gradient

问题 My question is similar to this question. But I can't transfer it to my own data. I have a dataframe like this (over 1400 rows): Code Stationsname Startdatum LAT LON Höhe Area Mean 1 AT0ENK1 Enzenkirchen im Sauwald 03.06.1998 48.39167 13.67111 525 rural 55.76619 2 AT0ILL1 Illmitz 01.05.1978 47.77000 16.76640 117 rural 58.98511 3 AT0PIL1 Pillersdorf bei Retz 01.02.1992 48.72111 15.94223 315 rural 59.47489 4 AT0SON1 Sonnblick 01.09.1986 47.05444 12.95834 3106 rural 97.23856 5 AT0VOR1 Vorhegg bei

问题 This shows an example of how to create a two-color gradient along a THREE.js line: Color Gradient for Three.js line How do you implement a multi-stop color gradient along a line? It looks like attributes will only interpolate across two values (I tried passing in three, it only worked with the first two values). 回答1: This is the do-it-yourself color gradient approach: Create a line geometry and add some vertices: var lineGeometry = new THREE.Geometry(); lineGeometry.vertices.push( new THREE

问题 Working with Javascript (jQuery), given 2 color values ( 2033ff and 3300a0 for example) how can I determine certain gradient stops between them? Reason being is, I intend on using an array of color values: 0 => '000000' 8400 => 'f0ff00' 44000 => '2033ff' 68400 => '3300a0' There being 86400 seconds in a day, 12:00AM maps to 0, and 11:59PM maps to 86399. As time passes, the background color of a specified element changes to the appropriate color in gradient list via window.setInterval(function

问题 I am sure that this could be done without using of pics: https://yadi.sk/i/Mx6S3s5XdG2tJ 回答1: Use something like this Which uses something like: .knockout-top-to-bottom { position: relative; } .knockout-top-to-bottom:before, .knockout-top-to-bottom:after { content: ""; position: absolute; } .knockout-top-to-bottom:before { top: -3px; left: -3px; bottom: 0; right: -3px; background-image: -webkit-gradient(linear, 0 0, 0 100%, from(#000), to(transparent)); background-image: -webkit-linear

问题 I am creating a game in Sprite-Kit and would want to animate the background in the similar fashion as Instagram does on its login screen. Basically, I just want to know how to have a background in my game just like the Instagram app has on its login screen, i.e the pink colored screen which gradually changes to violet color and then to red with a very subtle flowing effect from right to left. I know how to animate the gradient but that subtle effect that I'm talking about which gives quite a

问题 I am working on one of the opensource projects. I am facing a weird problem. When I open the website on Firefox or Chrome it displays the color I expect, but on IE it does not show up in that color (it shows very light color). My guess is, that this is happening because of the gradient I am using which IE is not able to interpret correctly. Here is gradient CSS code: #mainmenu { #css3_backgroundLinearGradient({ 'angle': 'top', 'colors': [ {'color': '#77D3F8', 'position': '0%'}, {'color': '

问题 I have a icon asset in interface builder which I have as my button image. I can change the colour of it using button.tintColor = UIColor.blueColor() Can I apply a gradient though to a tintColor property? UPDATE For clarity, my png image icon has different shapes, heart, camera, which I have set up as template images. They all have transparent backgrounds. 回答1: You can insert CAGradientLayer into your button and apply the tintColor. Another way is to subclass the UIButton, and in drawRect, use

问题 I'm trying to to program the Mandelbrot set for Android. I try to draw it on a Canvas. It works, but I want to have a color gradient. This is my code: package de.turbofractal; import android.app.AlertDialog; import android.content.Context; import android.content.DialogInterface; import android.graphics.Canvas; import android.graphics.Color; import android.graphics.Paint; import android.view.View; public class FractalView extends View { private int n,g,xMax,yMax; private float zr,zrh,zr0,zi

问题 I have enabled gradient view in attribute inspector but I’m having trouble fixing the colors to show more of a transition with the colors and also show the colors going from bottom to top instead of colors going left to right? What are the modifications on the right pane that need to be made? 回答1: You want Start PointX and End PointX to be 0. Then set Start PointY to 0 and End PointY to 1. This will give a gradient from top to bottom starting with the Top Color at the top and the Bottom Color

问题 I've written a rudimentary algorithm in Fortran 95 to calculate the gradient of a function (an example of which is prescribed in the code) using central differences augmented with a procedure known as Richardson extrapolation. function f(n,x) ! The scalar multivariable function to be differentiated integer :: n real(kind = kind(1d0)) :: x(n), f f = x(1)**5.d0 + cos(x(2)) + log(x(3)) - sqrt(x(4)) end function f !=====! !=====! !=====! program gradient !=========================================