greatest-n-per-group

Suppose we have 3 employees in each department.we have total 3 departments . Below is the sample source table Emp deptno salary A 10 1000 B 10 2000 C 10 3000 D 20 7000 E 20 9000 F 20 8000 G 30 17000 H 30 15000 I 30 30000 Output B 10 2000 F 20 8000 G 30 17000 With using analytic function dense_rank we can achive the second highest salary dept wise. Can we achieve this without using ANY analytic function ??? Is Max() is also analytic function ?? It is a pain, but you can do it. The following query gets the second highest salary: select t.deptno, max(t.salary) as maxs from table t where t.salary

I have some data formatted like this: Lane Series 1 680 1 685 1 688 2 666 2 425 2 775 ... And I'd like to grab the highest n series per lane (let's say 2 for the sake of this example, but it could be many more than that) So the output should be: Lane Series 1 688 1 685 2 775 2 666 Getting the highest series per lane is easy, but I can't seem to find a way to get the highest 2 results. I use a MAX aggregate function with a GROUP BY to get the MAX, but there's no "TOP N" function as in SQL Server and using ORDER BY... LIMIT only returns the highest N results overall, not per lane. Since I use a

I have this table CREATE TABLE `codes` ( `id` int(11) unsigned NOT NULL AUTO_INCREMENT, `language_id` int(11) unsigned NOT NULL, `title` varchar(60) CHARACTER SET utf8 COLLATE utf8_bin NOT NULL, `time_posted` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY (`id`) ) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=utf8 language_id refers to what language the record is in. What I would like to do is retrieve a list of the five most recent (ORDER BY time_posted DESC LIMIT 5) records in each language_id . I could do this in a loop within PHP with a number of different SQL queries but I

I have two tables (country & ducks) where the country table has every country in the world and the ducks table has a list of ducks with a country_id field to link to the main country. I'm trying to get a list of only countries with at least one duck in it and with that a single matching record from the ducks table for the highest rated duck within that country. So far I have: SELECT * FROM country c INNER JOIN ducks d ON c.id = d.country_id ORDER BY c.country ASC, d.rating DESC This returns a list of every duck rather than just one per country. I'd be grateful if anyone can point me in the

Possible Duplicate: SQL: Find the max record per group I have a table with four columns as such: name major minor revision p1 0 4 3 p1 1 0 0 p1 1 1 4 p2 1 1 1 p2 2 5 0 p3 3 4 4 This is basically ca table containing records for each version of a program. I want to do a select to get all of the programs and their latest version so the results would look like this: name major minor revision p1 1 1 4 p2 2 5 0 p3 3 4 4 I can't just group by the name and get the max of each column because then i would just end up with the highest number from each column, but not the specific row with the highest

I have this data: ID NAME DATE 3 JOHN 2011-08-08 2 YOKO 2010-07-07 1 JOHN 2009-06-06 Code (for SQL Server 2005): DECLARE @TESTABLE TABLE (id int, name char(4), date smalldatetime) INSERT INTO @TESTABLE VALUES (3, 'JOHN', '2011-08-08') INSERT INTO @TESTABLE VALUES (2, 'YOKO', '2010-07-07') INSERT INTO @TESTABLE VALUES (1, 'JOHN', '2009-06-06') I want to get, for each NAME, the ID that has the most recent DATE. Like this: 3 JOHN 2011-08-08 2 YOKO 2010-07-07 What is the most elegant way of accomplishing this? ;WITH x AS ( SELECT ID, NAME, [DATE], rn = ROW_NUMBER() OVER (PARTITION BY NAME ORDER BY