gsub

问题 The STRATUM from OECD data is so long, for simplicity I put this name and would like to simplified it to a more short and precise naming as in the code below. pisaMas[,`:=` (SchoolType = c(ifelse(STRATUM == "National Secondary School", "Public", ifelse(STRATUM == "Religious School", "Religious", ifelse(STRATUM == "MOE Technical School", "Technical",0)))))] pisaMas[,table(SchoolType)] I would like to know if there are a simple way to this problems, using data.table package. 回答1: Current

问题 The STRATUM from OECD data is so long, for simplicity I put this name and would like to simplified it to a more short and precise naming as in the code below. pisaMas[,`:=` (SchoolType = c(ifelse(STRATUM == "National Secondary School", "Public", ifelse(STRATUM == "Religious School", "Religious", ifelse(STRATUM == "MOE Technical School", "Technical",0)))))] pisaMas[,table(SchoolType)] I would like to know if there are a simple way to this problems, using data.table package. 回答1: Current

问题 Folllow up on question Searching for unique values in dataframe and creating a table with them Here is how my data looks like UUID Source 1 Jane http//mywebsite.com44bb00?utm_source=ADW&utm_medium=banner&utm_campaign=Monk&gclid1234 2 Mike http//mywebsite.com44bb00?utm_source=Google&utm_medium=cpc&utm_campaign=DOG&gclid1234 3 John http//mywebsite.com44bb00?utm_source=Yahoo&utm_medium=banner&utm_campaign=DOG&gclid1234 4 Sarah http//mywebsite.com44bb00?utm_source=Facebookdw&utm_medium=cpc&utm

问题 I want to extract the digits after "." from data.frame[ ,1] and store them in a second column as following: 1 6.354 354 2 6.355 355 3 6.363 363 4 6.367 367 5 6.378 378 6 6.419 419 7 6.426 426 8 6.427 427 9 6.428 428 10 6.431 431 11 6.460 46 12 6.477 477 (...) To do that I use gsub(".*\\.", "", data.frame[,1]) but this ignores the zeros as you can see e.g. in row 11. How can I extract the complete number/all digits after the "."? The column is numeric. 回答1: If this is numeric, then we may need

问题 I have a method that I want to use to replace characters in a string: def complexity_level_two replacements = { 'i' => 'eye', 'e' => 'eei', 'a' => 'aya', 'o' => 'oha'} word = "Cocoa!55" word_arr = word.split('') results = [] word_arr.each { |char| if replacements[char] != nil results.push(char.to_s.gsub!(replacements[char])) else results.push(char) end } end My desired output for the string should be: Cohacohaa!55 However when I run this method it will not replace the characters and only

问题 I'm trying to create a BBcode [code] tag for my rails forum, and I have a problem with the expression: param_string.gsub!( /\[code\](.*?)\[\/code\]/im, '<pre>\1</pre>' ) How do I get what the regex match returns (the text inbetween the [code][/code] tags), and escape all the html and some other characters in it? I've tried this: param_string.gsub!( /\[code\](.*?)\[\/code\]/im, '<pre>' + my_escape_function('\1') + '</pre>' ) but it didn't work. It just passes "\1" as a string to the function.

问题 I have a character vector that I need to clean. Specifically, I want to remove the number that comes before the word "Votes." Note that the number has a comma to separate thousands, so it's easier to treat it as a string. I know that gsub("*. Votes","", text) will remove everything, but how do I just remove the number? Also, how do I collapse the repeated spaces into just one space? Thanks for any help you might have! Example data: text <- "STATE QUESTION NO. 1 Amendment to Title 15 of the

问题 I have a character vector that I need to clean. Specifically, I want to remove the number that comes before the word "Votes." Note that the number has a comma to separate thousands, so it's easier to treat it as a string. I know that gsub("*. Votes","", text) will remove everything, but how do I just remove the number? Also, how do I collapse the repeated spaces into just one space? Thanks for any help you might have! Example data: text <- "STATE QUESTION NO. 1 Amendment to Title 15 of the

问题 What is the most efficient way to apply gsub to various columns? The following does not work x1=c("10%","20%","30%") x2=c("60%","50%","40%") x3 = c(1,2,3) x = data.frame(x1,x2,x3) per_col = c(1,2) x = gsub("%","",x[,per_col]) How can I most efficiently drop the "%" sign in specified columns. Can I apply it to the whole dataframe? This would be useful in the case where I don't know where the percentage columns are. 回答1: You can use apply to apply it to the whole data.frame apply(x, 2, function

问题 What is the most efficient way to apply gsub to various columns? The following does not work x1=c("10%","20%","30%") x2=c("60%","50%","40%") x3 = c(1,2,3) x = data.frame(x1,x2,x3) per_col = c(1,2) x = gsub("%","",x[,per_col]) How can I most efficiently drop the "%" sign in specified columns. Can I apply it to the whole dataframe? This would be useful in the case where I don't know where the percentage columns are. 回答1: You can use apply to apply it to the whole data.frame apply(x, 2, function