http-post

I need to upload Image and Video File with multiple parameters like File Name, Description , Height and Width using HttpPost method. Thanks, Suggestion appreciated. For uploading a file the efficient way is using HttpPost with multipart/form Multipart/form The file contents are either stored in memory or temporarily on disk. In either case, the user is responsible for copying file contents to a session-level or persistent store as and if desired. The temporary storages will be cleared at the end of request processing Refer this Upload Files from Android to a Website/Http Server using Post try

I have an array of image objects. console.info('gallery', galleryArray); The length of this array can be different. I have to make a POST request on every item of this array. The next request must be executed only after previous request has finished. So I tried to make an array of Observable requests like this: let requests: Observable<Response>[] = []; galleryArray.forEach((image) => { requests.push(this._myService.uploadFilesImages(image)); }); console.info(requests); My service looks like this: uploadFilesImages(fileToUpload: any): Observable<any> { const input = new FormData(); input

I have to do post request to a web-service to authenticating the user with username and password. I have a problem with following post request: public String postTest(String action, ConnectionParametrData [] parameters) { Uri.Builder builder = new Uri.Builder().scheme(scheme).authority(authority).path(action); uri = builder.build(); BufferedReader in = null; String ans = null; HttpPost request = new HttpPost(uri.toString()); HttpClient defaultClient = new DefaultHttpClient(); try { request.setHeader("Content-Type", "application/x-www-form-urlencoded"); request.setEntity(new

I need to accept form data to a WCF-based service. Here's the interface: [OperationContract] [WebInvoke(UriTemplate = "lead/inff", BodyStyle = WebMessageBodyStyle.WrappedRequest)] int Inff(Stream input); Here's the implementation (sample - no error handling and other safeguards): public int Inff(Stream input) { StreamReader sr = new StreamReader(input); string s = sr.ReadToEnd(); sr.Dispose(); NameValueCollection qs = HttpUtility.ParseQueryString(s); Debug.WriteLine(qs["field1"]); Debug.WriteLine(qs["field2"]); return 0; } Assuming WCF, is there a better way to accomplish this besides parsing

I have a controller to show up a model (User) and want to create a screen just with a button to activate. I don't want fields in the form. I already have the id in the url. How can I accomplish this? You could use a hidden field inside the form: <% using (Html.BeginForm()) { %> <%= Html.HiddenFor(x => x.Id) %> <input type="submit" value="OK" /> <% } %> or pass it in the action of the form: <% using (Html.BeginForm("index", "home", new { id = RouteData.Values["id"] }, FormMethod.Post)) { %> <input type="submit" value="OK" /> <% } %> Use [ActionName] attribute - this way you can have the URLs

I'd like to know if there is a way to show in an input of type text a different value than the one send to PHP. For example, let say you have : <input type="text" value="John"> that display John. Can I change the value to "Doe" for the user but keep it to "John" for php? Can I achieve this using the difference between $.attr('value') and $.val() ? I ran a couple of tests and it seems that I will have to reverse it directly in my controller. Is there an other solution? Here is a little jSFiddle to play around. An odd request to be sure but... You can't change the field's value and just do a