http-post

django ajax post 403 forbidden

被刻印的时光 ゝ 提交于 2019-12-03 16:47:56
问题 using django 1.4 im getting a 403 error when i try to do a post from my javascript do my django server. my get works fine though the problem is only with the post. also tried @csrf_exempt with no luck UPDATE: I can Post now that i added {% csrf_token %} , but the post response comes empty, although the GET comes correctly, any ideas? my django view: @csrf_protect def edit_city(request,username): conditions = dict() #if request.is_ajax(): if request.method == 'GET': conditions = request.method

SOAP object over HTTP post in C# .NET

Deadly 提交于 2019-12-03 16:37:01
问题 I am trying to compose a SOAP message(including header) in C# .NET to send to a URL using HTTP post. The URL I want to send it to is not a web-service, it just receives SOAP messages to eventually extract information from it. Any ideas on how to do this? 回答1: First you need to create a valid XML. I use Linq to XML to achieve this, like follow: XNamespace soapenv = "http://schemas.xmlsoap.org/soap/envelope/"; var document = new XDocument( new XDeclaration("1.0", "utf-8", String.Empty), new

Can I make HTTP POST request from Thymeleaf table in Spring Boot application

妖精的绣舞 提交于 2019-12-03 16:26:08
I have a Thymeleaf template in a simple Spring Boot application. The template contains a list in a table as follows: <p>There are <span th:text="${#lists.size(persons)}"></span> people:</p> <table th:if="${not #lists.isEmpty(persons)}" border="1"> <tr> <th>ID</th> <th>Name</th> <th>Address</th> <th>Telephone</th> <th>Email</th> <th>Actions</th> </tr> <tr th:each="person : ${persons}"> <td th:text="${person.personId}"></td> <td th:text="${person.name}"></td> <td th:text="${person.address}"></td> <td th:text="${person.telephone}"></td> <td th:text="${person.email}"></td> <td> <a href="#" data-th

How to login using Reddit's API?

℡╲_俬逩灬. 提交于 2019-12-03 16:24:34
Am trying to access my Reddit user's account by using the Reddit API - POST login Endpoint listed on its API page. I tried this: curl -i -X POST -d '{"user":"myusername", "passwd":"mypassword", "rem":"true" }' http://www.reddit.com/api/login But it said wrong password (I logged into the website with the same credentials so I don't know what's wrong): HTTP/1.1 200 OK Content-Type: application/json; charset=UTF-8 { "jquery": [[0, 1, "call", ["body"]], [1, 2, "attr", "find"], [2, 3, "call", [".status"]], [3, 4, "attr", "hide"], [4, 5, "call", []], [5, 6, "attr", "html"], [6, 7, "call", [""]], [7,

SpringMVC HTTP Status 405 - Request method 'POST' not supported

混江龙づ霸主 提交于 2019-12-03 16:21:04
I have a form i query the database from that form and is posted to another page with the results. I then select one record from the query results and it takes me back to the page i made the query from so i can update the record. I click update which takes me back to the controller and to tahe same method first called to query, however the requested parameter is now 'update' so it is suppose to go to the update condition in the method. It seems as though i cannot re-submitt the page to the same url mapping. Controller @RequestMapping(value="citizen_registration.htm", method = RequestMethod.POST

R - posting a login form using RCurl

佐手、 提交于 2019-12-03 15:18:04
问题 I am new to using R to post forms and then download data off the web. I have a question that is probably very easy for someone out there to spot what I am doing wrong, so I appreciate your patience. I have a Win7 PC and Firefox 23.x is my typical browser. I am trying to post the main form that shows up on http://www.aplia.com/ I have the following R script: your.username <- 'username' your.password <- 'password' setwd( "C:/Users/Desktop/Aplia/data" ) require(SAScii) require(RCurl) require(XML

Android set content type HttpPost

余生颓废 提交于 2019-12-03 14:56:45
问题 How can you change the content-type of a HttpPost in android? For a request I need to set the content type to application/x-www-form-urlencoded So i got this bit of code: httpclient=new DefaultHttpClient(); httppost= new HttpPost(url); StringEntity se = new StringEntity(""); se.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE, "application/x-www-form-urlencoded")); httppost.setEntity(se); But that doesn't do the trick and I cant find the solution anywhere. Cheers 回答1: HttpPost httppost =

HttpPost to ReturnURL after redirect

感情迁移 提交于 2019-12-03 14:35:09
I am writing an ASP.NET MVC 2.0 application which requires users to log in before placing a bid on an item. I am using an actionfilter to ensure that the user is logged in and, if not, send them to a login page and set the return url. Below is the code i use in my action filter. if (!filterContext.HttpContext.User.Identity.IsAuthenticated) { filterContext.Result = new RedirectResult(String.Concat("~/Account/LogOn","?ReturnUrl=",filterContext.HttpContext.Request.RawUrl)); return; } In my logon controller I validate the users credentials then sign them in and redirect to the return url FormsAuth

ByteArrayOutputStream to a FileBody

最后都变了- 提交于 2019-12-03 13:53:27
I have a Uri to an image that was either taken or selected from the Gallery that I want to load up and compress as a JPEG with 75% quality. I believe I have achieved that with the following code: ByteArrayOutputStream bos = new ByteArrayOutputStream(); Bitmap bm = BitmapFactory.decodeFile(imageUri.getPath()); bm.compress(CompressFormat.JPEG, 60, bos); Not that I have tucked it into a ByteArrayOutputStream called bos I need to then add it to a MultipartEntity in order to HTTP POST it to a website. What I can't figure out is how to convert the ByteArrayOutputStream to a FileBody. Use a

How to get form parameters in request filter

匆匆过客 提交于 2019-12-03 12:37:44
I'm trying to get the form parameters of a request in a request filter: @Override public ContainerRequest filter(final ContainerRequest request) { final Form formParameters = request.getFormParameters(); //logic return request; } However, the form always seems to be empty. The HttpRequestContext.getFormParameters() documentation says: Get the form parameters of the request entity. This method will ensure that the request entity is buffered such that it may be consumed by the applicaton. Returns: the form parameters, if there is a request entity and the content type is "application/x-www-form