greatest-n-per-group

I am trying to select of the duplicate rows in mysql table it's working fine for me but the problem is that it is not letting me select all the fields in that query , just letting me select the field name i used as distinct , lemme write the query for better understading mysql_query("SELECT DISTINCT ticket_id FROM temp_tickets ORDER BY ticket_id") mysql_query("SELECT * , DISTINCT ticket_id FROM temp_tickets ORDER BY ticket_id") 1st one is working fine now when i am trying to select all fields i am ending up with errors i am trying to select the latest of the duplicates let say ticket_id 127 is

I have been trying to find some info on how to select a non-aggregate column that is not contained in the Group By statement in SQL, but nothing I've found so far seems to answer my question. I have a table with three columns that I want from it. One is a create date, one is a ID that groups the records by a particular Claim ID, and the final is the PK. I want to find the record that has the max creation date in each group of claim IDs. I am selecting the MAX(creation date), and Claim ID (cpe.fmgcms_cpeclaimid), and grouping by the Claim ID. But I need the PK from these records (cpe.fmgcms

I want an SQL statement to get the row with a minimum value. Consider this table: id game point 1 x 5 1 z 4 2 y 6 3 x 2 3 y 5 3 z 8 How do I select the ids that have the minimum value in the point column, grouped by game? Like the following: id game point 1 z 4 2 y 5 3 x 2 Ken Clark Use: SELECT tbl.* FROM TableName tbl INNER JOIN ( SELECT Id, MIN(Point) MinPoint FROM TableName GROUP BY Id ) tbl1 ON tbl1.id = tbl.id WHERE tbl1.MinPoint = tbl.Point Aspirant This will work select * from table where (id,point) IN (select id,min(point) from table group by id); As this is tagged with sql only, the

How do I get the most frequently occurring category for each tag in MySQL? Ideally, I would want to simulate an aggregate function that would calculate the mode of a column. SELECT t.tag , s.category FROM tags t LEFT JOIN stuff s USING (id) ORDER BY tag; +------------------+----------+ | tag | category | +------------------+----------+ | automotive | 8 | | ba | 8 | | bamboo | 8 | | bamboo | 8 | | bamboo | 8 | | bamboo | 8 | | bamboo | 8 | | bamboo | 10 | | bamboo | 8 | | bamboo | 9 | | bamboo | 8 | | bamboo | 10 | | bamboo | 8 | | bamboo | 9 | | bamboo | 8 | | banana tree | 8 | | banana tree |

In my system, I have clients. Clients have programs. I want to display a list of clients, showing their most recent active (if it exists) program. Thus, we have something like this: SELECT * FROM clients AS client JOIN programs AS program ON client.id=program.client_id GROUP BY client.id ORDER BY program.close_date=0 DESC, program.close_date DESC close_date=0 means the program isn't closed. So it will put the non-closed programs first, and then the most recently closed programs next. Problem is, the order by doesn't work within the groups. It just kind of picks one of the programs at random.