Calling gulp-notify without using .pipe()
In my gulpfile.js I have a task that calls two other tasks. When the previous tasks have run, a notification should be triggered. var notify = require('gulp-notify'); gulp.task('build', ['build:js', 'build:css'], function() { console.log('hello', arguments); gulp.src('gulpfile.js').pipe( notify({ title: 'Production Build', message: 'Done' }) ); }); Is there a way to trigger notify without calling gulp.src('gulpfile.js').pipe( first? While not a real problem, this approach feels unnecessary to me. It is entirely possible that my question results from an insufficient understanding of gulp. So