gradient

iOS custom gradient background UIView won't display in simulator [duplicate]

家住魔仙堡 提交于 2019-12-25 18:11:40
问题 This question already has answers here : Execute Code in Launch Screen UPDATED (3 answers) Execute code in Launch Screen (3 answers) Closed last year . I have a custom gradient background on my launch screen which looks and works fine in Interface Builder in XCode but won't display in simulator. What's happening? import UIKit @IBDesignable open class LaunchBkg: UIView { private lazy var gradientLayer: CAGradientLayer = { let gradientLayer = CAGradientLayer() gradientLayer.frame = self.bounds

Gradient background in a JFrame

浪尽此生 提交于 2019-12-25 16:53:46
问题 I have googled this and read a lot but did not find an answer that suits my needs, so I'll ask here: I would like to have a gradient background in my JFrame. Currently the background is a single colour. My code looks something like this: //imports public class Game { //some other irrelevant instance variables JFrame frame = new JFrame("Game"); public Game() { frame.getContentPane().setBackground(new Color(200,220,200)); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setLayout

iOS. OpenGL. Fill area with gradient under curve line

China☆狼群 提交于 2019-12-25 09:16:57
问题 I need to create a sound wave animation like Siri (SiriAnim) With OpenGL I'v got a shape of wave: Here is my code: @property (strong, nonatomic) EAGLContext *context; @property (strong, nonatomic) GLKBaseEffect *effect; // ..... - (void)setupGL { [EAGLContext setCurrentContext:self.context]; glEnable(GL_CULL_FACE); self.effect = [[GLKBaseEffect alloc] init]; self.effect.useConstantColor = GL_TRUE; self.effect.constantColor = GLKVector4Make(0.0f, 1.0f, 0.0f, 1.0f); } // ..... - (void)glkView:

Memory heavy oval gradient

那年仲夏 提交于 2019-12-25 08:49:26
问题 As you may know it is not possible to draw an oval radial gradient using regular Android API. This is what I want to achieve: So I implemented this solution: draw a regular radial gradient on a square bitmap and then this bitmap will get stretched by the view itself (idea found here: https://stackoverflow.com/a/3543899/649910) This works great however this solution takes a lot of memory, because of BitmapDrawable usage (see implementation details below). Any ideas on how to avoid usage of

polygon with blended edges [closed]

不想你离开。 提交于 2019-12-25 07:59:06
问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 3 years ago . I'm trying to find the best way to draw polygons in C# with edges that gradually blend into the background color. I'm drawing the polygons to a bitmap, so currently I'm using the Graphics classes from System.Drawing. The polygons will be a blend mask, I have no problem to draw the

CSS Z-Index with Gradient Background

元气小坏坏 提交于 2019-12-25 06:19:07
问题 I'm making a small webpage where the I would like the top banner with some text to remain on top, as such: HTML: <div id = "topBanner"> <h1>Some Text</h1> </div> CSS: #topBanner{ position:fixed; background-color: #CCCCCC; width: 100%; height:200px; top:0; left:0; z-index:900; background: -moz-linear-gradient(top, rgba(204,204,204,0.65) 0%, rgba(204,204,204,0.44) 32%, rgba(204,204,204,0.12) 82%, rgba(204,204,204,0) 100%); /* FF3.6+ */ background: -webkit-gradient(linear, left top, left bottom,

How do you apply a fading overlay to an image in CSS?

那年仲夏 提交于 2019-12-25 05:18:45
问题 I have an image inside a div . For example's sake, let's say this div has a background-color of #000 . Now, I want this image to fade from the left, to the right. What I mean is, the first column of pixels should appear to have 100% opacity, whilst the final column of pixels should appear to have 0/1% opacity (the final column of pixels will blend in with the background of the div). How would I do this purely in CSS? The image will always be 50x50. 回答1: you could overlay div on top of an

Matlab: gradient of a scalar field

我是研究僧i 提交于 2019-12-25 04:27:23
问题 I have a data in the following format. x y density . . . . . . . . . Here, density is the scalar. How to perform gradient on this dataset? I tried the gradient operator in Matlab. However, it returns only a scalar. Note: Both x and y are uniformly spaced with unit spacing. The boundary points end as floating point numbers, as it is clipped data. 回答1: You can sort the rows of your data so that the data points can be reshaped into a 2D matrix. You can then compute the gradient of that . % Sort

android gradient with 4 params

怎甘沉沦 提交于 2019-12-25 02:27:07
问题 How can I make a gradient like this in xml I can not do it with just these params startColor="" centerColor="" endColor="" any ideas ? 回答1: <?xml version="1.0" encoding="UTF-8"?> <shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle" > <gradient android:angle="90" android:centerColor="#555994" android:endColor="#b5b6d2" android:startColor="#555994" android:type="linear" /> <corners android:radius="0dp"/> </shape> 回答2: if you want to draw it through shape

taking the gradient in Tensorflow, tf.gradient

人盡茶涼 提交于 2019-12-24 18:23:32
问题 I am using this function of tensorflow to get my function jacobian. Came across two problems: The tensorflow documentation is contradicted to itself in the following two paragraph if I am not mistaken: gradients() adds ops to the graph to output the partial derivatives of ys with respect to xs. It returns a list of Tensor of length len(xs) where each tensor is the sum(dy/dx) for y in ys. Blockquote Blockquote Returns: A list of sum(dy/dx) for each x in xs. Blockquote According to my test, it