generator

Using flow_from_dataframe what is the correct “value” for y_col

旧时模样 提交于 2020-08-24 11:17:00
问题 I am reading in a csv file with pandas, and give the column names stored in colname colnames=['file', 'label'] # Read data from file data = pd.read_csv('./Hand_Annotations_2.csv',names=colnames, header=None) # Preview the first 5 lines of the loaded data data.head() Then, I use ImageDataGenerator() and flow_fromdataframe() to get batches of data train_generator=datagen.flow_from_dataframe(dataframe=data, directory=None, x_col=colnames[0], y_col=colnames[1], class_indices=IDmap, class_mode=

multiprocessing Pool and generators

Deadly 提交于 2020-08-03 07:07:06
问题 First look at the following code: pool = multiprocessing.Pool(processes=N) batch = [] for item in generator(): batch.append(item) if len(batch) == 10: pool.apply_async(my_fun, args=(batch,)) batch = [] # leftovers pool.apply_async(my_fun, args=(batch,)) Essentially I'm retrieving data from a generator, collecting in into a list and then spawning a process that consumes the batch of data. This may look fine but when the consumers (aka the pool processes) are slower than the producer (aka the

How to write Python generator function that never yields anything

不问归期 提交于 2020-07-17 09:29:35
问题 I want to write a Python generator function that never actually yields anything. Basically it's a "do-nothing" drop-in that can be used by other code which expects to call a generator (but doesn't always need results from it). So far I have this: def empty_generator(): # ... do some stuff, but don't yield anything if False: yield Now, this works OK, but I'm wondering if there's a more expressive way to say the same thing, that is, declare a function to be a generator even if it never yields

How to write Python generator function that never yields anything

老子叫甜甜 提交于 2020-07-17 09:29:06
问题 I want to write a Python generator function that never actually yields anything. Basically it's a "do-nothing" drop-in that can be used by other code which expects to call a generator (but doesn't always need results from it). So far I have this: def empty_generator(): # ... do some stuff, but don't yield anything if False: yield Now, this works OK, but I'm wondering if there's a more expressive way to say the same thing, that is, declare a function to be a generator even if it never yields

how to write a generator for keras model for predict_generator

耗尽温柔 提交于 2020-06-29 06:49:24
问题 I have a trained keras model, and I am trying to run predictions with CPU only. I want this to be as quick as possible, so I thought I would use predict_generator with multiple workers. All of the data for my prediction tensor are loaded into memory beforehand. Just for reference, array is a list of tensors, with the first tensor having shape [nsamples, x, y, nchannels]. I made a thread-safe generator following the instructions here (I followed this when using fit_generator as well). class

how to write a generator for keras model for predict_generator

空扰寡人 提交于 2020-06-29 06:49:23
问题 I have a trained keras model, and I am trying to run predictions with CPU only. I want this to be as quick as possible, so I thought I would use predict_generator with multiple workers. All of the data for my prediction tensor are loaded into memory beforehand. Just for reference, array is a list of tensors, with the first tensor having shape [nsamples, x, y, nchannels]. I made a thread-safe generator following the instructions here (I followed this when using fit_generator as well). class

What's wrong with my use of generator expression?

两盒软妹~` 提交于 2020-06-29 04:17:39
问题 I have the following code, in which I try to convert a string representation of ranges to a list of numbers. For example, if the input is '0-0,3-5,7-10' the expected output is [0,3,4,5,7,8,9,10] . However, I got an error at: for l,h in r.split('-') which it says not enough values to unpack. My reasoning is that, r should have the form 'x-y' , so if I split it by '-' , I should get two values back. What's wrong with that? def parse_ranges(ranges): """Return a list of numbers corresponding to

What's wrong with my use of generator expression?

别来无恙 提交于 2020-06-29 04:17:38
问题 I have the following code, in which I try to convert a string representation of ranges to a list of numbers. For example, if the input is '0-0,3-5,7-10' the expected output is [0,3,4,5,7,8,9,10] . However, I got an error at: for l,h in r.split('-') which it says not enough values to unpack. My reasoning is that, r should have the form 'x-y' , so if I split it by '-' , I should get two values back. What's wrong with that? def parse_ranges(ranges): """Return a list of numbers corresponding to

What happens when you invoke a function that contains yield?

狂风中的少年 提交于 2020-06-28 09:51:07
问题 I read here the following example: >>> def double_inputs(): ... while True: # Line 1 ... x = yield # Line 2 ... yield x * 2 # Line 3 ... >>> gen = double_inputs() >>> next(gen) # Run up to the first yield >>> gen.send(10) # goes into 'x' variable If I understand the above correctly, it seems to imply that Python actually waits until next(gen) to "run up to" to Line 2 in the body of the function. Put another way, the interpreter would not start executing the body of the function until we call

How do yield-based coroutines in Python differ from coroutines with @asyncio.coroutine and @types.coroutine decorators?

梦想的初衷 提交于 2020-06-28 01:51:53
问题 I have been trying to understand asynchronous programming, particularly in Python. I understand that asyncio is built off of an event loop which schedules the execution of coroutines, but I have read about several different ways to define coroutines, and I am confused how they all relate to each other. I read this article for more background information on the topic. Although it covers each of the four types of coroutines I have mentioned, it does not entirely describe how they differ.