if-statement

问题 I am a noob at programming. I just wanted to ask what is wrong with the following code: scanf("%i", &battlechoice); printf("BCHOICE WAS:%i\n", battlechoice); if (battlechoice=4) //fleeing { fleechance=rand() % 100; if (fleechance <= 49) { printf("You attempt to flee...\n"); sleep(2000); printf("Oh dear! You failed to flee! Gamover!\n"); printf("Thank you for playing! -Anthony\n"); sleep(7000); exit(0); } else { printf("You succeeded in fleeing! You will be returned to town\nshortly...\n\n\n\n

问题 So I am using this current script below: <script type="text/javascript"> if (window.location.href.indexOf('thevault') > -1) { //window.location = 'http://thevault.co.uk/index.phtml?d=512060’; window.location = '/index.phtml?d=512060'; } else { //window.location = 'http://www.jths.co.uk/index.phtml?d=541300'; window.location = '/index.phtml?d=541300'; } </script> Which works fine, however I want to add another condition if the url is: http://www.nationalforestteachingschool.co.uk , then go to

问题 Excel Image 1 From "Excel Image 1", I am pulling data into python of Column A and Column B. The goal is to sum the values of Column B, and see whether it is higher or lower than the given sum of 1500. If it is higher or equal to 1500, then there needs to be nothing done. But, if it is lower, then adjust the values that has the word "change" beside them, such that the calculated sum becomes 1500 or more. In our case, the sum is 700, which is lower than 1500. import xlrd excel = '/Users/Bob

问题 Excel Image 1 From "Excel Image 1", I am pulling data into python of Column A and Column B. The goal is to sum the values of Column B, and see whether it is higher or lower than the given sum of 1500. If it is higher or equal to 1500, then there needs to be nothing done. But, if it is lower, then adjust the values that has the word "change" beside them, such that the calculated sum becomes 1500 or more. In our case, the sum is 700, which is lower than 1500. import xlrd excel = '/Users/Bob

问题 I'm trying to write a price quote estimator that utilizes an array of zip codes to be a service area. The list of zip codes is rather extensive, so I don't know if it is better or an option at all to have an external source, such as a CSV. What I would like is for people to enter their zip codes, and if it is on the list, they will be given the price calculator option. If their zip code is not on the list, a message should appear of "Please Call for More Info" I am sort of frankensteining

问题 I'm trying to write a price quote estimator that utilizes an array of zip codes to be a service area. The list of zip codes is rather extensive, so I don't know if it is better or an option at all to have an external source, such as a CSV. What I would like is for people to enter their zip codes, and if it is on the list, they will be given the price calculator option. If their zip code is not on the list, a message should appear of "Please Call for More Info" I am sort of frankensteining

问题 Closed . This question is opinion-based. It is not currently accepting answers. Want to improve this question? Update the question so it can be answered with facts and citations by editing this post. Closed 6 years ago . I have noticed similar repetition and trying to work around using a single for loop for this if I can to minimize the code length: I wouldn't need to use a switch case if I can form a loop instead? $returnNo variable starts at 5, each case multiplied by 2 then minus 1. where

问题 I'm trying to write an if statement like this if(denominator([(i-1)! + 1] / i)-1,print(hi),print(ho)) i can be any integer for example 10, when I set i to 10 it gives this error. ? [(x-1)! + 1] / x *** this should be an integer: [(x-1)!+1]/x ^----------- I really only need to check if [(x-1)! + 1] / x is an integer or not the denominator thing is what I came up with, I also tried Mod but couldn't get that working either. 回答1: It seems that you are confused with the names x and i . Please, see

问题 From this picture we know the data have mode 3.14 and the value 3.14 = value 3.1 , right? whereas the value 3.1 its not only 3.14 , but include 3.05, 3.06, 3.07, 3.08, 3.09, 3.10 , 3.11 , 3.12 , 3.13 , and 3.14 right ? the question is , how to let the count ​​of the formula may appear with the known just mode ? or whats formula of "if" or "round", if I want to know the count from that value of 3.05, 3.06, 3.07, 3.08, 3.09, 3.10 , 3.11 , 3.12 , 3.13 , and 3.14 was selected from the range of

问题 Is there a better way to be able to count the amounts of empty groups than using this method and then calling $count + 1 for each result? I tried to mess around with $123.count but it kept returning 0 $Groups = Get-ADGroup -Properties * -Filter * | where { $_.Members.Count -eq 0} $123= Foreach($G In $Groups) { $Membership = Get-ADGroupMember -Identity $G.Name If($Membership.count -eq 0){ $Count = $count + 1 } } 回答1: Get-ADGroup can do much of what you ask without going away from AD. Getting