generator

问题 When running CMake on one PC, CMake generates NMake files by default. On another, it generates a Visual Studio project. I know I can override the default by adding -G "NMake Makefiles" to the end of my CMake statement, but I want to know why it defaults to Visual Studio projects on one and NMake files on another. 回答1: The following is from the CMake Source (version 2.8.4: cmake.cxx: starting line 2039): // Try to find the newest VS installed on the computer and // use that as a default if -G

问题 Might sound like a simple question, but I'm stumped. I've created a gem that essentially contains a generator. It contains the following structure: lib - generators - my_generator my_generator_generator.rb (see below) - templates my_template_files... - my_generator.rb (empty file) test -test files GemFile etc.. However when I add this Gem to my gem file and run rails g, it's not listed. Is there any additional config that I need to do? My generator roughly looks like this... class

问题 I built a simple generator that yields a tuple(inputs, targets) with only single items in the inputs and targets lists. Basically, it is crawling the data set, one sample item at a time. I pass this generator into: model.fit_generator(my_generator(), nb_epoch=10, samples_per_epoch=1, max_q_size=1 # defaults to 10 ) I get that: nb_epoch is the number of times the training batch will be run samples_per_epoch is the number of samples trained with per epoch But what is max_q_size for and why

问题 I was at a node.js meetup today, and someone I met there said that node.js has es6 generators. He said that this is a huge improvement over callback style programming, and would change the node landscape. Iirc, he said something about call stack and exceptions. I looked them up, but haven't really found any resource that explains them in a beginner-friendly way. What's a high-level overview of generators, and how are the different (or better?) than callbacks? PS: It'd be really helpful if you

问题 [ Note: I read Python-style generators in Go, this is not a duplicate of it. ] In Python / Ruby / JavaScript / ECMAScript 6, generator functions could be written using the yield keyword provided by the language. In Go, it could be simulated using a goroutine and a channel. The Code The following code shows how a permutation function (abcd, abdc, acbd, acdb, ..., dcba) could be implemented: // $src/lib/lib.go package lib // private, starts with lowercase "p" func permutateWithChannel(channel

问题 I'm trying to make a bingo game for fun. I've looked in a lot of places for a unique generator but I can't seem to find one. I've tried to make my own,but once it actually hits a number that's the same it does an infinite loop. I've tried a simple code that in theory should work but for some reason things pass through. What can I do!? var bc = []; for (var i = 0; i < 5; i++) { var r = Math.floor(Math.random()*20+1) + 0; if(!(r in bc)){ bc.push(r); } else { i--; } } ___________________________

问题 I tied to simplify the task as much as possible, so I could apply it to my algorithm. And here is the challenge for mathematicians and programmers: I need to create a method where I pass parameter int n: public void optionality_generator(int n){ //some kind of loops, or recursions...to make it workable System.out.println("current combination: ..."); } The output should show all possible combinations of true's and false's. Here is examples where N=1; N=2; N=3; N=4; N=5 where x=false and 0=true

问题 I'm using a generator function, say: def foo(): i=0 while (i<10): i+=1 yield i Now, I would like the option to copy the generator after any number of iterations, so that the new copy will retain the internal state (will have the same 'i' in the example) but will now be independent from the original (i.e. iterating over the copy should not change the original). I've tried using copy.deepcopy but I get the error: "TypeError: object.__new__(generator) is not safe, use generator.__new__()"

问题 I have implemented a generator-based scanner in Python that tokenizes a string into tuples of the form (token type, token value) : for token in scan("a(b)"): print token would print ("literal", "a") ("l_paren", "(") ... The next task implies parsing the token stream and for that, I need be able to look one item ahead from the current one without moving the pointer ahead as well. The fact that iterators and generators do not provide the complete sequence of items at once but each item as

问题 I know that yield turns a function into a generator, but what is the return value of the yield expression itself? For example: def whizbang(): for i in range(10): x = yield i What is the value of variable x as this function executes? I've read the Python documentation: http://docs.python.org/reference/simple_stmts.html#grammar-token-yield_stmt and there seems to be no mention of the value of the yield expression itself. 回答1: You can also send values to generators. If no value is sent then x