idiomatic

I'm still pretty new to R and AI / ML techniques. I would like to use a neural net for prediction, and since I'm new I would just like to see if this is how it should be done. As a test case, I'm predicting values of sin() , based on 2 previous values. For training I create a data frame with y = sin(x) , x1 = sin(x-1) , x2 = sin(x-2) , then use the formula y ~ x1 + x2 . It seems to work, but I am just wondering if this is the right way to do it, or if there is a more idiomatic way. This is the code: require(quantmod) #for Lag() requre(nnet) x <- seq(0, 20, 0.1) y <- sin(x) te <- data.frame(y,

Programming is about making decisions about how to implement any piece of code. Depending of such decisions, the code will be more or less readable, efficient, complex, etc. A common decision is also about to do it more or less idiomatic, that is, using specific statements or your programming language or paradigm. As a proof of concept I have developed two code snippets, in Javascript, to analyze the performance. The goal is to generate a string in the form tagA|tagB|tagC where then number of tagX is random and the suffixes A , B , C are random integers. Moreover, tagX can not be repeated.

Is there a better or more concise way to do the following? (defn swap [v i1 i2] "swap two positions in a vector" (let [e1 (v i1) e2 (v i2)] (-> (assoc v i1 e2) (assoc i2 e1)))) I can't think of a particularly elegant solution, either. Here's how I'd write it though: (defn swap [v i1 i2] (asso­c v i2 (v i1) i1 (v i2)))­ 来源： https://stackoverflow.com/questions/5979538/what-is-the-idiomatic-way-to-swap-two-elements-in-a-vector

Let the code speak first def bars = foo.listBars() def firstBar = bars ? bars.first() : null def firstBarBetter = foo.listBars()?.getAt(0) Is there a more elegant or idiomatic way to get the first element of a list, or null if it's not possible? (I wouldn't consider a try-catch block elegant here.) Not sure using find is most elegant or idiomatic, but it is concise and wont throw an IndexOutOfBoundsException. def foo foo = ['bar', 'baz'] assert "bar" == foo?.find { true } foo = [] assert null == foo?.find { true } foo = null assert null == foo?.find { true } You could also do foo[0] This will

I have a simple class with a single method exec(arg1,..,argn) and I want to have a number of alias methods which call exec with predefined argument values (e.g. exec_sync = exec.bind(this, true) ). The following does the trick: class Executor { constructor() { this.exec_sync = this.exec.bind(this, true); } exec(sync, cmd, args/* ... */) { // impl } } But I don't know if this is a good idea or if this is idiomatic to ES6. UDATE: In a real-life example I have two nested loops with respectively 3 and 4 loops, which are used to dynamically add a total number of 12 alias methods to the class. It