standard MyISAM table. Simplified example: UPDATE votes SET num = num + 1; Will this cause problems if multiple connections are doing the same query, or will MySQL take care of it and lock the table or something to make sure that there are no conflicts? MyISAM tables use table level locking. This means that the whole table will be locked during the execution of your update query. So the answer for your simplified use case is: yes, this is thread safe. But this may not be the case if you use another storage engine or your

bool operator ++ and --

由 Deadly 提交于 2019-11-27 06:38:59
Today while writing some Visual C++ code I have come across something which has surprised me. It seems C++ supports ++ (increment) for bool, but not -- (decrement). It this just a random decision, or there is some reason behind this? This compiles: static HMODULE hMod = NULL; static bool once = false; if (!once++) hMod = LoadLibrary("xxx"); This does not: static HMODULE hMod = NULL; static bool once = true; if (once--) hMod = LoadLibrary("xxx"); Jon Hanna It comes from the history of using integer values as booleans. If x is an int , but I am using it as a boolean as per if(x)... then

C++ : List iterator not incrementable

由 你说的曾经没有我的故事 提交于 2019-11-27 06:18:28
问题 Getting this error while trying to erase the last element of a list. I debugged the code and was able to figure out what causes it and where, here's my code: for(Drop_List_t::iterator i = Drop_System.begin(); i != Drop_System.end() && !Drop_System_Disable; /**/) { if(Player->BoundingBox.Intersect(&(*i)->BoundingBox)) { i = Drop_System.erase(i); } ++i; //List iterator crashes here if last entry was deleted } I can't figure out what I'm doing wrong... Any suggestions? 回答1: Your algorithm is
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