globalevent | 易学教程

Spark rdd write in global list

阅读更多关于 Spark rdd write in global list

问题 How to write in global list with rdd? Li = [] Fn(list): If list.value == 4: Li.append(1) rdd.mapValues(lambda x:fn(x)) When I try to print Li the result is: [] What I'm trying to do is to transform another global liste Li1 while transforming the rdd object. However, when I do this I have always an empty list in the end. Li1 is never transformed. 回答1: The reason why you get Li value set to [] after executing mapValue s - is because Spark serializes Fn function (and all global variables that it

Monitor for all validation events

阅读更多关于 Monitor for all validation events

问题 It's quite easy to check if certain container or its children have validation errors. This can be used to disable Save button. I can use timer public SomeUserControl() { InitializeComponent(); var timer = new DispatcherTimer { Interval = TimeSpan.FromMilliseconds(100), IsEnabled = true }; Loaded += (s, e) => buttonSave.IsEnabled = IsValid(grid); Unloaded += (s, e) => timer.Stop(); } to poll and to disable button.  <Grid x:Name=

Spark rdd write in global list

阅读更多关于 Spark rdd write in global list

How to write in global list with rdd? Li = [] Fn(list): If list.value == 4: Li.append(1) rdd.mapValues(lambda x:fn(x)) When I try to print Li the result is: [] What I'm trying to do is to transform another global liste Li1 while transforming the rdd object. However, when I do this I have always an empty list in the end. Li1 is never transformed. vvladymyrov The reason why you get Li value set to [] after executing mapValue s - is because Spark serializes Fn function (and all global variables that it references - it is called closure) and sends to an another machine - worker. But there is no