if-statement

问题 In part of my program, I have the code: if(cameraName == L"AVT Prosilica GT2750") { mCamera = new camera_avtcam_ex_t(); } else if(cameraName == L"QImaging Retiga 2000R\\4000R") { mCamera = new camera_qcam_ex_t(); } When I have set up my program so that cameraName defaults to L"AVT Prosilica GT2750" (and my debugger will show this to be its value), it goes into the if statement and runs mCamera = new camera_avtcam_ex_t(); , but then when I step to the next executed line my debugger skips

问题 Context For quite a lot of our CentOS servers I would like to install some monitoring software, the software is based on the CentOS version, I want to check the release version and install software based on that. Issue It seems that the if statements are run successfully without errors while the results never should be true for both or all three if statements. I've looked into the if commands and the tests, it seems that I should use double brackets and single = symbol in bash. I believe that

问题 I have different functions for square matrix multiplication depending on matrix size which varies from 8x8 through 20x20. The functions differ from each other because each employ different strategies for optimization, namely, different loop permutations and different loop unroll factors. Matrix size is invariant during the life of a program. My goal is to reduce the time to decide which function must be used. For example, a naive implementation is: if (matrixSize == 8) C = mxm8(A, B); else if

问题 For the following Rust program: fn main() { let foo = "test".to_string(); if false { let _bar = foo; // value moved to _bar } println!("{}", foo); } I got this error when run it: error[E0382]: borrow of moved value: `foo` --> src\main.rs:6:20 | 2 | let foo = "test".to_string(); | --- move occurs because `foo` has type `std::string::String`, which does not implement the `Copy` trait 3 | if false { 4 | let _bar = foo; // value moved to _bar | --- value moved here 5 | } 6 | println!("{}", foo);

问题 I'm trying to create a simple stored procedure with an if else statement in SQLYog against a mySql db. I'm not overly familiar with mySql syntax so i'm hoping it's something simple but I just can't see why this isn't working CREATE PROCEDURE p(IN Number INT) IF NUMBER = 1 THEN SELECT * FROM tblProduct WHERE ProductID = Number ELSE SELECT * FROM tblProduct WHERE ProductId = 2 END IF I'd appreciate if anyone can help me with this and tell me where i'm going wrong. Thanks for reading. I get the

问题 If we are having an array of about 1000-2000 elements, and a mysql table of about 1000-2000 (can increase). We have to find that table content is in array or not. Which is a better approach? Getting an element from array and run simple mysql query like SELECT *...... WHERE..... (Running 1-2k sql queries) Get the table stored in mysql in other array and check it's element with other. i.e. nested for-loop type. (Running 1 sql query and then 1-2k condition checks) 回答1: The obvious answer is: try

问题 I am trying to learn Python lists. In this code I am trying to add a string s coming from a form to table row as long as the string is the same. When the string is different; the new string is written to the next column. I could write the string from column 0 to column 1 but I had problems adding the same string on column 1 correctly. The way it is; the script works only up to placing the different string to the next column. I realize that this is not the right way of doing this. I would

问题 I have spent a few hours working out how to do this which is why im posting it here now... If you want to return different values in a cell based on which range the value entered in another cell comes under then I have worked out how to do it!! (bear in mind that this is specific to my spreadsheet and was for calculating prices i.e. 0.99 = £0.99) For example: IF G2 is ABOVE "0" BUT BELOW "1" THEN display "0.1" IF G2 is ABOVE "0.99" BUT BELOW "5" THEN display "0.15" IF G2 is ABOVE "4.99" BUT

问题 I have spent a few hours working out how to do this which is why im posting it here now... If you want to return different values in a cell based on which range the value entered in another cell comes under then I have worked out how to do it!! (bear in mind that this is specific to my spreadsheet and was for calculating prices i.e. 0.99 = £0.99) For example: IF G2 is ABOVE "0" BUT BELOW "1" THEN display "0.1" IF G2 is ABOVE "0.99" BUT BELOW "5" THEN display "0.15" IF G2 is ABOVE "4.99" BUT

问题 I have written code that uses the fgets function with multiple conditions that call other functions within the code, namely aMethod and bMethod. int main(void) { char buffer[1024]; while (fgets(buffer, 1024, stdin)) { if ((strcasecmp(buffer,"a")) == 0) { aMethod(); } if ((strcasecmp(buffer, "b")) == 0) { bMethod(); } } } I'm not sure why it doesn't reach the if statements. Any help would be great, thankyou. 回答1: If in doubt, print it out: int main(void) { char buffer[1024]; while (fgets