if-statement

Multiple conditions in if statement (Liquid)

会有一股神秘感。 提交于 2020-01-06 05:47:09
问题 Is it possible to put multiple conditions inside a single if statement in Shopify Liquid? For example this is what I have: {% if product.type != "A" and product.type != "B" and product.type != "C" %} //do something {% endif %} The reason I'm wondering is because syntax highlighting stops after the first "and" operator , as if everything after that has incorrect syntax. 回答1: Your syntax is 100% valid and will work in Shopify {% if product.type != "A" and product.type != "B" and product.type !=

VBA If Statement within For Each for Emulation

安稳与你 提交于 2020-01-06 05:35:23
问题 I need to update several thousand X coordinates in BlueZone. I'm using VBA to enter key commands in BlueZone VT. Unfortunately, there is no "set cursor position" command, so I am limited to using "tabs" to put the cursor where it needs to go. At the coordinate updating screen there are two possibilities: 6 or 7 tabs depending on the presence of a 0 or not on the screen. For example: location 241054 has a 1 and needs 7 tabs, location 241051 has a 0 and needs 6 tabs to get to the X location

xslt replaces attribute's value correctly, but also empties other attributes

耗尽温柔 提交于 2020-01-06 05:26:29
问题 i'm using xslt 1.0, below is my xml file. I would like to update value of attribute code to "Chao" if code="Hello". I wrote a little script, it does update code="Hello" to code="Chao"; however, it also empties other code attribute. can you please help? **XML <Items> <Item itemIdentifier="07068283" code="Hello" /> <Item itemIdentifier="07059182" code="Hello" /> <Item itemIdentifier="07063805" code="Bye" /> <Item itemIdentifier="07064878" code="Bye" /> </Items> CODE** <xsl:stylesheet version="1

Python Tkinter Button with If Else statements

泪湿孤枕 提交于 2020-01-06 04:42:43
问题 I want to bind the Start_Button with 2 possible functions: If Choice_1_Button is clicked and then the Start_Button , the Start_Button should call foo1 . But when the user clicks Choice_2_Button then the same Start Button should call foo2 . Here is the code I currently have: from tkinter import * root=Tk() Choice_1_Button=Button(root, text='Choice 1', command=something) #what should it do? Choice_2_Button=Button(root, text='Choice 2', command=something_else) Start_Button=Button(root, text=

Select from 2 tables. Query = table1 OR table1 + table2

痞子三分冷 提交于 2020-01-06 04:04:23
问题 I have 2 tables with a 1:1 relation. I'm trying to select everything from table1 and table2 using PK from table1. I want to select everything from table1 and, IF table1 PK = table2 FK THEN (and, only THEN) select from table2. To make it short, I want to select from table1 even if the query result doesn't have any relation in table2. If it has, then select from table2 as well. Anyone know how to do this? 回答1: It's a left outer join select table1.*, table2.* from table1 left outer join table2

Shortened method to reduce statements in an Ada procedure?

心已入冬 提交于 2020-01-06 03:37:05
问题 I am creating a procedure that uses an if statement to perform a decision. I have four variables: Altitude , Velocity , Angle and Temperature . The procedure is as follows: procedure Test3 is begin if (Integer(Status_System.Altitude_Measured)) >= Critical_Altitude and (Integer(Status_System.Velocity_Measured)) >= Critical_Velocity and (Integer(Status_System.Angle_Measured)) >= Critical_Angle and (Integer(Status_System.Temperature_Measured)) >= Critical_Temperature then DT_Put ("message 1");

if statement with dates in R - generalizing per year

。_饼干妹妹 提交于 2020-01-06 03:08:06
问题 I start from the following question to seek generalization properties: if statement with dates in R df <- data.frame(date = as.Date(c("16.04.2015", "04.08.2014", "11.09.2013", "20.11.2015", "04.04.2014"), '%d.%m.%Y')) I want to identify all the dates between 07-15 (%m-%d) and 12-31, e.g. > date value > 16.04.2015 0 > 04.08.2014 1 > 11.09.2013 1 > 20.11.2015 1 > 04.04.2014 0 My solution is based on a solution by @rawr posted in the above question: Function for the interval: `%between%` <-

Python: If-else statements

梦想的初衷 提交于 2020-01-06 01:22:10
问题 The following piece of code is showing an error: if ((type(varA) or type(varB) ) == type('t')): print "string involved" elif varA<varB: print "RANDOM" the error is for this case: Test Values: varA = 0, varB = adios output: RANDOM while this other piece of code if ((type(varA) == type('t')) or (type(varB)== type('t'))): print "string involved" elif varA<varB: print "RANDOM"` For the following test values: Test Values: varA = 6, varB = adios ouput is as follows: string involved What is the

no hit on if-statement

旧城冷巷雨未停 提交于 2020-01-05 19:05:41
问题 I am trying to get a hit on my if-statement. I fetch qDiff (integer32) from the Core Data db and everything works except get a hit on the if-statements: NSString *diff; NSArray *fetchedObjects = [qContext executeFetchRequest:fetchRequest error:&error]; for (NSManagedObject *info in fetchedObjects) { NSLog(@"idQ: %@", [info valueForKey:@"idQ"]); NSLog(@"qDiff: %@", [info valueForKey:@"qDiff"]); //<<<<<<<<<Print correct number diff = [info valueForKey:@"qDiff"]; NSLog(@"diff: %@", diff); //<<<<

How to analyze a string in java to make sure that it has both letters and numbers? [closed]

房东的猫 提交于 2020-01-05 18:42:11
问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 6 years ago . I need to analyze a string in JAVA to find out if it has both letters and numbers. So this is what I have so far. The variable pass is a String of maximum 8 characters/numbers that is inputted by the user. if