increment

This is a test case for something larger, which is why it is written the way is. How could I make this bit of code so that a's value would keep incrementing? In my project I call a function that parses a line from a file. I need to set values of a struct to certain values that were set in the function call (the parameters of the function were initialized in the main function, like the code below). int increment(int a) { a++; return 0; } int main() { int a =0; int b =0; while( b<5){ increment(a); b++; cout << "a is: " << a << ". And b is: " << b << "\n"; } system("PAUSE"); } Thanks. Pass its

$var = 'test_1'; var_dump(++$var); // string(6) "test_2" $var2 = '1_test'; var_dump(++$var2); // string(6) "1_tesu" $var3 = 'test_z'; var_dump(++$var3); // string(6) "test_a" $var4 = 'test_'; var_dump(++$var4); // string(5) "test_" So apparently, using an increment operator on a string has the effect of increasing the digit if the last character is a number, increasing the letter and then resetting to a once z if the last character is in the alphabet, and has no effect on non alpha numeric characters. Is this a standard feature, expected in many scripting languages, or did I just find a PHP

This question already has an answer here: Why does this expression i+=i++ differs from Java and C? 8 answers I am not understanding why this post increment equation does not increase. I would have thought that after the += operation the value would increment by 1 and then the second time around i would have a 1 value. But the output is an infinite loop of 0 zero. Is anyone able to explain why 'i' doesn't increase. int i = 0; for(; ; ) { if ( i >= 10) break; i += i++; } System.out.println(i); While the answer from @njzk2 is correct, it is useful to point out why it is correct. There are other

I have this code: array ('id' => 1, 'name' => "Murka", 'date_of_birth' => "2014-10-31", "breed_id" => 1), array ('id' => 1, 'name' => "Jurka", 'date_of_birth' => "2014-11-31", "breed_id" => 2), array ('id' => 1, 'name' => "Nyash", 'date_of_birth' => "2014-12-31", "breed_id" => 3), array ('id' => 1, 'name' => "Meowy", 'date_of_birth' => "2014-01-31", "breed_id" => 4), array ('id' => 1, 'name' => "Yummi", 'date_of_birth' => "2014-10-31", "breed_id" => 2), array ('id' => 1, 'name' => "Barss", 'date_of_birth' => "2014-05-31", "breed_id" => 2), array ('id' => 1, 'name' => "Nonam", 'date_of_birth' =

I have an app that takes a Timestamp as a boundary for the start date and end date of a sql selection, I want to populate a hashmap with weeks this year since the first monday of the year as the values and the week number as the keys. I'm finding it really hard to work with timestamps and I don't feel very good about adding 86,400,000 seconds to it to increment the day, as this doesn't account for the leap days, hours, seconds. I plan on adding 13 days 23 hours, 59 minutes and 59 seconds to it so that I can lookup the start date in the map by the week as the key, then use the start date to get

I need to increment an integer in a SQL Server 2008 column. Sounds like I should use an IDENTITY column, but I need to increment separate counters for each of my customers. Think of an e-commerce site where each customer gets their own incrementing order number, starting with 1. The values must be unique (per customer). For example, Customer1 (Order #s 1,2,3,4,5...) Customer2 (Order #s 1,2,3,4,5...) Essentially, I will need to manually do the work of SQL's identity function since the number of customers is unlimited and I need order # counters for each of them. I am quite comfortable doing: