increment

问题 So I declare a variable some where and initialize it. Now later on I need to use it to loop while its still positive so I need to decrement it. To me looping using a condition and a decrement calls for a for but for it we are missing the first part the initialization. But I don't need to initialize anything. So how do I go about that in a nice way. for (space = space; space > 0; space--)//my first way to do it but ide doesnt like it Second way: for (; space > 0; space--)//my friend

问题 My problem looks as follows: I want to make a vote app where People can choose one or more Events(like Doodle). For this I have set up a function called vote. In the View you can choose the Events using checkboxes. The Models are Poll and Groupevent. A Poll has Many Groupevents. My Problem is when I call updateAll() , all values of the associated Groupevents are incremented. Here is my code: View: echo $this->Form->create('Poll', array('action' => 'vote')); for($i=0; $i<$count; $i++){ echo

问题 I'm working on an Excel spreadsheet, and I have to use only one type of formula for a huge amount of data. Since in the formula the only necessary changes concern letters, I was wondering if there is a way to make a program that increments them following the Excel columns order (A, B, C...Z; AA, AB, AC...AZ; BA, BB, BC...BZ). In my case, I would need to increment letters each time by five, so here is the kind of code I'm trying to obtain: #include <iostream> using namespace std; int main() {

问题 Consider the following code: for (float i = 0f; i < int.MaxValue; i++) { // Some code } Which is supposed to loop from 0 to int.MaxValue (2 31 -1), but it doesn't. Once i reached 2 24 , i++ doesn't work anymore for a reason that I'm totally unable to understand. In the Immediate Window of VS I've try this: >i 16777216.0 >i + 1 16777216.0 // ??? >i == i + 1 false // as expected, but a lack of consistency with upper statement >i + 2 16777218.0 Why does it behave like so? What is special with 2

问题 I have a version number 17.06.01.01 and I would like to know how many entries there are split by a period. My last piece of code was; setlocal ENABLEDELAYEDEXPANSION for /F "tokens=1-10 delims=." %%a in ("17.09.01.04.03") do ( set /a "iCount+=1" echo %%a, !iCount! ) endlocal I've tried a host of 'For' commands but seem to be getting further away each time. 回答1: replace every dot with a space (as a delimiter). Then count number of tokens: @echo off set "string=17.09.01.04.03" set count=0 for %

问题 I have a number (e.g. 6) that is dynamically generated and I would like to fill an array with the numbers 1 through the dynamically generated number (in this example, 6): array(1, 2, 3, 4, 5, 6); The only way I know to do this at the moment is by using a for loop, but I'm wondering if there's a better way, something similar to array_fill . I looked at array_fill, but it doesn't look like it will take a number and increment it for a set number of times. 回答1: Use range: $arr = range(1,6); //

问题 I've been trying to find a function which increments a counter using words. I know its possible using numbers with suffixes (i.e. 1st, 2nd, 3rd and so on). Here is a snippet of the code i've got: function addOrdinalNumberSuffix($num) { if (!in_array(($num % 100),array(11,12,13))){ switch ($num % 10) { // Handle 1st, 2nd, 3rd case 1: return $num.'st'; case 2: return $num.'nd'; case 3: return $num.'rd'; } } return $num.'th'; } Code Source But is there a way to replicate this with words (i.e

问题 Confusion with ++ and -- operator int a = 10; printf("%d\n", -(--a) ); // valid output: -9 But, problem occurs when following is used: printf("%d\n", --(-a)); // error, invalid Why? 回答1: The ++ and -- operator works on only lvalue, not value. An lvalue is something that can stand on the left side of an assignment. printf("%d\n", -(--a) ); Here, -- operator works on variable a , so this is valid. But, printf("%d\n", --(-a)); Here, (-a) returns a value. -- is applied to a value, which is not

问题 I accidentally wrote: total_acc =+ accuracy instead of: total_acc += accuracy I searched the net and could not find anything. So what happened, why does Python think I mean what I am typing? Computers trust us too much. :) 回答1: This is the same as if you were to do like total_acc = -accuracy , except positive instead of negative. It basically is the same as total_acc = accuracy though, as adding a + before a value does not change it. This is called an unary operator as there is only one

问题 I have a question about CountDownTimer. I have to make an application that allows the user to increment the time time by +1, for every click of the button. Then after the button stops being clicked it waits for three seconds, then starts to countdown. I pasted my code below. My Issue is: I can't seem to get the Incrementing of the number working correctly, however it seems that after I stop Incrementing the number (onStop()) it directly goes to (onFinish()). Instead of going to the OnTick()