httprequest

问题 I have been given the following documentation (https://autovit.zendesk.com/hc/ro/articles/214077685-Obtinere-token-acces) and I want to call this api to get the access token for subsequent requests. I do not understand how you can multiple parameters -u 79: 70f8c636a503d50ac6c411597b4cc402 The post request I have been given is: How can we help? dealers partners API Autovit POST https://ssl.autovit.ro/api/open/oauth/token/ -X POST -H "Accept: application / json" -u 79:

问题 I am working with cookies in my .net application. Is there anyway in the setting of the cookie to the users web browser it wont be sent in the http request for static resources such as css, javascript or images. Or is the only way around not sending cookies in such requests, setting up cookieless domains for such resources. 回答1: Let me start by saying this: Unless you're getting thousands of requests per second, the total effect on bandwidth and server load will be minimal. So unless you're

问题 Here is the scenario. A cookie with the key "MyCookie" has been set on a previous request. I can access it via HttpContext.Request.Cookies.Get("MyCookie") . I want to perform an update such as adding another value to the Cookie Values collection, but I'm not 100% sure I am doing it right. Am I doing this correctly in the following example? public static void UpdateCookie(HttpContext context, string cookieName, Action<HttpCookie> updateCookie){ var cookie = context.Request.Cookies.Get

问题 I need to put an array of objects ( each object has 2 fields ) as parameters in url of http request. How can i do it and how should this link looks like? 回答1: You can make an xml with your structure i.e an array of objects each having two fields then convert that to string as, As an example, String input = String.format("<Request><Data><Id>%s</Id></Data> </Request>",studentIdSelected); Then call this method with input and url as parameters for posting your data, public static String retriver

问题 The app I'm working on has a self contained database. The only time I need HTTP request is when the user first loads the app. I do this by calling a class that verifies whether or not a local DB exists and, if not, create one with the following request: HttpRequest data = new HttpRequest("http://www.somedomain.com/xml", "GET", this); data.start(); This xml returns a list of content, all of which have images that I want to fetch AFTER the original request is complete and stored. So something

问题 Controller: (function(angular) { var app = angular.module('t2w'); app.factory('httpq', function($http, $q) { return { get: function() { var deferred = $q.defer(); $http.get.apply(null, arguments).success(deferred.resolve).error(deferred.resolve); return deferred.promise; } } }); app.controller('JobsCtrl', ['$scope','httpq','baseUrl', function($scope, httpq, baseUrl) { httpq.get(baseUrl + '/jobs/json').then(function(data) { $scope.jobs = data; }).catch(function(data, status) { console.error(

问题 I am trying to submit a json post request using HttpURLConnection in Scala. I followed along to two tutorials and produced this: def sendPost(url: String, jsonHash: String) { val conn: HttpURLConnection = new URL(url).openConnection().asInstanceOf[HttpURLConnection] conn.setRequestMethod("POST") conn.setRequestProperty("Content-Type", "application/json") conn.setRequestProperty("Accept", "application/json") conn.setDoOutput(true) conn.connect() val wr = new DataOutputStream(conn

问题 I want to send the following JSON text {"Email":"aaa@tbbb.com","Password":"123456"} to a web service and read the response. I know to how to read JSON. The problem is that the above JSON object must be sent in a variable name jason . How can I do this from android? What are the steps such as creating request object, setting content headers, etc. 回答1: Android doesn't have special code for sending and receiving HTTP, you can use standard Java code. I'd recommend using the Apache HTTP client,

问题 I want to connect to a sms gateway. I found the following code. public void smsSender(String username, String password, String to, String text) throws IOException { try { String data = "username=" + username + "&password=" + password + "&to=" + to + "&text=" + text; URL url = new URL("https://sendsms.abc.com:1010/sms.php"); HttpURLConnection urlc = (HttpURLConnection) url.openConnection(); urlc.setRequestMethod("POST"); urlc.setDoOutput(true); urlc.setRequestProperty("Content-type",

问题 How to delete a saved request in chrome's ARC (Advanced REST Client) extension? I currently have ARC extension installed in chrome and some requests saved. I looked for, but didin't find any way to delete a request from the "saved" list. tried to select the request and press delete key (from keyboard), but doesn't work tried to find some "delete" option on the menus, but didn't find extension link: https://chrome.google.com/webstore/detail/advanced-rest-client/hgmloofddffdnphfgcellkdfbfbjeloo