if-statement

Decision making inside a for loop and taking certain path based on output from gathered results

橙三吉。 提交于 2020-04-18 01:04:11
问题 I would love to simplify my code, with better utilisation of for loop indexes. The goal is to change out all UP once for new UP once, which means take down each UP one and bring it up again. There should always be one in UP state while this process takes place, so I need to cover the following scenarios: up - up == delete -> create -> delete -> create down - down == delete -> create -> delete -> create up - down == delete -> create -> delete -> create down - up == delete -> create -> delete -

Simplifying decision tree when working with map which has two keys and value as a slice

亡梦爱人 提交于 2020-04-17 20:29:26
问题 Can this logic not be simplified more, the code works, but it has become too much of a spaghetti. The requirements are that there should always be one connection if possible in available state, but I need to take all the available states down and re-create them. these paths I have to cover: if both vifs down, call create if both vifs available, take them down and up one-by-one if one down and one available, bring first up the down one, then take down and bring up the available one if only one

Expected Statement End If

我的梦境 提交于 2020-04-17 14:27:14
问题 I have the following code setup in a form and I'm getting the "Expected Statement" error. My first time doing this and thought I had the syntax correct, what am I missing? <% If Trim(oQuote("shipmeth"))="FREIGHT" Then Response.Write "Freight" ElseIf Trim(oQuote("shipmeth"))="THRSHLD" Then Response.Write "Threshold" End If %> 回答1: When using nested 2-way conditionals, each conditional must be closed by its own End If : If condition_A Then action_A Else If condition_B Then action_B Else If

Expected Statement End If

两盒软妹~` 提交于 2020-04-17 14:22:43
问题 I have the following code setup in a form and I'm getting the "Expected Statement" error. My first time doing this and thought I had the syntax correct, what am I missing? <% If Trim(oQuote("shipmeth"))="FREIGHT" Then Response.Write "Freight" ElseIf Trim(oQuote("shipmeth"))="THRSHLD" Then Response.Write "Threshold" End If %> 回答1: When using nested 2-way conditionals, each conditional must be closed by its own End If : If condition_A Then action_A Else If condition_B Then action_B Else If

Using local variable outside its chunk in Lua?

别说谁变了你拦得住时间么 提交于 2020-04-16 05:00:29
问题 I have a nested if in Lua. I have a variable inside the second if layer that I want to use in the first layer. The variable is npcSpecimen . if conditions then local npcType = util.pickRandom(self.npcTypes) local npcSpecimen = "" if npcType == "spacebandit" then local npcSpecimen = util.pickRandom(self.npcSpecies) else local npcSpecimen = util.pickRandom(self.npcSpeciesMutant) end local npcId = space.spawnNpc(spawnPosition, npcSpecimen, npcType) end If written this way, npcSpecimen will

How to merge two files based on data in multiple columns?

大兔子大兔子 提交于 2020-04-16 03:47:06
问题 I have two separate files, each containing a different number of columns which I want to merge based on data in multiple columns. file1 VMNF01000015.1 1769465 1769675 . . - Focub_II5_mimp_1 VMNF01000014.1 3225875 3226081 . . + Focub_II5_mimp_1 VMNF01000014.1 3226046 3226081 . . - Focub_II5_mimp_1 VMNF01000014.1 3585246 3585281 . . - Focub_II5_mimp_1 VMNF01000014.1 3692468 3692503 . . - Focub_II5_mimp_1 VMNF01000014.1 3715380 3715415 . . + Focub_II5_mimp_1 VMNF01000014.1 2872478 2872511 . . -

Divide two integers without using multiplication, division and mod operator in java

一曲冷凌霜 提交于 2020-04-14 09:05:03
问题 I write down a code which find out quotient after dividing two number but without using multiplication,division or mod operator. My code public int divide(int dividend, int divisor) { int diff=0,count=0; int fun_dividend=dividend; int fun_divisor=divisor; int abs_dividend=abs(dividend); int abs_divisor=abs(divisor); while(abs_dividend>=abs_divisor){ diff=abs_dividend-abs_divisor; abs_dividend=diff; count++; } if(fun_dividend<0 && fun_divisor<0){ return count; } else if(fun_divisor<0||fun

Divide two integers without using multiplication, division and mod operator in java

笑着哭i 提交于 2020-04-14 09:03:25
问题 I write down a code which find out quotient after dividing two number but without using multiplication,division or mod operator. My code public int divide(int dividend, int divisor) { int diff=0,count=0; int fun_dividend=dividend; int fun_divisor=divisor; int abs_dividend=abs(dividend); int abs_divisor=abs(divisor); while(abs_dividend>=abs_divisor){ diff=abs_dividend-abs_divisor; abs_dividend=diff; count++; } if(fun_dividend<0 && fun_divisor<0){ return count; } else if(fun_divisor<0||fun

Divide two integers without using multiplication, division and mod operator in java

北战南征 提交于 2020-04-14 09:03:13
问题 I write down a code which find out quotient after dividing two number but without using multiplication,division or mod operator. My code public int divide(int dividend, int divisor) { int diff=0,count=0; int fun_dividend=dividend; int fun_divisor=divisor; int abs_dividend=abs(dividend); int abs_divisor=abs(divisor); while(abs_dividend>=abs_divisor){ diff=abs_dividend-abs_divisor; abs_dividend=diff; count++; } if(fun_dividend<0 && fun_divisor<0){ return count; } else if(fun_divisor<0||fun

multiple conditions for if else statement in R

主宰稳场 提交于 2020-04-10 06:46:45
问题 I would like to add (numerous) conditions to a loop that cycles through my data (and currently only picks the closest (not necessarily most recent) previous owner within a set distance). Previous owners (>20,000) are stored in a dataset called lifetime_census (data available here): previous_id reflo locx locy lifespan census_year gr 5587 -310 -3 10 1810 2003 A 7687 -310 -3 10.1 110 2001 A 5101 Q1 17.3 0.8 55 2004 A 9109 Q1 17.4 0.9 953 2003 B 6077 M2 13 1.8 979 2003 B 8044 M2 13.1 1.7 100