http-post

How to pass POST parameters in a URL?

独自空忆成欢 提交于 2019-11-28 18:36:30
Basically, I think that I can't, but would be very happy to be proven wrong. I am generating an HTML menu dynamically in PHP, adding one item for each current user, so that I get something like <a href="process_user.php?user=<user>> , but I have a preference for POST over GET. Is there any way to pass the info as a POST parameter, rather than GET from a clickable HREF link? Update: sorry, I am not allowed to use JS - I shoulda said, my bad Update to the update: it looks like @Rob is on to somethign with "You could use a button instead of an anchor and just style the button to look like a link.

urllib2 POST progress monitoring

我怕爱的太早我们不能终老 提交于 2019-11-28 18:27:47
I'm uploading a fairly large file with urllib2 to a server-side script via POST. I want to display a progress indicator that shows the current upload progress. Is there a hook or a callback provided by urllib2 that allows me to monitor upload progress? I know that you can do it with download using successive calls to the connection's read() method, but I don't see a write() method, you just add data to the request. It is possible but you need to do a few things: Fake out the urllib2 subsystem into passing a file handle down to httplib by attaching a __len__ attribute which makes len(data)

How to mimic an HTML form submission in a POST request?

前提是你 提交于 2019-11-28 17:34:11
I have HTML form that is used for sending bugreports from application to server. I need to mimic this behavior programmatically. What will the corresponding POST request (or series of requests) look like? <form name="bugreport" method="post" enctype="multipart/form-data" action="http://my-server.com/bugreport.php"> <div name="SentData"> <textarea name="logfile" class="UserVisible"></textarea><br> <textarea name="configfile" class="UserVisible"></textarea><br> </div> <textarea name="usercomment" class="invisible"></textarea><br> <input name="useremail" type="text" class="invisible"> <input

What is the difference between [AcceptVerbs(HttpVerbs.Post)] and [HttpPost]?

橙三吉。 提交于 2019-11-28 17:08:23
I can decorate an action either with the [AcceptVerbs(HttpVerbs.Post)]/[AcceptVerbs(HttpVerbs.Get)] [AcceptVerbs(HttpVerbs.Post)] public ActionResult Create(string title) { // Do Something... } or with the [HttpPost]/[HttpGet] attributes [HttpPost] public ActionResult Create(string title) { // Do Something... } Are they different? Nothing. One is just shorthand for the other. Rudresha Parameshappa [HttpPost] is shorthand for [AcceptVerbs(HttpVerbs.Post)] . The only difference is that you can't use [HttpGet, HttpPost] (and similar) together on the same action. If you want an action to respond

check POST request with Fiddler

依然范特西╮ 提交于 2019-11-28 16:48:46
问题 How can I use Fiddler to check the response from a web server. I could easily check the GET method by pasting the url to the field in Request Builder and get the response back in xml/json. There is an option POST, however I don't know how can I pass the parameters to the POST. For example: HttpWebRequest request = (HttpWebRequest)WebRequest.Create("https://www.google.com/accounts/ClientLogin"); request.Method = "POST"; string postData = "accountType=HOSTED_OR_GOOGLE"; postData += "&Email

How to send Https Post request in java

孤街浪徒 提交于 2019-11-28 16:42:53
问题 I want to login to application from java code. Here is my code... String httpsURL = "https://www.abcd.com/auth/login/"; String query = "email="+URLEncoder.encode("abc@xyz.com","UTF-8"); query += "&"; query += "password="+URLEncoder.encode("abcd","UTF-8") ; URL myurl = new URL(httpsURL); HttpsURLConnection con = (HttpsURLConnection)myurl.openConnection(); con.setRequestMethod("POST"); con.setRequestProperty("Content-length", String.valueOf(query.length())); con.setRequestProperty("Content-Type

submit a form in a new tab

陌路散爱 提交于 2019-11-28 16:35:20
问题 I'd like (just to test some functions, after I'll avoid this behaviour) to load the page called by submit on a new tab : is it possible? 回答1: <form target="_blank" [....] will submit the form in a new tab... I am not sure if is this what you are looking for, please explain better... 回答2: I have a [submit] and a [preview] button, I want the preview to show the print view of the submitted form data, without persisting it to database. Therefore I want [preview] to open in a new tab, and submit

Can't post response from AsyncTask to MainActivity [closed]

南笙酒味 提交于 2019-11-28 13:13:56
I'm new to Android application development. Please find my code for AsyncTask for connecting a URL when a user clicked on a button. package in.mosto.geeglobiab2bmobile; import java.io.IOException; import java.net.HttpURLConnection; import java.util.ArrayList; import java.util.List; import org.apache.http.HttpResponse; import org.apache.http.NameValuePair; import org.apache.http.StatusLine; import org.apache.http.client.ClientProtocolException; import org.apache.http.client.HttpClient; import org.apache.http.client.entity.UrlEncodedFormEntity; import org.apache.http.client.methods.HttpPost;

Objective-C->JSON->PHP Array

天大地大妈咪最大 提交于 2019-11-28 12:46:25
I've been struggling with this for the last few days; I am trying to post an array to PHP. I can successfully send it, but it's not taken in with a post-variable (I am trying to use the variable key "json"... With this code, I receive the array in php: Objective-C NSError *error; NSDictionary *jsonDictionary = [NSDictionary dictionaryWithObjects:[NSArray arrayWithObjects: @"one", @"two", @"three", nil] forKeys: [NSArray arrayWithObjects: @"a", @"b", @"c", nil]]; NSArray *jsonArray = [NSArray arrayWithObject:jsonDictionary]; NSData *jsonData = [NSJSONSerialization dataWithJSONObject:jsonArray

Send a JSONArray POST request with android volley library

点点圈 提交于 2019-11-28 12:45:17
I would like to send and receive a Json Array with volley. Now I can receive an array and it's ok but I don't know how to send a request (For example: with post method). JsonArrayRequest arrayReq = new JsonArrayRequest(URL, new Listener<JSONArray>() { } List<Map<String,String>> listMap = new ArrayList<Map<String, String>>(); Map<String,String> map = new HashMap<String,String>(); try { map.put("email", customer.getEmail()); map.put("password",customer.getPassword()); } catch (Exception e) { e.printStackTrace(); } listMap.add(map); String url = PersonalConstants.BASE_URL+"/url";