http-post

问题 I am new to android and I dont know how to POST using retrofit I have my own server which returns me data, I need to fetch that one This is how URL body looks like I have to send "city name" taken by edittext and pass it inside "ms_data's" keyword, i.e keyword="India" This is what I have tried so far... Retrofit Builder class public class RetrofitBuilder { public static Retrofit retrofit; public static final String BASE_URL = "my url"; public static Retrofit getApiData() { if(retrofit==null)

问题 I have the following ajax code that makes a POST request for a blob to the server,and prints the returned data. function upload(blob){ var formData = new FormData(); formData.append('file', blob); $.ajax({ url: "http://custom-url/record.php", type: 'POST', data: formData, contentType: false, processData: false, success: function(data) { console.log(data); } }); } How can I do the same thing in AngularJS? 回答1: Instead of appending the blob to FormData, it is more efficient to send the blob

问题 I'm trying to do a simple file upload using objective c and NSUrlRequest. My current (more or less googled and put together) code: NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init]; [request setURL:[NSURL URLWithString:@"http://127.0.0.1:8000/api/upload/"]]; [request setHTTPMethod:@"POST"]; NSString *boundary = [NSString stringWithString:@"---------------------------14737809831466499882746641449"]; NSString *contentType = [NSString stringWithFormat:@"multipart/form-data;

问题 I have one site e.g. www.myfirstsite.com/myapp . When I do login in this site I did extract the POST request of authentication from the browser. Is just a simple authentication (the authentication URL is different) process. and username and password in parameters username = abc_user password = 123456 and the complete URL is www.anothersite.com/login?username=abc_user&password=123456 When I do POST request using Postman I received expected result. Is there any way (any script which I enter in

问题 I have a form for logging into my website. I need to make it so that when the user hits enter, the form submits. How can I do this? Please provide code. Thanks. <form id="login" action="myHome.php" method="POST"> <input type="text" name="email" id="email"/> <br/> <br/> <input type="text" name="password" id="password"/> </form> 回答1: Have you actually tried anything? You need to add an <input type="submit"> and hide it with CSS so that the browser knows what to trigger when enter is pressed,

问题 We're integrating with chargify http://www.chargify.com and I need to handle webhooks from Chargify in our MVC4/C# server. Chargify sends POST data in the (ruby) way - sub objects are delimited in square brackets, like so: POST /1ffaj2f1 HTTP/1.1 X-Chargify-Webhook-Signature: 526ccfd9677668674eaa6ba5d447e93a X-Chargify-Webhook-Id: 11238622 User-Agent: Ruby Host: requestb.in Content-Type: application/x-www-form-urlencoded Content-Length: 5159 Connection: close Accept-Encoding: gzip, deflate

问题 I am sending a HTTP POST request from android to a server using the script below URI website = new URI("http://venkygcm.appspot.com"); HttpClient client = new DefaultHttpClient(); HttpPost request = new HttpPost(website); request.setHeader("Content-Type", "application/json"); String currentDateTimeString = DateFormat.getDateTimeInstance().format(new Date()); JSONObject obj = new JSONObject(); obj.put("reg_id","Registration ID sent to the server"); obj.put("datetime",currentDateTimeString);

问题 How do you get values from a POST request in ColdFusion? Figured the hard way that POST.id doesn't work like URL.id . 回答1: Post values are passed in the FORM scope ie FORM.id 回答2: You want FORM, not POST. eg form.id or form['id'] 来源： https://stackoverflow.com/questions/5812032/how-to-get-post-data-in-coldfusion

问题 Here are my resources: class CourseResource(ModelResource): subjects = fields.ToManyField('core.api.SubjectResource', 'subjects', full=True) class Meta: queryset = Course.objects.all() resource_name = 'course' authorization = Authorization() validation = FormValidation(form_class=CourseForm) class SubjectResource(ModelResource): class Meta: queryset = Subject.objects.all() resource_name = 'subject' authorization = Authorization() I am trying to post using curl on a django-tastypie system.

问题 I am new to Java and to client- server programming. I am using embedded Jetty, and I'm trying to send a JSON string to some address (http://localhost:7070/json) and then to display the JSON string in that address. I tried the following code but all I get is null. Embedded Jetty code: public static void main(String[] args) throws Exception { Server server = new Server(7070); ServletContextHandler handler = new ServletContextHandler(server, "/json"); handler.addServlet(ExampleServlet.class, "/"