gradient

问题 N.B. I've already looked at this post and can't emulate it. I'm trying to replicate the shadow on the British Council Sweden site: This is as far as I've managed to get on my own site: I can't post images yet but the HTML is structured like this: <div id="inner"> <!--Full width div, blue bar of color here--> <div class="wrap"> <!--Existing gradient background image here--> <div id="content-wrapper"> <!--Content begins--> </div> </div> </div> The existing CSS: #inner{ background: #1e5799;

问题 I am trying to get/trace the gradient of a variable using pytorch, where I have that variable, pass it to a first function that looks for some minimum value of some other variable, then the output of the first function is inputted to a second function, and the whole thing repeats multiple times. Here is my code: import torch def myFirstFunction(parameter_current_here): optimalValue = 100000000000000 Optimal = 100000000000000 for j in range(2, 10): i = torch.ones(1, requires_grad=True)*j with

问题 Suppose I had two brushes. One that was a linear gradient brush that was from Dark to light One was a radial brush that went from Dark to light. How could I merge the brushes so that when I apply them, I can apply both at once. EG Check this: 1) http://www.codeproject.com/KB/vista/WindowsVistaRenderer/VistaRenderer4.gif 2) http://www.codeproject.com/KB/vista/WindowsVistaRenderer/VistaRenderer5.gif How could I (In WPF/XAML) merge both into one gradient and then refer to that? (This is Mr.

问题 I need to replicate a circular (or angle) gradient from a Photoshop comp in WPF; so far I can only find linear and radial. Does anyone know if such a thing exists, or and easy way to get get a circular gradient in WPF? Note: I'm not asking about a radial gradient. A circular gradient is like taking a rectangle, applying a gradient and then transforming the rectangle into a circle. 回答1: Check this question for a new and a bit more complete answer to this question. 回答2: While I've never done

问题 I have XY data which I'd like to graph using a scatter plot , with R 's plotly package. set.seed(1) df <- data.frame(x=c(rnorm(30,1,1),rnorm(30,5,1),rnorm(30,9,1)), y=c(rnorm(30,1,1),rnorm(30,5,1),rnorm(30,9,1)), group=c(rep("A",30),rep("B",30),rep("C",30)),score=runif(90,0,1)) Each point is assigned to one of three groups ( df$group ) and has a score in the [0,1] range. I'm looking for a way to graph the data such that each group is colored with a different color but the shade of that color

问题 In tensorflow, if one has two tensors x and y and one want to have the gradients of y with respect to x using tf.gradients(y,x) . Then what one actually gets is : gradient[n,m] = sum_ij d y[i,j]/ d x[n,m] There is a sum over the indices of y, is there a way to avoid this implicit sum? To get the whole gradient tensor gradient[i,j,n,m] ? 回答1: Here is my work around just taking the derivative of each component (as also mentionned by @Yaroslav) and then packing them all together again in the

问题 I was persuaded some time ago to drop my comfortable matlab programming and start programming in Julia. I have been working for a long with neural networks and I thought that, now with Julia, I could get things done faster by parallelising the calculation of the gradient. The gradient need not be calculated on the entire dataset in one go; instead one can split the calculation. For instance, by splitting the dataset in parts, we can calculate a partial gradient on each part. The total

问题 I am trying to create a gradient drawable to depict a ratio of something. As a general example, lets say you were looking at a listview containing a fleet of cars. The background could be a fuel gauge - I don't want a smooth, wide transition. I want a very tight transition, and I want to be able to set where that transition takes place. Here's what I'm staring with, but I'm not getting very far. <?xml version="1.0" encoding="utf-8"?> <shape xmlns:android="http://schemas.android.com/apk/res

问题 I'm trying to do a gradient on a button but I can't make it have the same gradient as the other part of the button. I tried adding a gradient inside a gradient but it doesn't seems to work and can't find a solution for it. This the code I'm using: button{ color: white; padding: 3px 3px 3px 0px; border: 0px; font-size: 20px; width: 200px; text-align: right; background: linear-gradient(50deg , transparent 50%, rgb(149, 151, 155) 0%) left no-repeat, linear-gradient(rgb(200, 205, 212), rgb(149,

问题 it should look like http://img190.imageshack.us/img190/1686/textgradient.jpg the tricky part is, it should work for opera, canvas..? also important: the transparency is only needed for the big texts in the screenshot. the text is simple html text in a span tag. the background is a somewhat transparent png, defined as css background-image of the container div. i'd have no problems with using canvas or something like that for displaying the text. 回答1: If only Cufón supported a horizontal linear